OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

Our Updates

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
By OnlineEdumath   |  21st November, 2024
Let the height of the yellow area trapezoid be a. Calculating a. tan72 = a/b b = (a/tan72) cm. c = 2b c = (2a/tan72) cm. d = 8+c d = (8+(2a/tan72)) cm. It implies; ½*a(8+(8+(2...
By OnlineEdumath   |  21st November, 2024
Sir Mike Ambrose is the author of the question. Let AB be 2 unit. Therefore CD = 1 unit. It implies; Area Blue is; Area triangle with height 0.72111025509 unit and base sin(atan(3/2)) un...
By OnlineEdumath   |  20th November, 2024
Sir Mike Ambrose is the author of the question. Area brown exactly in square unit decimal is; Area brown exactly in square unit decimal is; Area triangle with height 2 unit and base (1.93220...
By OnlineEdumath   |  20th November, 2024
Let the square side be x. x²+(x-4)² = a² a = √(2x²-8x+16) b² = 2²+(x-2)² b = √(x²-4x+8) It implies; (½(a))²+6² = b² ½(x²-4x+8)+36 = (x²-4x+8) x²-4x+8+72 = 2x²-8x+16 x²-4x-64...
By OnlineEdumath   |  19th November, 2024
Hexagon Area = 1 square units. Calculating the regular hexagon side length. Let it be a. (6a²)/(4tan30) = 1 3a² = 2/√(3) a² = ⅑(2√(3)) a = ⅓(√(2√(3))) unit. a = 0.6204032394 units....
By OnlineEdumath   |  19th November, 2024
Area blue is; Quarter the area of the square. = ¼(10)² = ¼(100) = 25 cm²
By OnlineEdumath   |  18th November, 2024
Let the side of the two congruent sides be a units. The small green square side will be; ⅔(a) units. The big green square side is; 2a - ⅔(a) = ⅓(4a) units. b = a-⅔(a) b = ⅓(a) unit...
By OnlineEdumath   |  18th November, 2024
Sir Mike Ambrose is the author of the question. Shaded area exactly in cm² is; Area triangle with height 84 cm and base 13 cm - Area triangle with height 10 cm and base 24 cm + Area triangle wi...
By OnlineEdumath   |  17th November, 2024
Radius of the circle, r is; r² = (8+(3/2))²+4² r² = (19/2)²+16 r² = ¼(425) r = ½(5√(17)) cm Therefore; Area shaded, exactly in cm² decimal is; Area sector with radius ½(5√(17)) cm an...
By OnlineEdumath   |  17th November, 2024
Calculating r, radius of the circle. (r/tan40)+(r/tan30) = 10 r = 3.42020143326 cm. (a/sin60) = (10/sin40) a = 13.47296355334 cm. tan40 = 3.42020143326/b b = 4.07603734548  (4.076037...
By OnlineEdumath   |  16th November, 2024
Sir Mike Ambrose is the author of the question. Let the small inscribed square side length be x. The big inscribed square side length will be 2x. Calculating x. ⅓(√(3)x+2√(3)x+3x+6x) = 18...
By OnlineEdumath   |  16th November, 2024
Notice; AB = 25 units. cos30 = 8√(3)/a a = 16 units. tan30 = b/(8√(3)) b = 8 units. Let the side of the regular hexagon be c. c = ¼(AC) Calculating AC. ((AC)/sin46) = (25/sin74...
By OnlineEdumath   |  15th November, 2024
Calculating green inscribed triangle area. a² = 2(3√(2))² a² = 2*18 a = √(36) a = 6 units. a is AB. b = ½(360-90) b = ½(270) b = 135° b is angle ABC. c² = 6²+(4√(2))²-2*6*4√(2)cos13...
By OnlineEdumath   |  15th November, 2024
Calculating the required angle, alpha. Let it be a. Let R = 2 units, radius of the ascribed semi circle. b = (2-r) units. It implies; Calculating r. (2-r)² = 2r² 2-r = √(2r²) 2-...
By OnlineEdumath   |  14th November, 2024
9^(x)+9*9^(x) = 270 Let 9^(x) be p. p+9p = 270 10p = 270 p = 27 And p = 9^(x) 9^(x) = 27 2x = 3 x = 3/2 x = 1.5
By OnlineEdumath   |  14th November, 2024
