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OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

We are smart and clever!

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
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Welcome to Online Edumath

By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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We are smart and clever!

By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  6th November, 2024
Calculating Green Area. a = 2*4 a = 8 units. a is the radius of the ascribed quarter circle. b²+4² = 8² b² = 64-16 b = √(48) b = 4√(3) units. tanc = 4√(3)/4 c = atan(√(3))° c = 60°...
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Mathematics Question and Solution

By OnlineEdumath   |  6th November, 2024
Inscribed semi circle radius is 4 cm. Inscribed quarter circle radius is 8 cm. tana = 4/8 a = atan(½)° b = 2a b = 2atan(½)° c = 180-b c = 2atan(2)° Blue Area is; Area sector wi...
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Mathematics Question and Solution

By OnlineEdumath   |  5th November, 2024
2^(x+1)+2^(x-1) = 320 Let 2^(x) be p. It implies; 2p+½(p) = 320 ½(5p) = 320 5p = 640 p = 128 And  p = 2^(x) Calculating x. 2^(x) = 128 2^(x) = 2⁷ x = 7
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Mathematics Question and Solution

By OnlineEdumath   |  5th November, 2024
Let b be 1 unit. a = 50° b = 40° a and b are the two interior complementary angles or acute angles of the small right-angled triangle with hypotenuse b. sin50 = c/b c = sin50 c = 0.766044...
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Mathematics Question and Solution

By OnlineEdumath   |  4th November, 2024
Calculating angle x. Let 1 be the base of the ascribed isosceles triangle. a = 180-39-2(27) a = 141-54 a = 87° (1/sin87) = (b/sin(2*27)) b = 0.8101272456 units. c = 180-27-15-39 c =...
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Mathematics Question and Solution

By OnlineEdumath   |  4th November, 2024
Let AB be a. b = (a-2) units. c = ½(a) units. c is BD. d = c-2 d = ½(a)-2 d = ½(a-4) units. It implies; 2 - (a-2) ½(a-4) - 2 Cross Multiply. 4 = ½(a-4)(a-2) 8 = a²-6a+8 a...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd November, 2024
Let 1 be the side length of the ascribed regular hexagon. a = ⅙*180(6-2) a = 120° a is the single interior angle of the ascribed regular hexagon. b² = 1²+1²-2*1*1cos120 b = 1.7320508076 un...
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Mathematics Question and Solution

By OnlineEdumath   |  3rd November, 2024
Calculating Alpha. Let it be a. Let b be the radius of the ascribed quarter circle. c = (b-√(2)) units. d = (b-2√(2)) units. It implies, observing similar plane shape (right-angled)...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd November, 2024
Calculating angle x. Let AR be 1 unit. a = 180-24-15 a = 180-39 a = 141° a is angle ARK. (1/sin15) = (b/sin141) b = 2.4315072749 units. b is AK. c = 180-12-6 c = 180-18 c = 162°...
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Mathematics Question and Solution

By OnlineEdumath   |  2nd November, 2024
Sir Mike Ambrose is the author of the question. Calculating the equation of the curve. y-b=a(x-4)² ----- (1) At coordinate (8, 0) -b=16a Therefore; a = -b/16 Sub. a in (1) to get...
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Mathematics Question and Solution

By OnlineEdumath   |  1st November, 2024
Let the two equal lengths be 1 unit. (a) Calculating Theta exactly. Let theta be x. Calculating x. x = ½(90-54) x = ½(36) x = 18° sin18 = a/1 a = 0.30901699437 units. b = 90-18...
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Mathematics Question and Solution

By OnlineEdumath   |  1st November, 2024
Let the side of the inscribed square be a. Calculating a. a+2√(a²-(a/2)²) = 10√(2) a+2√(3a²/4) = 10√(2) 2√(3a²/4) = 10√(2)-a 3a² = 200-20√(2)a+a² 2a²+20√(2)a-200 = 0 a²+10√(2)a-100 = 0...
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Mathematics Question and Solution

By OnlineEdumath   |  31st October, 2024
Sir Mike Ambrose is the author of the question. Biggest square side is 14 units. Bigger square side is 8 units. a = atan(9/16) (9/16) = b/c c = (16b/9) units. (16b/9)+6 = 14 (16b/9)...
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Mathematics Question and Solution

By OnlineEdumath   |  31st October, 2024
Sir Mike Ambrose is the author of the question. Area Red Total in 1 d. p. Square unit is; Area Square with side 2√(2) units - Area triangle with height 2√(2) units and base 1.1313708499 units +...
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Mathematics Question and Solution

