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OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

We are smart and clever!

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
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Welcome to Online Edumath

By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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We are smart and clever!

By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  26th March, 2025
Let the side of the regular pentagon be 1 unit. a² = 2-2cos108 a = 1.61803398875 units. sin30 = b/0.5 b = 0.25 unit. c = 2b c = 0.5 unit. Where c is the inscribed square side. Are...
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Mathematics Question and Solution

By OnlineEdumath   |  25th March, 2025
a = asin(1/3)° a = 19.47122063449°  a = angle ABF. Let the centre of the diameter of the half circle be O. Angle AOF = 90-19.47122063449 = 70.52877936551° (OC)² = 12²+18² OC = 6√(13) c...
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Mathematics Question and Solution

By OnlineEdumath   |  24th March, 2025
Let the side of the regular pentagon be 1 unit. Notice; The regular pentagon side is equal the regular heptagon side. a = ⅐(180*5) a = ⅐(900)°, the single interior angle of the regular he...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd March, 2025
a = 360-140-80 a = 140° cos20 = 1/b b = 1.06417777248 units. (1.06417777248/sin30) = (c/sin70) c = 2 units. d² = 4+1.064177772482²-4*1.06417777248cos140 d = 2.89711998506 units. (2...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd March, 2025
Let the side of the regular pentagon be 1 unit. a = 360-2(108)-90 a = 54° tan72 = b/0.5 b = 1.53884176859 units. tan54 = 1.53884176859/c c = 1.11803398875 units. d = c-0.5 d = 0.618...
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Mathematics Question and Solution

By OnlineEdumath   |  21st March, 2025
Notice; The diameter of the semicircle is 8 units. Therefore radius is 4 units. tan30 = a/2 a = ⅔(√(3)) units. b = 3a b = 2√(3) units. c² = 2²+(⅔(√(3)))² c = (4/√(3)) units. d...
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Mathematics Question and Solution

By OnlineEdumath   |  20th March, 2025
Let the side of the regular hexagon which is equal the side of the square be 1 unit. a = ½(180-108) a = 36° tan36 = b/0.5 b = 0.363271264 unit. Area Blue is; 0.5*0.363271264*0.5 =...
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Mathematics Questions and Solution

By OnlineEdumath   |  19th March, 2025
Sir Mike Ambrose is the author of the question. Let the side of the inscribed square be 2 units. Therefore; Area S is; Area triangle with two side 1.03528 units and 0.53589838486 units, and angl...
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Mathematics Question and Solution

By OnlineEdumath   |  18th March, 2025
Sir Mike Ambrose is the author of the question. P coordinate is; P(3, 9) Q coordinate is; Q(2, 5), Q(3, 5) It implies; Shaded area exactly in its square units simplest form is; (...
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Mathematics Question and Solution

By OnlineEdumath   |  17th March, 2025
Sir Mike Ambrose is the author of the question. Calculating the circle's radius, r. 21r + 15r + 12√(2)r = 21*12√(2)sin45 (36+12√(2))r = 252 r = 252/(36+12√(2)) cm r = 3(3-√(2)) cm I...
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Mathematics Question and Solution

By OnlineEdumath   |  16th March, 2025
Sir Mike Ambrose is the author of the question. Let the radius of the ascribed semicircle be 2 units. Therefore; Radius of the inscribed circle is 1 unit. It implies; Area R is; Are...
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Mathematics Question and Solution

By OnlineEdumath   |  15th March, 2025
Let a be the side of the square. cos30 = b/8 b = 4√(3) cm. sin30 = c/8 c = 4 cm. a = b+12 a = (12+4√(3)) cm. Area Square is; a² = (12+4√(3))² = 358.27687752661 cm²  d² = 12²+4²...
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Mathematics Question and Solution

By OnlineEdumath   |  14th March, 2025
Let the single side length of the two congruent inscribed regular pentagon be 1 unit. Area Green is; 0.5*5(1/(2tan(180/5))) = 1.72047740059 square units. Calculating Area Shaded. a =...
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Mathematics Question and Solution

By OnlineEdumath   |  13th March, 2025
Sir Mike Ambrose is the author of the question. Area Orange exactly in square cm decimal is; Area triangle with height 1.64419338427 cm and base (4.95325421888sin129.5411167921) cm = ½*1.644...
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Mathematics Question and Solution

By OnlineEdumath   |  12th March, 2025
a = atan(3/2)° b = atan(2/3)° b = Angle BEG. tan(atan(2/3)) = c/2 ⅔ = c/2 c = (4/3) cm. c = BG. OG = 2-(4/3) OG = ⅔ cm. Notice; Radius of the circle is 2 cm. Angle OGH = 180-...
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Mathematics Question and Solution