7² = 3²+8²-2*3*8cosa 48cosa = 9+64-49 a = acos((9+64-49)/48) a = 60° Calculating b, radius of the inscribed circle. 3b+8b+7xb = 3*8sin60 18b = 12√(3) 3b = 2√(3) b = ⅔√(3) units. b = 1....
By OnlineEdumath   |  13th November, 2024
Sir Mike Ambrose is the author of the question. Let the side of the regular pentagon be 1 unit. Therefore; Area purple is; Area trapezium with two parallel side 0.07294901687 units and 0....
By OnlineEdumath   |  13th November, 2024
Notice; Green regular hexagon's side is 8 cm. sin60 = a/8 a = 4√(3) cm Where a is the the height of the white triangle enclosed by the two green regular hexagon and the regular pentagon....
By OnlineEdumath   |  12th November, 2024
Radius of the circle, r is; √(2-2cos120) r = √(3) units. Therefore! Area yellow is; Area regular hexagon with side 2 units - 2(area triangle with height ½ units and base √(3) units) -...
By OnlineEdumath   |  12th November, 2024
Let the base of the triangle ascribing the green and yellow area b 1 unit. tan55 = a/1 a = 1.42814800674 units. tan55 = b/(1-b) b = 0.58816349035 units. Where b is the side of the white...
By OnlineEdumath   |  11th November, 2024
Sir Mike Ambrose is the author of the question. Notice; Square side is 4 units. Small regular hexagon side is 2 units. Big regular hexagon side is 4 units. Therefore; Area shaded, exa...
By OnlineEdumath   |  11th November, 2024
Let the regular octagon side be 2 units.   Area Octagon is; ½(8*2)*(2/(2tan(180/8))) = 8/(tan(180/8)) = 19.31370849898 square units. Calculating Area Red. a = ⅛(180*6) a = 135° Le...
By OnlineEdumath   |  10th November, 2024
a² = R²+6² a = √(R²+36) units. a is OB. b = a-4 b = (√(R²+36)-4) units. c = 6+4 c = 10 units. It implies; 10² = R²+(√(R²+36)-4)² 100 = R²+R²+36-8√(R²+36)+16 48 = 2R²-8√(R²+36) 8√...
By OnlineEdumath   |  10th November, 2024
Let the single side length of the two congruent inscribed regular pentagon be 1 unit. Area Green is; 0.5*5(1/(2tan(180/5))) = 1.72047740059 square units. Calculating Area Shaded. a = ⅕...
By OnlineEdumath   |  10th November, 2024
Let a be the big inscribed circle radius. Let b be the bigger inscribed circle radius. Let c be the biggest inscribed circle radius. It implies; a+b = 12 --- (1). a+c = 22 --- (2)....
By OnlineEdumath   |  9th November, 2024
(x⁶-1)/(x⁴-x) = 2 ((x³+1)(x³-1))/(x(x³-1)) = 2 (x³+1)/x = 2 x³-2x+1 = 0 For x = 1 x³-2x+1 = 0 Therefore; (x-1) is a factor of x³-2x+1 Calculating the other values of x. (x³-2x+1)/(...
By OnlineEdumath   |  9th November, 2024
Calculating the area of the red rectangle. Let a be the radius of the half circle. b = ½(a) units. Calculating a. a² = (½(a))²+1² a² = ¼(a²)+1 (3/4)a² = 1 a² = 4/3 a = √(4/3) a = ⅓...
By OnlineEdumath   |  8th November, 2024
Calculating red area. a = (1+x) units. a is the diameter of the circle. b = ½(a) b = ½(1+x) units. b is the radius of the circle. c = ½(1-x) units. Calculating x. (½(1+x))² = (½(1...
By OnlineEdumath   |  8th November, 2024
Calculating x, the side length of the ascribed square. tana = 14/7 a = atan(2)° b = 90+a b = (90+atan(2))° c² = 14²+7² c² = 196+49 c = √(245) units. c = 7√(5) units. d² = √(245)²+9...
By OnlineEdumath   |  7th November, 2024
a = 8+2 a = 10 units. a is OA, the radius of the half circle. b = 2a b = 20 units. b is AB, the diameter of the half circle. c = 2+a c = 12 units. c is BC. Notice. BC = BD = 12 un...
By OnlineEdumath   |  7th November, 2024
