OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

Our Updates

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
By OnlineEdumath   |  6th June, 2025
Sir Mike Ambrose is the author of the question. tan30 = a/3 a = √(3) units. b = a+3 b = (3+√(3)) units. tan30 = c/b ⅓√(3) = c/(3+√(3)) c = ⅓(3√(3)+3) units. c = (1+√(3)) units. It implies; (1+√(...
By OnlineEdumath   |  6th June, 2025
Let a be the blue length. b² = 4²+3² b = √(25) b = 5 units. Let alpha be c. cos(2c) = 4/5 cos(c+c) =4/5 (cosc)²-(sinc)² = 4/5 --- (1). cosc = 3/a --- (2). a² = 3²+d² d = √(a²-9)...
By OnlineEdumath   |  5th June, 2025
Let a be the radius of the circle. b = 7-3 b = 4 cm. c = (7-a) cm. d = (3-a) cm. e = c+d e = 7-a+3-a e = (10-2a) cm. Calculating a. e² = (2a)²+4²  (10-2a)² = 4a²+16 100-40a+4...
By OnlineEdumath   |  5th June, 2025
Notice. Triangle ACD and Triangle BCD are right-angled triangles. Let AD = 2 units. AB = 6 units. It implies; BD = 6-2 BD = 4 units. a² = 2(0.5*4)² a = 2√(2) units. a is BE = C...
By OnlineEdumath   |  5th June, 2025
Notice. The inscribed square area is 3 square units. Therefore the single side length of the inscribed square is √(3) units. The radius of the ascribed quarter circle will be; √((√(3))²+(...
By OnlineEdumath   |  4th June, 2025
Let AG be y. Calculating y. a² = 8²+y² a = √(y²+64) cm. a is AD. It implies; Considering area ADG including the inscribed circle with radius 1 cm. ½(1*8)+½(1*y)+½(1*√(y²+64)) = ½(8*y) 8+y+√(y²...
By OnlineEdumath   |  4th June, 2025
Let the side length of the regular pentagon be 1 unit. tan36 = a/0.5 a = 0.363271264 units. b² = 0.363271264²+0.5² b = 0.61803398875 units. tan72 = c/0.5 c = 1.53884176859 units. Are...
By OnlineEdumath   |  4th June, 2025
Let the single side length of the square be x. Therefore; Area rectangle of length x unit and width 1 cm + area triangle of height x cm and width (x-2) cm + 2(area triangle of height (x-1) cm...
By OnlineEdumath   |  3rd June, 2025
Let a be the side length of the regular hexagon. 3² = 1²+a²-2acosb 2acosb = a²-8 cosb = (a²-8)/(2a) --- (1). c²+(a²-8)² = (2a)² c² = 4a²-(a⁴-16a²+64) c = √(-a⁴+20a²-64) units. sinb = c...
By OnlineEdumath   |  3rd June, 2025
Let the radius of the semi circle be 3 units. Calculating area Red. Area red will be; 2(area triangle of two length 3 units and 1 unit, and angle (cos–¹(⅓)), angle they form) + area sector...
By OnlineEdumath   |  3rd June, 2025
a = 180-75-27 a = 78° b = 1+½(√(5)+1)  b = 2.61803398875 units. (2.61803398875/sin78) = (c/sin27) c = 1.21511575349 units. sin75 = d/1.21511575349 d = 1.17371168822 units. cos75 = e...
By OnlineEdumath   |  3rd June, 2025
Sir Mike Ambrose is the author of the question. Area W to 3 decimal places is; Area triangle of two length 5 units and 7.5 units, and angle 86.4166783015° - Area triangle of two length 5 units...
By OnlineEdumath   |  3rd June, 2025
Sir Mike Ambrose is the author of the question. Let the length of the inscribed rectangle be 2 units. Let the width of the inscribed rectangle be √(3) units. Therefore the single side length...
By OnlineEdumath   |  3rd June, 2025
Let r be the radius of the quarter circle. Let x be the interior angle facing 1 cm. a = (x+45)° a is alternate to y, the angle formed by the meet point of r and 2 cm at the circumference of...
