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a² = 15²+12²-2*12*15cos120
a = 23.43074902772 cm.
Where a is the side length of the equilateral triangle ABC.
(23.43074902772/sin120) = (12/sinb)
b = 26.32950349168°
c = 60-b
c = 33.67...
Sir Mike Ambrose is the author of the question.
Let the side length of triangle ABC be 1 unit.
a = 120-78
a = 42°
b = 60-42
b = 18°
(1/sin42) = (c/sin18)
c = 0.4618186516 unit.
tan6...
a² = 12²+6²
a = 6√(5) cm.
a = AE.
b = atan(1/2)°
b = angle DAE.
c = 180-atan(2)
c = 116.56505117708°
c = angle AFC.
d = 180-116.56505117708-atan(1/2)
d = 36.86989764584°
(6/sin36....
Le the side of the pentagram be 1 unit.
tan54 = a/0.5
a = 0.68819096024 unit.
cos54 = 0.5/b
b = 0.85065080835 unit.
c = b+a
c = 1.53884176859 units.
Let the side length of the ascrib...