By OnlineEdumath   |  30th October, 2024
Let the biggest regular pentagon side length be 2 units. sin72 = a/2 a = 1.90211303259 units. tan72 = (1.90211303259/b) b = 0.61803398875 units. c = 2b c = 1.2360679775 units. Where c...
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Mathematics Question and Solution

By OnlineEdumath   |  30th October, 2024
Sir Mike Ambrose is the author of the question. The side length of the congruent Hexagons is 2 units. Area hexagon is; (6*2²)/(4tan30) = 6√(3)) square units. a² = 8-8cos30 a = √(8-4√(3)...
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Mathematics Question and Solution

By OnlineEdumath   |  29th October, 2024
Let the side length of the regular pentagon be 4 units. a = ⅕*180(5-2) a = 108° a is the single interior angle of the regular pentagon. b = ½(180-a) b = ½(180-108) b = 36° c = 2 units....
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Mathematics Question and Solution

By OnlineEdumath   |  29th October, 2024
Notice. 7 square units is the are of the small pink half circle. ½*a²π = 7 And π = 22/7 ½*a²(22/7) = 7 11a² = 49 √(11)a = 7 a = 7√(11)/11 units. a = 2.110579412 units. a is the radius...
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Mathematics Question and Solution

By OnlineEdumath   |  28th October, 2024
a² = 4²+3² a = √(25) a = 5 units. a is MN, the side length of the inscribed square. b² = 2(5²) b = 5√(2) units. b is MK, the diagonal of the inscribed square. tanc = 4/3 c = atan(4/3)°...
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Mathematics Question and Solution

By OnlineEdumath   |  28th October, 2024
Notice. 7 square units is the are of the small pink half circle. ½*a²π = 7 And π = 22/7 ½*a²(22/7) = 7 11a² = 49 √(11)a = 7 a = 7√(11)/11 units. a = 2.110579412 units. a is the radius...
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Mathematics Question and Solution

By OnlineEdumath   |  28th October, 2024
tana = 5/10 a = atan(½)° b = 2a b = 2atan(½)° c = b-45 c = 8.1301023542° d² =10²+10²-2*10*10cos8.1301023542 d = 1.4177804018 units. e = ½(180-8.1301023542) e = 85.9349488229° f²...
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Mathematics Question and Solution

By OnlineEdumath   |  28th October, 2024
Sir Mike Ambrose is the author of the question. Let length AB be 3 units. Therefore; AC = 20 units. It implies; Area large square is; 20² = 40 square units. Area orange is; A...
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Mathematics Question and Solution

By OnlineEdumath   |  27th October, 2024
Let EB be a. Let AE be b. It implies; a/b = √(2) --- (1). a+b = 1 --- (2). From (1). a = √(2)b --- (3). Substituting (3) in (2) to get b. √(2)b+b = 1 b(√(2)+1) = 1 b = (√...
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Mathematics Question and Solution

By OnlineEdumath   |  27th October, 2024
Sir Mike Ambrose is the author of the question. Let the side of the square be 2 units. Therefore; Area square is; 2² = 4 square units. Area S is; Area triangle with two side 0.9892...
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Mathematics Question and Solution

By OnlineEdumath   |  27th October, 2024
Let the square side be 2 units. tan30 = a/2 a = ⅓(2√(3)) unit. sin60 = 2/b b = ⅓(4√(3)) units. c = 2-a c = ⅓(6-2√(3)) units. It implies; Area Shaded is; 2(½*(⅓(6-2√(3)))²sin60)...
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Mathematics Question and Solution

By OnlineEdumath   |  26th October, 2024
Sir Mike Ambrose is the author of the question. Let the side of the inscribed square be 2 units. Therefore; Area S is; Area triangle with two side 1.03528 units and 0.53589838486 units, a...
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Mathematics Question and Solution

By OnlineEdumath   |  26th October, 2024
cos15 = 12/a a = 12.42331416492 cm. Where a is the side length of the inscribed regular triangle. Radius, r of the inscribed circle is; tan30 = r/(0.5* 12.42331416492) r = 3.58630188867...
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Mathematics Question and Solution

By OnlineEdumath   |  25th October, 2024
a = 90+45 a = 135° b² = 6²+(4√(2))²-2*6*4√(2)cos135 b = 10.7703296143 units. b = 2√(29) units. b is BC. (10.7703296143/sin135) = (6/sinc) c = 23.1985905136° c is angle ACD. tan23.198...
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Mathematics Question and Solution

By OnlineEdumath   |  25th October, 2024
Let the diameter of the blue semi circle be a. Calculating a. It implies; (½*a*6)+(½*10*16) = 140 6a+160 = 2*140 6a = 280-160 6a = 120 a = 20 cm. Again, a is the diameter of the blue...
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Mathematics Question and Solution

