By OnlineEdumath   |  21st February, 2026
Sir Mike Ambrose is the author of the question.Let the side of the regular pentagon be 1 unit.a = 360-2(108)-90a = 54°tan72 = b/0.5b = 1.53884176859 units.tan54 = 1.53884176859/cc = 1.11803398875 uni...
By OnlineEdumath   |  20th February, 2026
Sir Mike Ambrose is the author of the question.Let the side of the square be 2 units.Therefore;a = 3√(5)/5 units.b = 2√(5)/5 units.c = √(5)/5 units.d = 2√(5)/5 unitsIt implies;a² = b² + c² + d² is;(3...
By OnlineEdumath   |  19th February, 2026
Sir Mike Ambrose is the author of the question.Area yellow in square units to 2 decimal places is;Area triangle with height (tan70+tan(450/7)) units and base (tan70+tan54)sin80 units.= ½(tan70+tan(45...
By OnlineEdumath   |  18th February, 2026
Sir Mike Ambrose is the author of the question.At x = 0, y = 2.At y = 16, x = 1.Gradient of the curve at x = 1 or at the tangent is;dy/dx = 3In2*2^(3x+1)For x = 1dy/dx = 48In2Therefore coordinate Q i...
By OnlineEdumath   |  17th February, 2026
Calculating Area Pink.a*b = 4*(4+1)ab = 20a = 20/b units.c = a+bc = (20/b)+bc = (b²+20)/b units.c is the diameter of the ascribed pink circle.d = ½(c)d = (b²+20)/(2b) units.d is the radius of the pin...
By OnlineEdumath   |  16th February, 2026
Calculating Area Red.a = 1+(161/9)+(10/9)a= 1+(171/9)a = 1+19a = 20 units.a is the diameter of the ascribed circle.b = ½(a)b = 10 units.b is the radius of the ascribed circle.Let x be the radius of t...
By OnlineEdumath   |  16th February, 2026
Calculating Area of the yellow Hexagon.Let x be the side length of the hexagon.a²+3² = x²a = √(x²-9) cm.b² = 2x²-2x²cos120b = √(3x²)b = √(3)x cm.It implies;Calculating x.sinc = √(x²-9)/x --- (1).sinc...
By OnlineEdumath   |  16th February, 2026
Calculating Area Red.a² = 6²+8²a = √(100)a = 10 cm.a is the side length of the square.6b+8b+10b = 8*624b = 48b = 2 cm.b is the radius of the inscribed circle.tanc = 6/8c = atan(3/4)°cosc = 2/dd = 2/c...
By OnlineEdumath   |  16th February, 2026
Sir Mike Ambrose is the author of the question.Let the side length of the square be 1 unit.Therefore;Area square is;1² = 1 square units.It implies;Area R is;Area square - Area equilateral triangle wi...
By OnlineEdumath   |  7th February, 2026
Sir Mike Ambrose is the author of the question.Let the side length of the be 2 units.Therefore;BC = 2 units.It implies;Area orange is;½(1*2) = 1 square units.Area green is;½(1*2) + ½(2/√(5))(4/√(5))=...
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