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OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

We are smart and clever!

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
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Welcome to Online Edumath

By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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We are smart and clever!

By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  6th June, 2025
Sir Mike Ambrose is the author of the question. tan30 = a/3 a = √(3) units. b = a+3 b = (3+√(3)) units. tan30 = c/b ⅓√(3) = c/(3+√(3)) c = ⅓(3√(3)+3) units. c = (1+√(3)) units. It implies; (1+√(...
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Mathematics Question and Solution

By OnlineEdumath   |  6th June, 2025
Let a be the blue length. b² = 4²+3² b = √(25) b = 5 units. Let alpha be c. cos(2c) = 4/5 cos(c+c) =4/5 (cosc)²-(sinc)² = 4/5 --- (1). cosc = 3/a --- (2). a² = 3²+d² d = √(a²-9)...
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Mathematics Question and Solution

By OnlineEdumath   |  5th June, 2025
Let a be the radius of the circle. b = 7-3 b = 4 cm. c = (7-a) cm. d = (3-a) cm. e = c+d e = 7-a+3-a e = (10-2a) cm. Calculating a. e² = (2a)²+4²  (10-2a)² = 4a²+16 100-40a+4...
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Mathematics Question and Solution

By OnlineEdumath   |  5th June, 2025
Notice. Triangle ACD and Triangle BCD are right-angled triangles. Let AD = 2 units. AB = 6 units. It implies; BD = 6-2 BD = 4 units. a² = 2(0.5*4)² a = 2√(2) units. a is BE = C...
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Mathematics Question and Solution

By OnlineEdumath   |  5th June, 2025
Notice. The inscribed square area is 3 square units. Therefore the single side length of the inscribed square is √(3) units. The radius of the ascribed quarter circle will be; √((√(3))²+(...
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Mathematics Question and Solution

By OnlineEdumath   |  4th June, 2025
Let AG be y. Calculating y. a² = 8²+y² a = √(y²+64) cm. a is AD. It implies; Considering area ADG including the inscribed circle with radius 1 cm. ½(1*8)+½(1*y)+½(1*√(y²+64)) = ½(8*y) 8+y+√(y²...
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Mathematics Question and Solution

By OnlineEdumath   |  4th June, 2025
Let the side length of the regular pentagon be 1 unit. tan36 = a/0.5 a = 0.363271264 units. b² = 0.363271264²+0.5² b = 0.61803398875 units. tan72 = c/0.5 c = 1.53884176859 units. Are...
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Mathematics Question and Solution