By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the inscribed half circle. b²+8² = (2a)² b = √(4a²-64) units. It implies; Calculating a. 2a ~ 8 a ~ √(4a²-64) Cross Multiply. 8a = 2a√(4a²-64) 4 = √(4a²-...
By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the red inscribed circle. b = (4-a) units. tan30 = a/b ⅓√(3) = a/(4-a) 3a = 4√(3)-√(3)a (3+√(3))a = 4√(3) a = 4√(3)/(3+√(3)) a = ⅙(12√(3)-12) a = (2√(3)-2) units....
By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the circle. c = (a-1) units. Calculating a. 7² = a²+(a-1)²-2a(a-1)cosb 49 = a²+a²-2a+1-(2a²-2a)cosb  48 = 2a²-2a-(2a²-2a)cosb  (2a²-2a)cosb = 2a²-2a-48 --- (1)....
By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the inscribed circle. b² = 2(10)² b = 10√(2) cm. b is the diagonal of the square. 10²+a² = c² c = √(100+a²) cm. d = b-c d = (10√(2)-√(100+a²)) cm. Calculating a. 2a² = (1...
By OnlineEdumath   |  2nd June, 2025
Let a be the radius of the circle. b² = a²+√(5)² b = √(a²+5) units. It implies; 2a ~ √(a²+5) 8 ~ a Cross Multiply. 2a² = 8√(a²+5) a² = 4√(a²+5) a⁴ = 16a²+80 a⁴-16a²-80 = 0 Le...
By OnlineEdumath   |  2nd June, 2025
r will be; ½(½(AB)) = ¼(AB) Therefore; r = ¼(1) r = ¼ units.
By OnlineEdumath   |  2nd June, 2025
Let the ascribed semi circle radius be R. Let the inscribed circle radius be r. Notice; R=2r It implies; R²=1²+r² (2r)²=1+r² 4r²=1+r² 4r²-r²=1 3r²=1 Therefore; r =...
By OnlineEdumath   |  2nd June, 2025
a ~ 6 6 ~ 8 Cross Multiply. 8a = 6*6 2a = 9 a = ½(9) units. b = a+8 b = ½(9)+8 b = ½(25) units. b is the diameter of the ascribed half circle. c = ½(b) c = ¼(25) units. c is the...
By OnlineEdumath   |  2nd June, 2025
Calculating area of the red inscribed circle. Let a be the radius of the blue ascribed circle. πa² =144π a² = 144 a = 12 cm. b = 2a b = 24 cm. b is the diameter of the blue ascribed cir...
By OnlineEdumath   |  2nd June, 2025
Radius of the green circle is 4 units, therefore area of the green circle is; π4² = 16π square units. Calculating radius of the red circle. Let the radius of the red circle be r. (4-...
By OnlineEdumath   |  1st June, 2025
Let 1 unit be the side length of the regular hexagon. a = ⅙*180(6-2) a = 120° a is the single interior angle of the regular hexagon. cos75 = 0.5/b b = 1.93185165258 units. c² = 1²+0.5²-...
By OnlineEdumath   |  1st June, 2025
Let the three equal inscribed lengths be y. a = 5+4 a = 9 units. a is the radius of the ascribed half circle. b² = y²+y² b = √(2)y units. Notice. a = b √(2)y = 9 y = ½(9√(2)) uni...
By OnlineEdumath   |  1st June, 2025
Sir Mike Ambrose is the author of the question. Let the radius of the semi circle be 3 units. Therefore shaded area ÷ area square will be; (½(area quarter circle of radius 3 units - area tri...
By OnlineEdumath   |  1st June, 2025
Let the radius of the ascribed quarter circle be R. Let the radius of the inscribed circle be r. Therefore; 2²+(2r)²=R² 4+4r²=R² Therefore; R²-4r²=4 Multiplying through by ¼(π)...
By OnlineEdumath   |  1st June, 2025
Let a be the side length of the two equal inscribed lengths. r = 2+1 r = 3 units. r is the radius of the ascribed half circle. b²+(a/2)² = 3² b²= 9-¼(a²) b = √(9-¼(a²)) b = ½√(36-a²) unit...
By OnlineEdumath   |  1st June, 2025
a = (10+x) units. a is the radius of the half circle. (10+10)² = 16²+b² b = √(400-256) b = √(144) b = 12 units. It implies; 12 ~ c 20 ~ 10 Cross Multiply. 20c = 120 c = 6 units...
