Sir Mike Ambrose is the author of the question.Radius, r of the inscribed circle is;r = (3-√(3)) cmTherefore;Area purple exactly in square cm is;Area trapezium with parallel sides (3-√(3)) cm and 4 c...
Sir Mike Ambrose is the author of the question. P(2, (16√(5)/5))Gradient of the curve at the tangent is;= 24/5√(5)Therefore;Gradient of the curve at the normal is;= -5√(5)/24It implies;Coordinate Q i...
Calculating x, chord of the circle..a² = 1 square units.a = 1 unit.a is the side length of the 3 inscribed equal squares.b = 1+½(1)+yb = (1.5+y) units.c = 1+1c = 2 units.d² = 2²+0.5²d² = 4+0.25d = √(...
Sir Mike Ambrose is the author of the question.AB exactly is;= 16tan(3acos(8/9)) - 2√(17)= 2(8tan(3acos(8/9))-√(17)) cm.= 102.760478669 cm.
Sir Mike Ambrose is the author of the question. Equation of the curve is;y = ¼(x²)+4Shaded area exactly in square units is;Area triangle with height 8 units and base 4 units - Area sector with radius...
Sir Mike Ambrose is the author of the question.Calculating Area Orange.Area orange exactly in square units is;Area triangle with height ⅓(10√(2)) units and base 5sin45 units - Area triangle with heig...
Sir Mike Ambrose is the author of the question.Let the side of the regular pentagon be 1 unit.a = 360-2(108)-90a = 54°tan72 = b/0.5b = 1.53884176859 units.tan54 = 1.53884176859/cc = 1.11803398875 uni...
Sir Mike Ambrose is the author of the question.Let the side of the square be 2 units.Therefore;a = 3√(5)/5 units.b = 2√(5)/5 units.c = √(5)/5 units.d = 2√(5)/5 unitsIt implies;a² = b² + c² + d² is;(3...
Sir Mike Ambrose is the author of the question.Area yellow in square units to 2 decimal places is;Area triangle with height (tan70+tan(450/7)) units and base (tan70+tan54)sin80 units.= ½(tan70+tan(45...
Sir Mike Ambrose is the author of the question.At x = 0, y = 2.At y = 16, x = 1.Gradient of the curve at x = 1 or at the tangent is;dy/dx = 3In2*2^(3x+1)For x = 1dy/dx = 48In2Therefore coordinate Q i...
