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OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

Welcome to Online Edumath

By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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We are smart and clever!

By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  17th October, 2024
a² = 1²+4² a = √(17) units. a is the diameter of the circle. r, radius of the circle is; ½(a) r = ½√(17) units.
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Mathematics Question and Solution

By OnlineEdumath   |  17th October, 2024
Notice! AB = BC Let AB = BC be a. b²+(0.5(8+10))² = a² b = √(a²-81) units. c = ½(10+8)-8 c = 1 unit. √(a²-81) - 1 9 - √(a²-81) Cross Multiply. a²-81 = 9 a² = 90 a = √(90)...
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Mathematics Question and Solution

By OnlineEdumath   |  17th October, 2024
Sir Mike Ambrose is the author of the question. AC = 12 cm. AB = 10 cm. Therefore Area red exactly in cm² is; Area triangle with two side (165/90) cm and √(61) cm, and angle atan(5/6)° =...
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Mathematics Question and Solution

By OnlineEdumath   |  16th October, 2024
Calculating blue area (area inscribed half circle). 15² = 13²+14²-2*13*14cosa 364cosa = 140 a = 67.380135052° (15/sin67.380135052) = (13/sinb) b = 53.1301023542° c = 180-a-b c = 59.489...
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Mathematics Question and Solution

By OnlineEdumath   |  16th October, 2024
a = ½(360-90) a = ½(270) a = 135° b² = 6²+(4√(2))²-2*6*4√(3)cos135 b = 2√(29) units. b = 10.7703296143 units. 2c² = b² 2c² = (2√(29))² 2c² = 4*29 c² = 58 c = √(58) units. c is the ra...
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Mathematics Question and Solution

By OnlineEdumath   |  16th October, 2024
Calculating Area Yellow. Let a be the radius of the ascribed semi circle. b²+6² = a² b = √(a²-36) units. b is the radius of the inscribed half circle. Therefore, area yellow is; ½(a²)...
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Mathematics Question and Solution

By OnlineEdumath   |  15th October, 2024
Let the side length of the regular hexagon be 1 unit. a = ⅙*180(6-2) a = 120°  a is the single interior angle of the regular hexagon. sin30 = b/1 b = ½ units. cos30 = c/1 c = ½√(3) uni...
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Mathematics Question and Solution

By OnlineEdumath   |  15th October, 2024
Sir Mike Ambrose is the author of the question. a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.410...
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Mathematics Question and Solution

By OnlineEdumath   |  15th October, 2024
Sir Mike Ambrose is the author of the question. a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.410...
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Mathematics Question and Solution

By OnlineEdumath   |  15th October, 2024
Let the side length of the regular hexagon be 1 unit. Therefore; a = 1 unit. Calculating b. Cos30=a/c And a = 1 c = 1/cos30 c = ⅔√(3) units. Where c is the hypotenuse of the r...
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Mathematics Question and Solution

By OnlineEdumath   |  15th October, 2024
Sir Mike Ambrose is the author of the question. Area Blue, in cm² to 1 d. p. is; Half area regular pentagon with side 12 cm - area triangle with height 6 cm and base 6tan24 cm - area triangle w...
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Mathematics Question and Solution

By OnlineEdumath   |  14th October, 2024
Calculating yellow area. a = ½(10) a = 5 km. a is the radius of the inscribed circle. tanb = 5/10 b = atan(½)° c = 180-2b c = (180-2atan(½))° d² = 2(5²)-2(5²)cos(180-2atan(½)) d =...
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Mathematics Question and Solution

By OnlineEdumath   |  14th October, 2024
Let a be the radius of the inscribed circle. Let b be the radius of the ascribed circle. It implies; πb²-πa² = 20π b²-a² = 20 b = √(20+a²) units. Again, b is the radius of the ascribed...
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Mathematics Question and Solution

By OnlineEdumath   |  14th October, 2024
Sir Mike Ambrose is the author of the question. Let the side length of the large square be x. Calculating x. 25=x²+64-(16xcos20) Therefore; x = 11.70244 cm. It implies; Area large sq...
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Mathematics Question and Solution

By OnlineEdumath   |  14th October, 2024
Sir Mike Ambrose is the author of the question. Let the side length of the regular pentagon be 2 units. a² = 2²-1² a = √(3) units. b² = 5-4cos108 b = 2.49721204096 units. (2.49721204096/...
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Mathematics Question and Solution

By OnlineEdumath   |  14th October, 2024
Calculating Area Red. tana = 5/10 a = atan(½)° b = 2a b = 2atan(½)° c = b-45 c = 8.1301023542° d² =10²+10²-2*10*10cos8.1301023542 d = 1.4177804018 units. e = ½(180-8.1301023542) e...
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Mathematics Question and Solution