Calculating x. Let a be the radius of the ascribed quarter circle. b = 4+4 b = 8 units. Notice. BD = 4 units. OB = x+BD OB = (x+4) units. OB is the radius of the ascribed quarter...
By OnlineEdumath   |  6th November, 2024
Calculating Green Area. a = 2*4 a = 8 units. a is the radius of the ascribed quarter circle. b²+4² = 8² b² = 64-16 b = √(48) b = 4√(3) units. tanc = 4√(3)/4 c = atan(√(3))° c = 60°...
By OnlineEdumath   |  6th November, 2024
Inscribed semi circle radius is 4 cm. Inscribed quarter circle radius is 8 cm. tana = 4/8 a = atan(½)° b = 2a b = 2atan(½)° c = 180-b c = 2atan(2)° Blue Area is; Area sector wi...
By OnlineEdumath   |  5th November, 2024
2^(x+1)+2^(x-1) = 320 Let 2^(x) be p. It implies; 2p+½(p) = 320 ½(5p) = 320 5p = 640 p = 128 And  p = 2^(x) Calculating x. 2^(x) = 128 2^(x) = 2⁷ x = 7
By OnlineEdumath   |  5th November, 2024
Let b be 1 unit. a = 50° b = 40° a and b are the two interior complementary angles or acute angles of the small right-angled triangle with hypotenuse b. sin50 = c/b c = sin50 c = 0.766044...
By OnlineEdumath   |  4th November, 2024
Calculating angle x. Let 1 be the base of the ascribed isosceles triangle. a = 180-39-2(27) a = 141-54 a = 87° (1/sin87) = (b/sin(2*27)) b = 0.8101272456 units. c = 180-27-15-39 c =...
By OnlineEdumath   |  4th November, 2024
Let AB be a. b = (a-2) units. c = ½(a) units. c is BD. d = c-2 d = ½(a)-2 d = ½(a-4) units. It implies; 2 - (a-2) ½(a-4) - 2 Cross Multiply. 4 = ½(a-4)(a-2) 8 = a²-6a+8 a...
By OnlineEdumath   |  3rd November, 2024
Let 1 be the side length of the ascribed regular hexagon. a = ⅙*180(6-2) a = 120° a is the single interior angle of the ascribed regular hexagon. b² = 1²+1²-2*1*1cos120 b = 1.7320508076 un...
By OnlineEdumath   |  3rd November, 2024
Calculating Alpha. Let it be a. Let b be the radius of the ascribed quarter circle. c = (b-√(2)) units. d = (b-2√(2)) units. It implies, observing similar plane shape (right-angled)...
By OnlineEdumath   |  2nd November, 2024
Calculating angle x. Let AR be 1 unit. a = 180-24-15 a = 180-39 a = 141° a is angle ARK. (1/sin15) = (b/sin141) b = 2.4315072749 units. b is AK. c = 180-12-6 c = 180-18 c = 162°...
By OnlineEdumath   |  2nd November, 2024
Sir Mike Ambrose is the author of the question. Calculating the equation of the curve. y-b=a(x-4)² ----- (1) At coordinate (8, 0) -b=16a Therefore; a = -b/16 Sub. a in (1) to get...
By OnlineEdumath   |  1st November, 2024
Let the two equal lengths be 1 unit. (a) Calculating Theta exactly. Let theta be x. Calculating x. x = ½(90-54) x = ½(36) x = 18° sin18 = a/1 a = 0.30901699437 units. b = 90-18...
By OnlineEdumath   |  1st November, 2024
Let the side of the inscribed square be a. Calculating a. a+2√(a²-(a/2)²) = 10√(2) a+2√(3a²/4) = 10√(2) 2√(3a²/4) = 10√(2)-a 3a² = 200-20√(2)a+a² 2a²+20√(2)a-200 = 0 a²+10√(2)a-100 = 0...
By OnlineEdumath   |  31st October, 2024
Sir Mike Ambrose is the author of the question. Biggest square side is 14 units. Bigger square side is 8 units. a = atan(9/16) (9/16) = b/c c = (16b/9) units. (16b/9)+6 = 14 (16b/9)...

Our Media

media video Class with Tejiri (year 12) and Vwarhe (year 10)

Class with Tejiri (year 12) and Vwarhe (year 10)

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Introduction to Decimals

Introduction to Decimals

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

WhatsApp Google Map

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support