By OnlineEdumath   |  16th July, 2026
Calculating Alpha.Let it be x.Let a be the radius of the ascribed quarter circle.b = (a-√(2)) units.c = (a-2√(2)) units.Calculating a.a ~ (a-√(2))(a-2√(2)) ~ √(2) Cross Multiply.√(2)a = a²-2√(2)a-√(2...
By OnlineEdumath   |  16th July, 2026
Calculating r, radius of the inscribed circle.Notice.Angle ABD = ¼(60)Angle ABD = 15°tan30 = r/a1/√(3) = r/aa = √(3)r units.b = 2ab = 2√(3)r units.b is the side length of the ascribed regular triangl...
By OnlineEdumath   |  16th July, 2026
Calculating the green area x.Notice.5 units is the height of the green triangle and 15 units is the base.It implies, area green (x) is;½*5*15= ½(75)= 37.5 square units.
By OnlineEdumath   |  15th July, 2026
Calculating theta.Let it be x.Let angle BAD be a.b+a+30 = 180b = (150-a)°b is angle ADB.It implies;x+b = 180x+150-a = 180x = (30+a)°Again, a is theta.c = 180-100c = 80°c is the supplementary angle of...
By OnlineEdumath   |  15th July, 2026
Calculating Angle x.a = 90-40a = 50°a is angle EOQ.b = ½(180-a)b = ½(180-50)b = ½(130)b = 65°Therefore the required angle, x is;x = ½(90)+bx = 45+65x = 110°
By OnlineEdumath   |  14th July, 2026
Calculating x.a = ½(180-60)a = ½(120)a = 60°a is angle DCO = angle COD = angle CDO, making triangle CDO equilateral. b = a-45b = 60-45b = 15°b is angle ECO = angle CEO.c = 180-2bc = 180-2(15)c = 150°...
By OnlineEdumath   |  14th July, 2026
Calculating Area Blue.a = 8-2a = 6 units.cosb = 6/8b = acos(3/4)°Therefore, blue area is;½*8*8sin(acos(3/4))=½*8*8*0.66143782777= 32*0.66143782777= 21.1660104886 square units.
By OnlineEdumath   |  14th July, 2026
Calculating x.a = (2+x) units. Is the radius of the half circle.b = 2+ab = 2+2+xb = (4+x) units.Therefore, length x is;a²+a² = b²(2+x)²+(2+x)² = (4+x)²2(4+4x+x²) = 16+8x+x²8+8x+2x² = 16+8x+x²8+2x² =...
By OnlineEdumath   |  13th July, 2026
Calculating Shaded Area.Notice.ABCD is a square.Let x be the side length of the square.a²+x² = 40²a = √(1600-x²) units.a is BF.b = x-ab = (x-√(1600-x²)) units.b is AF.It implies;cosc = x/40 --- (1).c...
By OnlineEdumath   |  12th July, 2026
Calculating L, length of the ascribed regular pentagon.a = (x+8) units.b = ⅕(180(5-2))b = ⅕*180*3b = 108°b is the single interior angle of the regular pentagon.c = 180-bc = 180-108c = 72°Calculating...
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