By OnlineEdumath   |  13th October, 2024
Let EB be a. Let AE be b. It implies; a/b = √(2) --- (1). a+b = 1 --- (2). From (1). a = √(2)b --- (3). Substituting (3) in (2) to get b. √(2)b+b = 1 b(√(2)+1) = 1 b = (√...
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Mathematics Question and Solution

By OnlineEdumath   |  13th October, 2024
Let the radius of the circle be 2 units. a = (2-b) units. Calculating b. 2² = 2(2-b)² 4 = 2(4-4b+b²) b²-4b+2 = 0 (b-2)² = -2+(-2)² (b-2)² = 2 b = 2±√(2) It implies; b ≠ (2+√(2)) b...
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Mathematics Question and Solution

By OnlineEdumath   |  13th October, 2024
Let the regular pentagon side length be 1 unit. sin72 = a/1 a = 0.9510565163 unit. Let the side length of the two inscribed congruent squares be b. c = ½(b) unit. b+½(b) = 0.9510565163...
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Mathematics Question and Solution

By OnlineEdumath   |  12th October, 2024
Let a be the radius of the circle. b = 2a units. b is the diameter of the circle. Calculating a observing similar plane shape (right-angled triangle) ratios. It implies; 2a - 5 9 - a...
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Mathematics Question and Solution

By OnlineEdumath   |  12th October, 2024
Let the radius of the ascribed half circle be a. Let the radius of the inscribed half circle be b. It implies; a² = b²+(0.5*12)² a²-b² = 6² a²-b² = 36 square units. Where (a²-b²) is the b...
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Mathematics Question and Solution

By OnlineEdumath   |  12th October, 2024
Sir Mike Ambrose is the author of the question. Let the radius of the semi circle be 1 unit. Therefore; Area lilac is; Area triangle with height 0.26794919243 units and base 1 unit = ½(0....
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Mathematics Question and Solution

By OnlineEdumath   |  11th October, 2024
Let AB be 5 units. Radius, r of the inscribed circle is; 5*(2/5) r = 2 units. a = ⅛(180*6) a = 135° 2b² = 25 b = ½(5√(2)) units. c = 180-0.5(135)-45 c = 67.5° sin22.5 = ½(5√(2...
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Mathematics Question and Solution

By OnlineEdumath   |  11th October, 2024
Shaded inscribed area is; Area regular hexagon with side 1 unit - 6(Area sector with radius 1 unit and angle 60°) + 6(Area equilateral triangle with side 1 unit). = 6/(4tan(180÷6)) - 6(60π÷36...
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Mathematics Question and Solution

By OnlineEdumath   |  11th October, 2024
Sir Mike Ambrose is the author of the question. Let the single side length of the regular octagon be 2 units. Therefore;  Area green is; Area triangle with height and base √(2) units + Are...
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Mathematics Question and Solution

By OnlineEdumath   |  10th October, 2024
Sir Mike Ambrose is the author of the question. 18² = 14²+16²-2*14*16cosa 448cosa = 14²+16²-18² a = acos((14²+16²-18²)/448) a = 73.39845040098° (18/sin73.39845040098) = (14/sinb) b = 48.189...
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Mathematics Question and Solution

By OnlineEdumath   |  10th October, 2024
Green Area is; 2(area square with side 2 cm - area quarter circle with radius 2 cm) + 3(area sector with radius 1 unit and angle 300°) + 4(area equilateral triangle with side 1 unit) = 2(4 -...
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Mathematics Question and Solution

By OnlineEdumath   |  10th October, 2024
Sir Mike Ambrose is the author of the question. a = 6-2 a = 4 units. b² = 6²-4² b = 2√(5) units. c = 6-b c = (6-2√(5)) units. d = asin(⅔)° tan(asin⅔) = e/(6-2√(5)) e = ⅕(12√(5)-20)...
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Mathematics Question and Solution

By OnlineEdumath   |  9th October, 2024
½(xy)=24 xy = 48 ------ (1) x²+y²=10² ------- (2) And; x²+y²=(x+y)²-2xy Therefore; (x+y)²-2xy=100 And; xy = 48 (x+y)²-2(48)=100 (x+y)²=196 x+y=14 ----- (3) x = 14-y --...
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Mathematics Question and Solution

By OnlineEdumath   |  9th October, 2024
Let the radius, r of the circle be 7 units. Therefore perimeter of the circle is; 2πr = 44 units. Calculating the length of the square. 14² = (14-2x)²+(14-4x)² 196 = 196-56x+4x²+196-1...
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Mathematics Question and Solution

By OnlineEdumath   |  9th October, 2024
Let r be the radius of the semi circle. Therefore; A right-angled triangle with hypotenuse 6 units, and adjacent height and base, (r-7) units and √(r²-49) units respectively is derived. It...
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Mathematics Question and Solution