By OnlineEdumath   |  24th October, 2024
Let x be the side of the small inscribed square. Calculating x. Notice; The side length of the ascribed square is 14 cm. A small triangle with height ½ cm on the same vertical length w...
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Mathematics Question and Solution

By OnlineEdumath   |  24th October, 2024
Sir Mike Ambrose is the author of the question. Let the small inscribed circle's radius be x. x = 6 cm. Let the big inscribed circle's radius be y. y = 8 cm. Let the ascribed semi circle's...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd October, 2024
a = ½(10) a = 5 units. a is the radius of the circle. b = (5-a) units. c = (5-2a) units. Calculating a. 5² = (5-2a)²+(5-a)² 25 = 25-20a+4a²+25-10a+a² 5a²-30a+25 = 0 a²-6a+5 = 0 a²...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd October, 2024
a = 4+6 a = 20 cm. a is the radius of the quarter circle. tanb = 10/4 b = atan(5/2)° c = b+60 c = (60+atan(5/2))° c = 128.1985905136° (10/sin128.1985905136) = (4/sind) d = 18.3215084...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd October, 2024
Calculating x. (2√(3)/sin100) = (a/sin60) a = 3.0462798357 units. b = 180-(180-100-60) b = 160° Therefore, the required length, x is; x² = 2(3.0462798357)²-2(3.0462798357)²cos160  x...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd October, 2024
Notice; a² = 5² - (⅕(√(481)))² a = ⅕(12) units. b = 5-a b = ⅕(13) units. c² = 4²-(⅕(12))² c = ⅕(16) units. d = atan(4/3)° (a) Area A exactly is; ½*⅕(16)*(5+⅕(13)) - atan(4/3)π*16/360 = ((8*38)...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd October, 2024
Calculating area of the inscribed triangle. a = 2r a = 2√(5) units. a is the side length of the ascribed square. tanb = √(5)/(2√(5)) b = atan(½)° c = 2b c = 2atan(½)° d = 90-2atan(½...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd October, 2024
Sir Mike Ambrose is the author of the question. Let the side of the square be 2 units. Area square is; 2² = 4 square units. Area orange is; Area triangle with two side 0.70710678119 u...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd October, 2024
Sir Mike Ambrose is the author of the question. Area red is; Area triangle with two side 4 cm and 8 cm, and angle 110°. = 0.5*4*8sin110 = 15.0350819326 cm² Area blue is; Area triangle wit...
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Mathematics Question and Solution

By OnlineEdumath   |  21st October, 2024
a² = 2²+2²-2*2*2cos120 a = √(8+½(8)) a = √(12) a = 2√(3) units. a is the side length of each of the 4 inscribed small regular hexagon. sin30 = b/a b = asin30 b = ½*2√(3) b = √(3) units....
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Mathematics Question and Solution

By OnlineEdumath   |  21st October, 2024
Let a be the congruent side lengths each. b = ½(2) b = 1 unit. c²+1² = a² c = √(a²-1) units. d = ½(180-45) d = ½(135) d = 67.5° tan67.5 = e/1 e = 2.4142135624 units. e = (1+√(2))...
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Mathematics Question and Solution

By OnlineEdumath   |  21st October, 2024
a = ¼(60) a= 15 units. b² = 40²+15² b = 5√(73) units. b = 42.7200187266 units. c = ½(b) c = 2.5√(73) units. c = 21.3600093633 units. c is each of the congruent lengths. d = 60-15 d...
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Mathematics Question and Solution

By OnlineEdumath   |  21st October, 2024
a = 180-54-30-18 a = 180-102 a = 78° a is angle ABC. b = 78+54 b = 132° b is angle BAD. c = 180-b-18 c = 180-150 c = 30° c is angle ADB. Let AD = 1 unit. (1/sin18) = (d/sin30)...
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Mathematics Question and Solution

By OnlineEdumath   |  21st October, 2024
Calculating h. tan60 = h/a a = ⅓(√(3)h) units. tan30 = h/b b = √(3)h units. It implies; a + b = 100 ⅓(√(3)h)+√(3)h = 100 √(3)h+3√(3)h = 300 4√(3)h = 300 √(3)h = 75 h = ⅓(75√(3))...
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Mathematics Question and Solution

By OnlineEdumath   |  20th October, 2024
Let a be the radius of the half circle. a-x = 4 x = a-4 --- (1). b = (a-2x) units. It implies; a² = 4²+(a-2x)² a² = 16+a²-4ax+4x² 4ax = 16+4x² --- (2). Substituting (1) in (2) to...
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Our Media

media video Class with Tejiri (year 12) and Vwarhe (year 10)

Class with Tejiri (year 12) and Vwarhe (year 10)

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Introduction to Decimals

Introduction to Decimals

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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