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OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

We are smart and clever!

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
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Welcome to Online Edumath

By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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We are smart and clever!

By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  27th June, 2025
Let the height and base of the brown area be x and y respectively. Therefore; ½(3+x)(4+y)-42 = ½(xy) 12+3y+4x+xy-84 = xy 3y+4x = 72 --- (1). 3 ~ (3+x) 4 ~ (y+4) Cross Multiply. 4(...
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Mathematics Question and Solution

By OnlineEdumath   |  27th June, 2025
a² = 2(1)² a = √(2) units. a is the diagonal of the inscribed square and also the side length of the two congruent inside bigger regular triangle. b = ½(a)  b = ½√(2) units. c²+b² = a² c² = √(2)²-...
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Mathematics Question and Solution

By OnlineEdumath   |  27th June, 2025
a = 2(20) a = 40 units. b = 60+20 b = 80 units. c = 2(20) c = 40 units. d = atan(80/40)+atan(20/40) d = 90° d is angle ACB Area Triangle ABC is; ½*√(80²+40²)*√(40²+20²) = ½*√(6400+1600)*√(1600...
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Mathematics Question and Solution

By OnlineEdumath   |  27th June, 2025
Let the inscribed green square side length be a. 2b² = a² b = ½√(2)a units. c² = 2(4)² c = 4√(2) units. c is the diagonal of the ascribed bigger square. It implies; 4+a+½(a) = c...
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Mathematics Question and Solution

By OnlineEdumath   |  26th June, 2025
Calculating x, length AD. c² = x²+3² c = √(x²+9) units. c is AC. d²+2² = c² d² = √(x²+9)²-4 d² = x²+5 d = √(x²+5) units. d is AB. Notice. a-b = 30 Therefore; a = (30+b)° sinb = x/√(x²+9) --- (1...
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Mathematics Question and Solution

By OnlineEdumath   |  26th June, 2025
Let b = 1 unit. Calculating a. c² = 2a² c = √(2)a units. c is the diagonal of each of the three identical squares. d = c-a d = (√(2)a-a) units. It implies; 1² = a²+(√(2)a-a)²-2a(√(2)a-a)cos45...
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Mathematics Question and Solution

By OnlineEdumath   |  26th June, 2025
Let the single side length of the square be (x+12) units. Calculating x. 18²=(x+12)²+(x+6)² 324=x²+24x+144+x²+12x+36 324=2x²+36x+180 2x²+36x-144=0 x²+18x-72=0 (x+9)²=72+81 x = -9±√(153) x ≠...
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Mathematics Question and Solution

By OnlineEdumath   |  26th June, 2025
Calculating Length x. tana = 5/10 a = atan(½)° b = 2a b = 2atan(½)° c = 180-2b c = (180-4atan(½))° It implies; x² = 2(10)²-2(10)²cos(180-4atan(½)) x² = 144 x = 12 units.
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Mathematics Question and Solution

By OnlineEdumath   |  25th June, 2025
Calculating Length x. a = 4+6 a = 10 units. a is the side length of the square. b = 10-3 b = 7 units. c = 10-2-3 c = 5 units. d² = 7²+4² d = √(49+16) d = √(65) units. tane = 4/7...
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Mathematics Question and Solution

By OnlineEdumath   |  25th June, 2025
Calculating Shaded Area. a = 4(4) a = 16 units. a is AB. b = a+4 b = 20 units. b is AC. It implies; 15²+20² = 7²+c² 225+400-49 = c² c = 24 units. c is CE. d = ½(c) d = 12 units. d is CD = DE. d...
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Mathematics Question and Solution

By OnlineEdumath   |  25th June, 2025
Calculating alpha. Let it be a. Let the three equal lengths be 1 units each. b = 180-30-7.5 b = 142.5 ° b is angle AKC. Notice. Angle CAK = Angle KBC = 7.5° (1/sin30) = (c/sin7.5) c = 0.2610523...
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Mathematics Question and Solution

By OnlineEdumath   |  25th June, 2025
Calculating Shaded Area. a² = 1²-(4k)² a = √(1-16k²) units. 1 ~ √(1-16k²) 4k ~ b Cross Multiply. b = 4k√(1-16k²) units. Again. 1 ~ √(1-16k²)  √(1-16k²) ~ c Cross Multiply. c = (1-16k²) units....
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Mathematics Question and Solution

