By OnlineEdumath   |  21st July, 2026
Calculating x, the radius of the big quarter circle.a = ½(90)a = 45°a is half angle DBE.b = ½(180-45)b = 67.5°b is angle BDF.c = (x+1) units.c is AB.d = (x-1) units.Therefore, x is;tan67.5 = (x+1)/(...
By OnlineEdumath   |  20th July, 2026
Calculating Area Pink Regular Hexagon.Let a be the side length of the pink regular hexagon.Let b be the side length of the red regular hexagon with area 6 square units.A nice analysis of the composit...
By OnlineEdumath   |  19th July, 2026
Calculating Area Triangle APC, Area Yellow.Let x be AP = CPa = ½(10)a = 5 cm.a is the mid-point of AC.Notice.Since angle BAP = angle CAP is equal and length AP = length CP.It implies;AB = 5 cm.cosb =...
By OnlineEdumath   |  18th July, 2026
Calculating the required inscribed orange triangle area.a = ½(3)a = 1.5 units.a is the radius of the inscribed circle.tanb = 3/4b = atan(3/4)°tan(atan(3/4)) = c/1.53/4 = c/1.54c = 4.5c = 1.125 units....
By OnlineEdumath   |  17th July, 2026
Calculating Area ADCB, a Cylic Quadrilateral.a = ½(45)a = 22.5°a is angle CBD.b = a+45b = 22.5+45b = 67.5°b is angle ABE.sin67.5 = 10/cc = 10.8239220029 units.c is AB = AD.d² = 2c²d² = 2*10.823922002...
By OnlineEdumath   |  16th July, 2026
Calculating Alpha.Let it be x.Let a be the radius of the ascribed quarter circle.b = (a-√(2)) units.c = (a-2√(2)) units.Calculating a.a ~ (a-√(2))(a-2√(2)) ~ √(2) Cross Multiply.√(2)a = a²-2√(2)a-√(2...
By OnlineEdumath   |  16th July, 2026
Calculating r, radius of the inscribed circle.Notice.Angle ABD = ¼(60)Angle ABD = 15°tan30 = r/a1/√(3) = r/aa = √(3)r units.b = 2ab = 2√(3)r units.b is the side length of the ascribed regular triangl...
By OnlineEdumath   |  16th July, 2026
Calculating the green area x.Notice.5 units is the height of the green triangle and 15 units is the base.It implies, area green (x) is;½*5*15= ½(75)= 37.5 square units.
By OnlineEdumath   |  15th July, 2026
Calculating theta.Let it be x.Let angle BAD be a.b+a+30 = 180b = (150-a)°b is angle ADB.It implies;x+b = 180x+150-a = 180x = (30+a)°Again, a is theta.c = 180-100c = 80°c is the supplementary angle of...
By OnlineEdumath   |  15th July, 2026
Calculating Angle x.a = 90-40a = 50°a is angle EOQ.b = ½(180-a)b = ½(180-50)b = ½(130)b = 65°Therefore the required angle, x is;x = ½(90)+bx = 45+65x = 110°
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