By OnlineEdumath   |  11th March, 2025
Sir Mike Ambrose is the author of the question  Let the side of the regular Pentagon be 2 units. Therefore; Area orange is; Area triangle with height 1.7013016167 units and base 1.8345763...
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Mathematics Question and Solution

By OnlineEdumath   |  10th March, 2025
a² = 2*12²-2*12²cos120 a = 12√(3) cm. a = 20.78460969083 cm. a = AB. b = 2a b = 24√(3) cm. b = 41.56921938165 cm. b = AC. c² = 12²+41.56921938165²-24*41.56921938165cos30 c = 31.7490157...
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Mathematics Question and Solution

By OnlineEdumath   |  9th March, 2025
a² =2*12² a = 12√(2) cm. a = AC. 12b+12b+12√(2)b = 12*12 b = 144/(24+12√(2)) b = 12-6√(2) cm. b = 3.51471862576 cm. b = radius of the inscribed circle. BF = ½(12√(2)) BF = 6√(2) cm....
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Mathematics Question and Solution

By OnlineEdumath   |  8th March, 2025
a² = 15²+12²-2*12*15cos120 a = 23.43074902772 cm. Where a is the side length of the equilateral triangle ABC. (23.43074902772/sin120) = (12/sinb) b = 26.32950349168° c = 60-b c = 33.67049...
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Mathematics Question and Solution

By OnlineEdumath   |  7th March, 2025
Sir Mike Ambrose is the author of the question. Area Green exactly is;  Area trapezoid with parallel sides 3 cm and (6-2√(3)) cm, and height (6-3√(3)) cm. = ½(6-3√(3))(3+(6-2√(3))) = ½(6-...
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Mathematics Question and Solution

By OnlineEdumath   |  6th March, 2025
a² = 12²-6² a = 6√(3) cm. a = 10.39230484541 cm. a = circle's radius = AD = AG. b² = 2*10.39230484541²-2*10.39230484541²cos120 b = 18 cm. b = DG. c = 12-10.39230484541 c = 1.60769515459...
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Mathematics Question and Solution

By OnlineEdumath   |  5th March, 2025
Let AB be 5 units. Radius, r of the inscribed circle is; 5*(2/5) r = 2 units. a = ⅛(180*6) a = 135° 2b² = 25 b = ½(5√(2)) units. c = 180-0.5(135)-45 c = 67.5° sin22.5 = ½(5√...
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Mathematics Question and Solution

By OnlineEdumath   |  4th March, 2025
AB = BC = AC = 6 cm. cos60 = 2/BE BE = 4 cm. (DE)² = 4²-2² DE = 2√(3) cm. (CE)² = (2√(3))²+4² CE = 12+16 CE = 2√(7) cm EF = (2√(7)-4) cm. EF = 1.29150262213 cm. AE = 6-4 AE = 2...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd March, 2025
a = ½(180-150) a = 15° b = 90-15 b = 75° (c/sin45) = (12/sin60) c = 9.79795897113 cm. (12/sin60) = (d/sin45) d = 9.79795897113 cm. e² = 9.79795897113²+12²-24*9.79795897113cos135 ...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd March, 2025
The radius of the circle is 6 cm. a = atan(2)° Where a is angle AOB = angle COE. Angle BOE = 180-atan(2) = 116.56505117708° Angle OBE = ½(180-116.56505117708) = 31.71747441146° b =...
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Mathematics Question and Solution

By OnlineEdumath   |  1st March, 2025
Let GD (inscribed square side) be a. Calculating a. 2(a/(tan60))+a = 12 a = 12/((2/√(3))+1) a = 5.56921938165 cm. b = ½(12-5.56921938165) b = 3.21539030918 cm. Where b is BD = CE. c = 3.21539030...
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Mathematics Question and Solution

By OnlineEdumath   |  28th February, 2025
a² = 12²-6² a = 6√(3) cm. Where a is BD. b = ½(a) b = 3√(3) cm. Where b is BG = DG. c = atan(6/(3√(3)) c = 49.10660535087° Where c is angle AGD = angle BGE. d = 60-49.10660535087 d...
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Mathematics Question and Solution

By OnlineEdumath   |  27th February, 2025
Let a be the radius of the inscribed circle. Calculating a. tan30 = a/6 a = 2√(3) cm. b = inscribed circle diameter. b = 4√(3) cm. 12² = c²+6² c = 144-36 c = √(108) c = 6√(3) cm. d = 6√(3)-4√(3)...
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Mathematics Question and Solution

By OnlineEdumath   |  26th February, 2025
18² = 14²+16²-2*14*16cosa 448cosa = 14²+16²-18² a = acos((14²+16²-18²)/448) a = 73.39845040098° (18/sin73.39845040098) = (14/sinb) b = 48.18968510422° c = 180-48.18968510422-73.39845040098 c = 58....
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Mathematics Question and Solution