By OnlineEdumath   |  24th June, 2025
a = x° b = (90-x)° R² = 6²+16²-2*6*16cosx R² = 292-192cosx  cosx = (292-R²)/192 --- (1). Notice. At (1). (292-R²) is adjacent. 192 is hypotenuse. Let c be opposite. c² = 1...
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Mathematics Question and Solution

By OnlineEdumath   |  24th June, 2025
Let the radius of the ascribed circle be 2 units. Therefore, radius of the bigger inscribed circle is 1 unit. a = (1+y) units  b = (2-y) units. c = (1-y) units. Calculating y, radius of the big...
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Mathematics Question and Solution

By OnlineEdumath   |  24th June, 2025
Notice. The ascribed quadrilateral is a square. Let it's side length be x. a²+x² = 3² a = √(9-x²) units.    2 ~ 3 b ~ x Cross Multiply. b = ⅓(2x) units. It implies; Calculating x. x²-½(x*√(...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2025
Let OA be 1 unit. Area Triangle AOB is; ½*1*1  = ½ square units. Calculating Area Triangle ODG. a² =2(1)²-2(1)²cos30 a = √(2-√(3)) units. a = 0.51763809021 units. a is AC, the side length of the...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2025
Let a = 1 unit. It implies; 1 ~ b b ~ e Cross Multiply. e = b² f = (1-b²) units. cos60 = g/(1-b) g = ½(1-b) units. h = 2g+1 h = (2-b) units. It implies; Calculating b....
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2025
Calculating length RT. a = ½(10) a = 5 units. a is half the diagonal of the rectangle. b = 8+a b = 13 units. It implies; (RT)²+5² = 13² RT = √(169-25) RT = √(144) RT = 12 units.
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2025
Calculating x, length BE. a = 90-75 a = 15° a is angle CBE. sin15 = b/x b = (xsin15) units. b is CE. c = 5+b c = (5+(xsin15)) units. c is CD. cos15 = d/x d = (xcos15) units. d is BC. Notice. c...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd June, 2025
Let the length of the rectangle be a. Let the width of the rectangle be (6+b) units. ½(2a-4)(6+b)-70 = ½(6a)+½(a-4)b 12a+2ab-24-4b-140 = 6a+ab-4b 6a+ab = 164 Therefore; a(6+b) = 164 Notice....
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Mathematics Question and Solution

