By OnlineEdumath   |  12th April, 2026
Calculating The Shaded Area.Let x be the three equal lengths.a²+x² = 5²a = √(25-x²) units.a is the height of the ascribed right-angled triangle.Calculating xa ~ x2x ~ xCross Multiply.ax = 2x²2x = a....
By OnlineEdumath   |  11th April, 2026
Sir Mike Ambrose is the author of the question.Let AC = 2 units.Therefore;AB = ⅖ unit.BC = (8/5) unit.It implies;Area Blue is;Area triangle with height ⅖ unit and base 2sin120 units + Area triangle w...
By OnlineEdumath   |  9th April, 2026
Sir Mike Ambrose is the author of the question.Let AC be 1 unit.Area smaller pentagon is;½(5)*(1/(2tan(36)))= 1.72047740059 square units.a² = 1²+0.5²-cos108a = 1.24860602048 units.Where a is CD.(1.24...
By OnlineEdumath   |  8th April, 2026
Calculating Green Area.Let x be the equal inscribed angles.Let a be the radius of the sector.It implies;b² = 2a²-2a²cosx --- (1).b² = 6²+9²-2*6*9cosxb² = 117-108cosx --- (2).Equating (1) and (2).2a²-...
By OnlineEdumath   |  7th April, 2026
Sir Mike Ambrose is the author of the question. Area R is;Area triangle with height 4 cm and base (4tan52.5) cm - Area sector with angle 52.5° and radius 4 cm.= ½*4(4tan52.5) - (52.5*4*4π)/360= 8tan5...
By OnlineEdumath   |  6th April, 2026
Calculating Area Yellow.Notice.The ascribed quadrilateral is a square with side 6 units.a² = x²+3²a = √(x²+9) units.b = 2ab = 2√(x²+9) units.c = (6+x) units.Notice.b = cTherefore, calculating x.2√(x²...
By OnlineEdumath   |  5th April, 2026
Calculating x, chord of the circle..a² = 1 square units.a = 1 unit.a is the side length of the 3 inscribed equal squares.b = 1+½(1)+yb = (1.5+y) units.c = 1+1c = 2 units.d² = 2²+0.5²d² = 4+0.25d = √(...
By OnlineEdumath   |  4th April, 2026
Blue area is;Area sector with radius 12 units and angle 30° - Area sector with radius 6 units and angle 60° - Area triangle with height 6 units and base 6sin120 units.= (30π*12²/360) - (60π*6²/360) -...
By OnlineEdumath   |  3rd April, 2026
Calculating Length CF.a² = 4²+4²-2*4*4cos150a = 7.72740661031 cm.Where a is BE.b = angle ABE = ½(180-150)b = 15°c = angle AFE = 180-45-15c = 120°(4/sin120) = (d/sin45)d = 3.26598632371 cm.Where d is...
By OnlineEdumath   |  2nd April, 2026
Calculating Length FG.tan15 = a/4a = 1.07179676972 cm.Where a is AD.b² = 1.07179676972²+4²b = 4.14110472164 cm.Where b is DF.c = 4-1.07179676972c = 2.92820323028 cm.Where c is CD.sin60 = d/2.92820323...
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