Total red area is;
3(area square with side 5 units - area quarter circle with radius 5 units) + Area triangle with height 5 units and base 10 units - Area sector with radius 5 units and angle 2a...
Sir Mike Ambrose is the author of the question.
Let the side length of the square be x.
Calculating x.
18²=x²+(x-6)²
324=x²+x²-12x+36
2x²-12x-288=0
x²-6x-144=0
(x-3)²=144+9
x = 3±√(153)...
Please, move the above question left/right one time to review the solution of the question.
Thank you.
Calculating x.
a = 4+1
a = 4 units.
a is the radius of the quarter circle.
b²+4² = 5²
b = √(25-16)
b = 3 units.
tanc = 3/4
c = atan(3/4)°
d = 90-c
d = atan(4/3)°
It implies;...
Sir Mike Ambrose is the author of the question.
Let the single side length of the inscribed regular pentagon be 2 units.
Therefore;
Area green is;
Area rectangle with length 2 units and w...
Shaded area is;
Area sector with radius 10 units and angle acos(0.7) - Area triangle with height √(51) units and base 7 units - area sector with radius 3 units and angle 81.37307344° - area sect...
Sir Mike Ambrose is the author of the question.
Area Purple exactly in decimal square cm is;
Area triangle with two side length 7.04301437734 cm and 7.01866670644 cm, and angle 100°
= ½(7.04...
Calculating Area Orange.
It is;
Area rectangle with length 10 cm and width 5 cm + Area circle with radius 2.5 cm.
= (10*5)+(π*2.5²)
= 50+¼(25π)
= ¼(200+25π) cm²
= 69.6349540849 cm²
Calculating Area of the inscribed half circle.
Let the radius of the inscribed half circle be a.
b² = 2a²
b = √(2)a units.
It implies;
1² = a²+b²
1 = a²+(√(2)a)²
1 = a²+2a²
a² = ⅓...
Let the side length of the ascribed regular pentagon be 2 units.
a = ⅕*180(5-2)
a = 108°
a is the single interior angle of the ascribed regular pentagon.
b² = 2²+1²-2*1*2cos108
b = 2.49721...
