By OnlineEdumath   |  18th April, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
By OnlineEdumath   |  24th June, 2024
The radius, r if the small circle will be; (5+r)²=2(5-r)² 25+10r+r²=50-20r+2r² Therefore r²-30r+25=0 (r-15)²=-25+225 r = 15±√(200) r = 15±10√(2) It implies; r ≠ 15+10√(2) r = 15...
By OnlineEdumath   |  24th June, 2024
Sir Mike Ambrose is the author of the question. Notice! AB = BC Calculating AB. AB = (20sin60)/sin104 AB = BC = 17.85075169007 cm. Calculating BD BD = (20sin16)/sin104 BD = 5.6815...
By OnlineEdumath   |  23rd June, 2024
Let the side length of the inscribed green square be a. b = ½(10-a) units. c = b+a c = ½(10-a+2a) c = ½(10+a) units. Therefore, a² (area green inscribed triangle) is; 10² = a²+(½(10+a...
By OnlineEdumath   |  23rd June, 2024
Let OC be a. Let the radius of the inscribed blue half circle be b. Calculating area inscribed blue half circle. 20² = 2c² c = √(200) c = 10√(2) units. d = ½(c) d = 5√(2) units. d i...
By OnlineEdumath   |  23rd June, 2024
Let the side length of the two congruent inscribed squares be 1 unit each. a² = 1+2² a = √(5) units. a is the radius of the half circle. tanb = (½)  b = atan(½)° (√(5)/sin(atan(½))) = (...
By OnlineEdumath   |  23rd June, 2024
Let alpha be a. Let AB be b. tana = 2/b --- (1). tana = b/(2+6)  tana = b/8 --- (2). Equating (1) and (2). 2/b = b/8 b² = 16 b = 4 units. Again, b is AB. Therefore, the requir...
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