By OnlineEdumath   |  8th October, 2024
Let the side length of the regular pentagon be 1 unit. tan36 = a/0.5 a = 0.363271264 units. b² = 0.363271264²+0.5² b = 0.61803398875 units. tan72 = c/0.5 c = 1.53884176859 units. Are...
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Mathematics Question and Solution

By OnlineEdumath   |  8th October, 2024
Let r be the radius of the circle. (6√(2))²=r²+(6+r)² 72=r²+36+12r+r² 2r²+12r-36=0 r²+6r-18=0 (r+3)²=18+9 r = -3±3√(3) Therefore; r ≠ - 3 - 3√(3) r = (3√(3)-3) units. Therefore;...
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Mathematics Question and Solution

By OnlineEdumath   |  8th October, 2024
Let the two equal lengths be 1 unit each. a² = 2(1²) a = √(2) units. b = 180-60-45 b = 75° (√(2)/sin45) = (c/sin75) c = 1.9318516526 units. d = c-a d = 0.5176380902 units. e = 18...
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Mathematics Question and Solution

By OnlineEdumath   |  8th October, 2024
Sir Mike Ambrose is the author of the question. Please, move the above question left/right one time to review the solution. Thank you. Let the side length of the inscribed square be 1 unit....
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Mathematics Question and Solution

By OnlineEdumath   |  7th October, 2024
Sir Mike Ambrose is the author of the question. Calculating Area Purple. Let the side length of the square be x. Calculating x. 2(one-sixth x²) = Area Orange 2(1/6)x² = 96 x² = 288 x = 1...
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Mathematics Question and Solution

By OnlineEdumath   |  7th October, 2024
(0.5*(8+3)(8+4)sina)-(0.5*3*8sina) = 36 Calculating angle a. 66sina-12sina = 36 11sina-2sina = 6 9sina = 6 sina = 2/3 a = asin(2/3) a = 41.8103148958° Therefore, the required area is;...
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Mathematics Question and Solution

By OnlineEdumath   |  7th October, 2024
Let the side length of the ascribed regular pentagon be 2 units. a = ⅕*180(5-2) a = 108° a is the single interior angle of the ascribed regular pentagon. b² = 2²+1²-2*1*2cos108 b = 2.49721...
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Mathematics Question and Solution

By OnlineEdumath   |  7th October, 2024
R is; R² = 2(R-2)² R² = 2(R²-4R+4) R² = 2R²-8R+8 R²-8R+8 = 0 (R-4)² = -8+16 (R-4)² = 8 R = 4±2√(2) Therefore; R ≠ 4-2√(2) cm. R = 4+2√(2) cm.
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Mathematics Question and Solution

By OnlineEdumath   |  7th October, 2024
a² = 11*11+10*10-2*11*10cos50 a = 8.92113926968 cm. (8.92113926968/sin50) = (10/sinb) b = 59.16920318624° c = 180-50-59.16920318624 c = 70.83079681376°  d = 0.5a d = 4.46056963484 cm....
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Mathematics Question and Solution

By OnlineEdumath   |  6th October, 2024
Calculating the area of the ascribed right-angled triangle. a = (y+2) units. a is the adjacent base of the right-angled triangle. b = (z+2) units. b is the adjacent height of the right-angle...
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Mathematics Question and Solution

By OnlineEdumath   |  6th October, 2024
Radius of the quarter circle is (2+3) = 5 units. Let a be the side length of the inscribed square. b²+3² = a² b = √(a²-9) units. c = 3+b c = (3+√(a²-9)) units. Calculating a. (3+√(...
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Mathematics Question and Solution

By OnlineEdumath   |  6th October, 2024
tana = 3/4 a = atan(3/4) b² = 3²+4² b = 5 units. cos(atan(3/4)) = 1/c c = 1.25 units. c = (5/4) units. sin(atan(3/4)) = 1/d d = 1.6666666667 units. d = (5/3) units. e = b-c-d e =...
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Mathematics Question and Solution

By OnlineEdumath   |  6th October, 2024
Calculating angle x. Let BC be 2 units. a = 180-70-40 a = 70° a is angle ACB. cos70 = 1/b b = 2.9238044002 units. b is AB. c = 180-80-50 c = 50° c is angle ADC. d = ½(b) d = 1...
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Mathematics Question and Solution

By OnlineEdumath   |  6th October, 2024
Sir Mike Ambrose is the author of the question. Let the side length of the regular hexagon be 1 unit. Therefore; Area green is; Area regular hexagon with side 1 unit + Area regular pentag...
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Class with Tejiri (year 12) and Vwarhe (year 10)

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Introduction to Decimals

Introduction to Decimals

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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