Area R is;Area sector with radius 8 cm and angle 20.16632290743° - Area triangle with height 8 cm and base (4.2sin 20.16632290743) cm= ( 20.16632290743 *64π÷360) - (½*8*4.2sin 20.16632290743)= 11.26...
Shaded area is;Area sector with radius 10 cm and angle 60°(100π*60)/360= (100π)/6= ⅓(50π) cm²
Sir Mike Ambrose is the author of the question.Let the side length of the regular pentagon be 1 unit.tan36 = a/0.5a = 0.363271264 unit.b² = 0.363271264²+0.5²b = 0.61803398875 unit.tan72 = c/0.5c = 1....
Sir Mike Ambrose is the author of the question.Calculating Area Blue.The radius of the inscribed small circle is 2 units.a = 2atan(⅓)°b = 2atan(⅕)°c = 180-a-bc = (180-2atan(⅓)-2atan(⅕))°sin(2atan(⅓))...
Area coloured regions is;Half the area of the ascribed square.½(2*2)= 2 square units.
Calculating The Shaded Area.Let x be the three equal lengths.a²+x² = 5²a = √(25-x²) units.a is the height of the ascribed right-angled triangle.Calculating xa ~ x2x ~ xCross Multiply.ax = 2x²2x = a....
Sir Mike Ambrose is the author of the question.Let AC = 2 units.Therefore;AB = ⅖ unit.BC = (8/5) unit.It implies;Area Blue is;Area triangle with height ⅖ unit and base 2sin120 units + Area triangle w...
Sir Mike Ambrose is the author of the question.Let AC be 1 unit.Area smaller pentagon is;½(5)*(1/(2tan(36)))= 1.72047740059 square units.a² = 1²+0.5²-cos108a = 1.24860602048 units.Where a is CD.(1.24...
Calculating Green Area.Let x be the equal inscribed angles.Let a be the radius of the sector.It implies;b² = 2a²-2a²cosx --- (1).b² = 6²+9²-2*6*9cosxb² = 117-108cosx --- (2).Equating (1) and (2).2a²-...
Sir Mike Ambrose is the author of the question. Area R is;Area triangle with height 4 cm and base (4tan52.5) cm - Area sector with angle 52.5° and radius 4 cm.= ½*4(4tan52.5) - (52.5*4*4π)/360= 8tan5...
