Let the inscribed square side be a.
tan60 = a/b
a = √(3)b cm.
Where b is BS = CR
It implies;
b+√(3)b+b = 10
(2+√(3))b = 10
b = 10(2-√(3)) cm.
Therefore;
a = √(3)*10(2-√(3))
a = 10(2√(3)-3) cm.
a...
Sir Mike Ambrose is the author of the question.
Area ABC (yellow area) exactly is;
Area triangle with height ⅓√(265) cm and base ((5√(26)/6)sin84.3306169587) cm.
= ½*⅓√(265)*((5√(26)/6)sin84.33061...
Sir Mike Ambrose is the author of the question.
Area Blue Exactly in decimal cm² is;
Area triangle with height 3.84187454245 cm and base 5sin(180-atan(12/5)-atan(4/5))
= ½*3.84187454245*5sin(180-a...
Let the inscribed square side be a.
tan60 = a/b
a = √(3)b cm.
Where b is BS = CR
It implies;
b+√(3)b+b = 10
(2+√(3))b = 10
b = 10(2-√(3)) cm.
Therefore;
a = √(3)*10(2-√(3))
a = 10(2√(3)-3) cm.
a...
Sir Mike Ambrose is the author of the question.
(a) Area yellow exactly in decimal cm² is;
Area triangle with height 25.2274259042 cm and base 14.5sin(½atan(20/21)) cm
= ½*25.2274259042*14.5sin(½a...
Area ABED is;
Area trapezium with parallel sides (4√(2)sin15) cm and (4+4√(2)sin15) cm, and height 4√(3) cm.
= ½*4√(3)((4√(2)sin15)+(4+4√(2)sin15))
= 2√(3)((4√(2)sin15)+(4+4√(2)sin15))
= 24 cm²...
Blue area is;
Area sector with radius 12 units and angle 30°
- Area sector with radius 6 units and angle 60° - Area triangle with height 6 units and base 6sin120 units.
= (30π*12²/360) - (60π*6²/3...
Let the length of the ascribed regular hexagon be 2 units.
Therefore it area will be;
(2*2*6)/(4tan(180/6))
= 6/tan30
= 6√(3) square units.
The green areas is;
Area rectangle with...
Let the side of the ascribed regular hexagon be 2 units.
Area regular hexagon is;
(2*2*6)/(4tan(180/6))
= 6/tan30
= 6√(3) square units.
Area green is;
Area kite with perpendicular lengths 4 un...
a² = 4²+4²-2*4*4cos150
a = 7.72740661031 cm.
Where a is BE.
b = angle ABE = ½(180-150)
b = 15°
c = angle AFE = 180-45-15
c = 120°
(4/sin120) = (d/sin45)
d = 3.26598632371 cm.
Where d is EF.
Noti...