By OnlineEdumath   |  4th June, 2025
Let the single side length of the square be x. Therefore; Area rectangle of length x unit and width 1 cm + area triangle of height x cm and width (x-2) cm + 2(area triangle of height (x-1) cm...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd June, 2025
Let a be the side length of the regular hexagon. 3² = 1²+a²-2acosb 2acosb = a²-8 cosb = (a²-8)/(2a) --- (1). c²+(a²-8)² = (2a)² c² = 4a²-(a⁴-16a²+64) c = √(-a⁴+20a²-64) units. sinb = c...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd June, 2025
Let the radius of the semi circle be 3 units. Calculating area Red. Area red will be; 2(area triangle of two length 3 units and 1 unit, and angle (cos–¹(⅓)), angle they form) + area sector...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd June, 2025
a = 180-75-27 a = 78° b = 1+½(√(5)+1)  b = 2.61803398875 units. (2.61803398875/sin78) = (c/sin27) c = 1.21511575349 units. sin75 = d/1.21511575349 d = 1.17371168822 units. cos75 = e...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd June, 2025
Sir Mike Ambrose is the author of the question. Area W to 3 decimal places is; Area triangle of two length 5 units and 7.5 units, and angle 86.4166783015° - Area triangle of two length 5 units...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd June, 2025
Sir Mike Ambrose is the author of the question. Let the length of the inscribed rectangle be 2 units. Let the width of the inscribed rectangle be √(3) units. Therefore the single side length...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd June, 2025
Let r be the radius of the quarter circle. Let x be the interior angle facing 1 cm. a = (x+45)° a is alternate to y, the angle formed by the meet point of r and 2 cm at the circumference of...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the inscribed half circle. b²+8² = (2a)² b = √(4a²-64) units. It implies; Calculating a. 2a ~ 8 a ~ √(4a²-64) Cross Multiply. 8a = 2a√(4a²-64) 4 = √(4a²-...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the red inscribed circle. b = (4-a) units. tan30 = a/b ⅓√(3) = a/(4-a) 3a = 4√(3)-√(3)a (3+√(3))a = 4√(3) a = 4√(3)/(3+√(3)) a = ⅙(12√(3)-12) a = (2√(3)-2) units....
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the circle. c = (a-1) units. Calculating a. 7² = a²+(a-1)²-2a(a-1)cosb 49 = a²+a²-2a+1-(2a²-2a)cosb  48 = 2a²-2a-(2a²-2a)cosb  (2a²-2a)cosb = 2a²-2a-48 --- (1)....
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the inscribed circle. b² = 2(10)² b = 10√(2) cm. b is the diagonal of the square. 10²+a² = c² c = √(100+a²) cm. d = b-c d = (10√(2)-√(100+a²)) cm. Calculating a. 2a² = (1...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the circle. b² = a²+√(5)² b = √(a²+5) units. It implies; 2a ~ √(a²+5) 8 ~ a Cross Multiply. 2a² = 8√(a²+5) a² = 4√(a²+5) a⁴ = 16a²+80 a⁴-16a²-80 = 0 Le...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
r will be; ½(½(AB)) = ¼(AB) Therefore; r = ¼(1) r = ¼ units.
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Let the ascribed semi circle radius be R. Let the inscribed circle radius be r. Notice; R=2r It implies; R²=1²+r² (2r)²=1+r² 4r²=1+r² 4r²-r²=1 3r²=1 Therefore; r =...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
a ~ 6 6 ~ 8 Cross Multiply. 8a = 6*6 2a = 9 a = ½(9) units. b = a+8 b = ½(9)+8 b = ½(25) units. b is the diameter of the ascribed half circle. c = ½(b) c = ¼(25) units. c is the...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Calculating area of the red inscribed circle. Let a be the radius of the blue ascribed circle. πa² =144π a² = 144 a = 12 cm. b = 2a b = 24 cm. b is the diameter of the blue ascribed cir...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd June, 2025
Radius of the green circle is 4 units, therefore area of the green circle is; π4² = 16π square units. Calculating radius of the red circle. Let the radius of the red circle be r. (4-...
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Mathematics Question and Solution

By OnlineEdumath   |  1st June, 2025
Let 1 unit be the side length of the regular hexagon. a = ⅙*180(6-2) a = 120° a is the single interior angle of the regular hexagon. cos75 = 0.5/b b = 1.93185165258 units. c² = 1²+0.5²-...
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Mathematics Question and Solution

By OnlineEdumath   |  1st June, 2025
Let the three equal inscribed lengths be y. a = 5+4 a = 9 units. a is the radius of the ascribed half circle. b² = y²+y² b = √(2)y units. Notice. a = b √(2)y = 9 y = ½(9√(2)) uni...
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Mathematics Question and Solution

By OnlineEdumath   |  1st June, 2025
Sir Mike Ambrose is the author of the question. Let the radius of the semi circle be 3 units. Therefore shaded area ÷ area square will be; (½(area quarter circle of radius 3 units - area tri...
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Mathematics Question and Solution

By OnlineEdumath   |  1st June, 2025
Let the radius of the ascribed quarter circle be R. Let the radius of the inscribed circle be r. Therefore; 2²+(2r)²=R² 4+4r²=R² Therefore; R²-4r²=4 Multiplying through by ¼(π)...
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Mathematics Question and Solution