By OnlineEdumath   |  1st June, 2025
Let the radius of the circle be a. sinb = a/(a+a) b = 30° cos30 = c/2a c = √(3)a units. d = 2-c d = (2-√(3)a) units. sin30 = e/d e =½(2-√(3)a) units. cos30 = f/d ½√(3) = f/(2-√(...
By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Area S exact, or to 3 d.p. will be; Area sector of radius 2√(7) units and angle (180 - 2sin–¹(4sin120÷(2√(7)))) + area triangle of two lengths 2...
By OnlineEdumath   |  31st May, 2025
Let the radius of the red circle be r. Calculating r. It will be; √(13²-5²)=√((9+r)²-(9-r)²)+√((4+r)²-(4-r)²) 12=√(36r)+√(16r) 12=10√(r) √(r)=1.2 r=1.44 units. Calculating a...
By OnlineEdumath   |  31st May, 2025
Kindly move the question left/right one time to review the solution. Thank you nicely.
By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Let the radius of the inscribed semi circle be 1 unit. Therefore; Shaded area ÷ Rectangle area in it's simplest decimal form will be; (0.25...
By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Let the radius of one of the two equal circles be 1 unit. Total shaded area ÷ Rectangle area will be; (½(2x4)-π-(1-¼(4-π)-((180-2tan–¹(0.5))π÷...
By OnlineEdumath   |  31st May, 2025
Let x be the radius of the sector. b = (x-1) units. c = x+b c = x+(x-1) c = (2x-1) units. Therefore; 5*3 = (2x-1)*1 15 = 2x-1 2x = 16 x = 8 units. Again, a is the radius of the se...
By OnlineEdumath   |  31st May, 2025
x ~ 7 7 ~ y Cross Multiply. y = 49/x units. Notice. 7 units is the radius of the green inscribed half circle. x = 5 units. x is the radius of the red inscribed half circle. Therefor...
By OnlineEdumath   |  31st May, 2025
tana = 3/1.5 a = atan(2)° b = 3+1.5 b = 4.5 units. c = 3+1+x c = (4+x) units. Calculating x. It implies; tan(atan(2)) = c/b 2 = (4+x)/4.5 2 = (4+x)/(9/2) 2 = 2(4+x)/9 18 = 8...
By OnlineEdumath   |  31st May, 2025
Notice. Calculating the required angle, alpha. 4 units is the radius of the quarter circle. It implies; 3² = 4²+4²-2*4*4cosa 9 = 32-32cosa 32cosa = 32-9 a = acos(23/32) a = 44.04862...
By OnlineEdumath   |  31st May, 2025
a = ½(2+7) a = 4.5 units. a is the radius of the ascribed half circle. Let b be the radius of the inscribed circle. c = (4.5-2b) units. d = (4.5-b) units. e = 4.5-2-b e = (2.5-b) uni...
By OnlineEdumath   |  31st May, 2025
Let the side length of the regular heptagon be 1 unit. Calculating angle x. a = ⅐*180(7-2) a = ⅐(900)° a is the single interior angle of the regular heptagon. b = ½(360-2*⅐(900)) b = 18...
By OnlineEdumath   |  31st May, 2025
Calculating x. a = ⅙*180(6-2) a = 120° a is the single interior angle of the green regular hexagon. b = ½(x) units. c = ⅙(x) units. It implies; d ~ b b ~ c Therefore; d ~ ½(...
By OnlineEdumath   |  28th May, 2025
Let the side length of the ascribed square be 1 unit. Therefore, the side length of the inscribed green regular triangle 1 unit. a = 90-60° a = 30° b² = 2-2cos30 b = 0.51763809021 units....

Our Media

media video Class with Tejiri (year 12) and Vwarhe (year 10)

Class with Tejiri (year 12) and Vwarhe (year 10)

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

media video Mathematics Knowledge

Mathematics Knowledge

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

WhatsApp Google Map

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support