By OnlineEdumath   |  22nd June, 2025
Let the side length of the square be x. a = (x-4) units. Calculating x. ½(x²) = ½*x(x-4)-10+30 x² = x(x-4)+40 x² = x²-4x+40 4x = 40 x = 10 units. Again, x is the side length of the square. A...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd June, 2025
Calculating R, radius of the circle. 12a = 3*4 a = 1 unit. b = ½(3+4) b = 3.5 units. c = b-3 c = 0.5 units. d = 180-60 d = 120° e² = R²-3.5² e =√(R²-12.25) units. f² = 1²+0.5...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2025
Calculating R, radius of the quarter circle. a = 3+4 a = 7 units. b² = 2(4)² b = 4√(2) units. c = R-b c = (R-4√(2)) units. d = 180-45 d = 135° R is; R² = 7²+(R-4√(2))²-2*7(R-4√(2))cos135 R² =...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2025
Let BF be a. b² = 18²+a² b = √(324+a²) units. b is AB. c = (a+14) units. It implies; calculating a. (a+14) ~ √(324+a²) √(324+a²) ~ 18 Cross Multiply. 18(a+14) = 324+a² 18a+252 = 324+a² a²-18a+...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2025
Let the side length of the inscribed regular triangle be a. 2b² = a² b = √(a²/2) b = ½√(2)a units. c = 2b c = √(2)a units. c is the side length of the ascribed square. d² = b²+c² d² = (√(2)a)²+(½...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2025
Let AB be 1 unit. Let BC be a. Therefore; CD = (1-a) units. It implies; tan60 = b/(0.5a) 2b = √(3)a b = ½√(3)a units. b is the height of the bigger inscribed equilateral triangle....
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2025
Calculating Blue Area. a = 8+2 a = 10 units. a is the side length of the ascribed square and the radius of the bigger inscribed quarter circle. b = 8 units. b is the radius of the big insc...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2025
Let angle AOB be a. Let b = AD = OB = OD. b is the radius of the quarter circle. Calculating b. 2² = 2b²-2b²cosa 2b²cosa = 2b²-4 b²cosa = b²-2 cosa = (b²-2)/b² --- (1). 4² = b²+(2b)²-4b²cosa 16...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2025
Let r = 1 unit. a = (R+1) units. b = (R-1) units. c²+b² = a² c²+(R-1)² = (R+1)² c² = R²+2R+1-(R²-2R+1) c = √(4R) c = 2√(R) units. d = R+2-R d = 2 units. e = R+R e = 2R units. Calculating R....
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2025
Notice. The ascribed quadrilateral is regular (square). Let a be it's side length. ½*ab = 3 ab = 6 b = (6/a) units. b is the base of the red area. ½*ac = 4 ac = 8 c = (8/a) units....
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2025
tan60 = a/(0.5*8) a = 4tan60 a = 4√(3) cm. a is the diameter of the circle. b = ½(a) b = 2√(3) cm. b is the radius of the circle. c = ¼(8) c = 2 cm. c is the radius of the two equal half circles....
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2025
a = 4+4 a = 8 units. a is the radius of the quarter circle. cosb = ⅛(0.5*4) b = acos(¼)° cosb = c/8 c = 8cos(acos(¼)) c = ¼(8) c = 2 units. c is the width of the inscribed rectangle. sinb = d/8...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2025
Let AD = BC = 1 unit. a = 180-100-30 a = 50° a is angle BAC. (1/sin50) = (b/sin30) b = 0.65270364467 units. b is AC. Therefore, the required angle theta is, let it be c. (0.65270364...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2025
Let BD = CD = 1 unit. a = 180-45-30 a = 105° a is angle CAD. (1/sin105) = (b/sin45) b = 0.73205080757 units. b is AC. c² = 0.73205080757²+2²-2*2*0.73205080757cos30 c = 1.41421356237 units. c is A...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2025
a = 180-60 a = 120° b = 180-120-45 b = 15° (1/sin15) = (c/sin45) c = 2.73205080757 units. sin60 = d/c d = 2.73205080757sin60 d = 2.36602540378 units. cos60 = e/c e = 2.73205080757...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2025
Area blue is; 2(area quarter circle with radius 8 cm - area isosceles right-angled triangle with equal lengths 8 cm) + 2(area quarter circle with radius 4 cm - area isosceles right-angled triang...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2025
Notice. 10 m is the radius of the circle. a = 10-3 a = 7 m. sinb = (7/10) b = asin(7/10)° Calculating length AB. tanb = 10/(AB) AB = 10/(tanb) AB = 10/tan(asin(7/10)) AB = 10.2020406122 m. Or...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2025
Calculating angle x. Let the longest ascribed quadrilateral side length be 1 unit. a = = 180-25-2(35) a = 180-95  a= 85° (1/sin85) = (b/sin25) b = 0.42423259484 units. c = 180-35-2(25) c = 180-8...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2025
Calculating Area Triangle A. Let the two equal inscribed angles be a each. (0.5*14*12sina)÷(0.5*12*35sina) = 14/35 = 2/5 = 2:5 Where 2:5 is the ratio of the bases of the both triangles wi...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2025
b = √(a) b = √(48) b = √(16*3) b = 4√(3) units. b is the radius of the ascribed quarter circle. c = ½(b) c = 2√(3) units. c is the radius of the inscribed half circle. tan30 = d/c ⅓√(3) = d/(2√(3)...
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2025
Calculating angle x. a = 3-1 a = 2 units. a is CD. tanb = 3/1 b = atan(3)° b is angle BCF equal angle ACD. It implies; ((⅕(3√(10)))/sin(atan(3))) = (2/sinc) c = asin(1) c = 90° c...
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2025
Let a be 1 unit. e = ½(180-45) e = 67.5° tane = 1/f f = 1/tan(67.5) f = 0.41421356237 units  g = 1-f g = 1-0.41421356237 g = 0.58578643763 units. 2h² = a² 2h² = 1 h = ½√(2) units...
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Mathematics Question and Solution

By OnlineEdumath   |  14th June, 2025
Let the ascribed square side length be 1 units. Calculating area red inscribed circle. a = (1-b) units. Where b is the radius of the red inscribed circle  sin30 = b/(1-b) 2b = 1-b 3b =...
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Mathematics Question and Solution

By OnlineEdumath   |  14th June, 2025
Let a be the radius of the inscribed pink circle. b = (a+7) units. c = (7-a) units. d = (a-2) units. Calculating a. It implies; a ~ (a+7) (a-2) ~ (7-a) Cross Multiply. a(7-a) = (a-2)(a+7) 7a...
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Class with Tejiri (year 12) and Vwarhe (year 10)

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Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

media video Mathematics Knowledge

Mathematics Knowledge

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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