By OnlineEdumath   |  25th February, 2025
a² = 11*11+10*10-2*11*10cos50 a = 8.92113926968 cm. (8.92113926968/sin50) = (10/sinb) b = 59.16920318624° c = 180-50-59.16920318624 c = 70.83079681376°  d = 0.5a d = 4.46056963484 cm. e² = 4.460...
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Mathematics Question and Solution

By OnlineEdumath   |  24th February, 2025
Sir Mike Ambrose is the author of the question. Radius of the semicircle is 2 units. Therefore; Shaded area exactly in decimal square units is; Area trapezoid with parallel sides 2 units...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd February, 2025
Radius, r1 of the inscribed semicircle is; sin60 = r1/6 r1 = 3√(3) cm. Radius, r2 of the inscribed circle is; tan60 = 3/r2 r2 = 3/√(3) r2 = √(3) cm. It implies; Area of the coloured inscribe...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd February, 2025
Sir Mike Ambrose is the author of the question. Let the base of the parallelogram be 2 units. Therefore the area of the parallelogram is; 2(area triangle with height (sin70/sin35) unit and base 2s...
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Mathematics Question and Solution

By OnlineEdumath   |  21st February, 2025
Sir Mike Ambrose is the author of the question. Let the side of the regular hexagon be 1 unit. Therefore; Area green is; Area triangle with height ½ units and base √(3) units + Area trian...
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Mathematics Question and Solution

By OnlineEdumath   |  21st February, 2025
Area yellow is; 2(area triangle with height (4.5/cos15) cm and base (4.5/cos15)sin60 cm + Area square with side (4.5/cos15) cm. = 2*½*(4.5/cos15)²(√(3)/2) + (4.5/cos15)² = (4.5/cos15)²(√(3)/2) +...
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Mathematics Question and Solution

By OnlineEdumath   |  20th February, 2025
Let a be the side of the inscribed square. Calculating a. tan60 = a/b b = a/(tan60) cm. Where b is BS = CR. Therefore; 2b+a = 10 2a/(tan60)+a = 10 a((2/tan60)+1) = 10 a = 10(2√(3)-3) cm. a = 4.6...
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Mathematics Question and Solution

By OnlineEdumath   |  19th February, 2025
Sir Mike Ambrose is the author of the question. Area green exactly in decimal is; Square side is (16/√(17)) units. Area trapezoid with parallel sides (16/√(17)) units and (4/√(17)) units, an...
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Mathematics Question and Solution

By OnlineEdumath   |  18th February, 2025
Let the bigger inscribed side of the square be 2 units. Therefore, the big inscribed square side is 1 unit. The marked angle is; ½(atan(½)+atan(2)) = ½(90°) = 45°
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Mathematics Question and Solution

By OnlineEdumath   |  17th February, 2025
Area blue is; Area square with side 10 cm - Area quarter circle with radius 10 cm - Area square with side 5 cm + Area quarter circle with radius 5 cm. = (10*10) - (¼*10*10*π) - (5*5) + (¼*5*5*π)...
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Mathematics Question and Solution

By OnlineEdumath   |  16th February, 2025
Area pink is; 4(area semicircle with radius 4 cm - area quarter circle with radius 4√(2) cm + area triangle with height and base 4√(2) cm) respectively. It implies; 4(½(π(4²)) - ¼(π(4√(2))²) + ½(...
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Mathematics Question and Solution

By OnlineEdumath   |  16th February, 2025
Sir Mike Ambrose is the author of the question. Yellow area exactly in decimal cm² is; Area triangle with height 7.49903313849 cm and base 8sin(32.2356103172) cm + Area triangle with height 7.49...
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Mathematics Question and Solution

By OnlineEdumath   |  15th February, 2025
Sir Mike Ambrose is the author of the question. Let c be 4 units. Therefore; b is; 2cos(25)+2cos(25)tan(65/2) b = 2.96737905059 units. a is; 2sin(65)-2sin(65)tan(65/2) a = 0.65...
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Mathematics Question and Solution

By OnlineEdumath   |  14th February, 2025
Let the inscribed square side be a. tan60 = a/b a = √(3)b cm. Where b is BS = CR It implies; b+√(3)b+b = 10 (2+√(3))b = 10 b = 10(2-√(3)) cm. Therefore; a = √(3)*10(2-√(3)) a = 10(2√(3)-3) cm. a...
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Mathematics Question and Solution

By OnlineEdumath   |  14th February, 2025
Sir Mike Ambrose is the author of the question. Area ABC (yellow area) exactly is; Area triangle with height ⅓√(265) cm and base ((5√(26)/6)sin84.3306169587) cm. = ½*⅓√(265)*((5√(26)/6)sin84.33061...
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Class with Tejiri (year 12) and Vwarhe (year 10)

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Introduction to Decimals

Introduction to Decimals

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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