By OnlineEdumath   |  1st June, 2025
Let a be the side length of the two equal inscribed lengths. r = 2+1 r = 3 units. r is the radius of the ascribed half circle. b²+(a/2)² = 3² b²= 9-¼(a²) b = √(9-¼(a²)) b = ½√(36-a²) unit...
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Mathematics Question and Solution

By OnlineEdumath   |  1st June, 2025
a = (10+x) units. a is the radius of the half circle. (10+10)² = 16²+b² b = √(400-256) b = √(144) b = 12 units. It implies; 12 ~ c 20 ~ 10 Cross Multiply. 20c = 120 c = 6 units...
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Mathematics Question and Solution

By OnlineEdumath   |  1st June, 2025
Let the radius of the circle be a. sinb = a/(a+a) b = 30° cos30 = c/2a c = √(3)a units. d = 2-c d = (2-√(3)a) units. sin30 = e/d e =½(2-√(3)a) units. cos30 = f/d ½√(3) = f/(2-√(...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Area S exact, or to 3 d.p. will be; Area sector of radius 2√(7) units and angle (180 - 2sin–¹(4sin120÷(2√(7)))) + area triangle of two lengths 2...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Let the radius of the red circle be r. Calculating r. It will be; √(13²-5²)=√((9+r)²-(9-r)²)+√((4+r)²-(4-r)²) 12=√(36r)+√(16r) 12=10√(r) √(r)=1.2 r=1.44 units. Calculating a...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Kindly move the question left/right one time to review the solution. Thank you nicely.
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Let the radius of the inscribed semi circle be 1 unit. Therefore; Shaded area ÷ Rectangle area in it's simplest decimal form will be; (0.25...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Let the radius of one of the two equal circles be 1 unit. Total shaded area ÷ Rectangle area will be; (½(2x4)-π-(1-¼(4-π)-((180-2tan–¹(0.5))π÷...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Let x be the radius of the sector. b = (x-1) units. c = x+b c = x+(x-1) c = (2x-1) units. Therefore; 5*3 = (2x-1)*1 15 = 2x-1 2x = 16 x = 8 units. Again, a is the radius of the se...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
x ~ 7 7 ~ y Cross Multiply. y = 49/x units. Notice. 7 units is the radius of the green inscribed half circle. x = 5 units. x is the radius of the red inscribed half circle. Therefor...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
tana = 3/1.5 a = atan(2)° b = 3+1.5 b = 4.5 units. c = 3+1+x c = (4+x) units. Calculating x. It implies; tan(atan(2)) = c/b 2 = (4+x)/4.5 2 = (4+x)/(9/2) 2 = 2(4+x)/9 18 = 8...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Notice. Calculating the required angle, alpha. 4 units is the radius of the quarter circle. It implies; 3² = 4²+4²-2*4*4cosa 9 = 32-32cosa 32cosa = 32-9 a = acos(23/32) a = 44.04862...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
a = ½(2+7) a = 4.5 units. a is the radius of the ascribed half circle. Let b be the radius of the inscribed circle. c = (4.5-2b) units. d = (4.5-b) units. e = 4.5-2-b e = (2.5-b) uni...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Let the side length of the regular heptagon be 1 unit. Calculating angle x. a = ⅐*180(7-2) a = ⅐(900)° a is the single interior angle of the regular heptagon. b = ½(360-2*⅐(900)) b = 18...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Calculating x. a = ⅙*180(6-2) a = 120° a is the single interior angle of the green regular hexagon. b = ½(x) units. c = ⅙(x) units. It implies; d ~ b b ~ c Therefore; d ~ ½(...
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Mathematics Question and Solution

By OnlineEdumath   |  28th May, 2025
Let the side length of the ascribed square be 1 unit. Therefore, the side length of the inscribed green regular triangle 1 unit. a = 90-60° a = 30° b² = 2-2cos30 b = 0.51763809021 units....
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Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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