Calculating Area of the yellow Hexagon.Let x be the side length of the hexagon.a²+3² = x²a = √(x²-9) cm.b² = 2x²-2x²cos120b = √(3x²)b = √(3)x cm.It implies;Calculating x.sinc = √(x²-9)/x --- (1).sinc...
Calculating the blue shaded area.Let x be the radius of the half circle.a = (x-2) cm.Calculating x.It implies;x² = 4²+(x-2)²x² = 16+x²-4x+44x = 20x = 5 cm.Again, x is the radius of the half circle.O...
Sir Mike Ambrose is the author of the question.a² = 10²+16²-2*10*16cos120a = 2√(129) units.Where a is length AC.(3√(129)/sin120) = (16/sinb)b = 37.58908946897°c = 90-bc = 52.41091053103° d = 60-bd =...
Calculating x.8 = 2³It implies;2^(3x)+2^(x) =130Let 2^(x) = p.p³+p = 130130 = 1*2*5*13It implies;p = 5Calculating x.Recall.p = 2^(x) And p = 55 = 2^(x)log5 = xlog2x = (log5)/(log2)x = 2.32192809489
Sir Mike Ambrose is the author of the question.The side of area green, inscribed square is;Let it be x.Therefore;1.11496246101x + 0.82101781219x = 27.36726040631.9359802732x = 27.3672604063x = 14.136...
Sir Mike Ambrose is the author of the question.Let the two equal marked lengths of triangle ABC be 2 units.Therefore;Area triangle ABC is;Area triangle with height 5.75877048314 units and base (5.758...
Sir Mike Ambrose is the author of the question.Point P coordinate is;P(4, -3)Point R coordinate is;R(0, ⅓(37))Point Q (maximum turning point) coordinate is;Q((-3√(259)/14), (4√(259)/7))Therefore;Area...
Sir Mike Ambrose is the author of the question.The side of the square is;6.065425 cmTherefore;Area red in cm² to 2 d. p is;Area triangle with height (2.1tan29.11) cm and base 2.1 cm= 0.5*2.1(2.1tan29...
Sir Mike Ambrose is the author of the question.Calculating Area Green.Area green exactly in cm² is;Area ABCD - Area trapezoid with parallel sides (9-2√(3)) cm and (24√(3)-39) cm, and height 6 cm.= (5...
Calculating FM ÷ ML.Let 2 units be the side length of square.Calculating FM.tana = 2/1a = atan(2)°a is angle AFB.Let b, be the radius of the small inscribed circle.c = (1-b) units.Therefore;Calculati...
