By OnlineEdumath   |  24th July, 2025
Calculating Red Area. Let AB = CD = x. Let AD = BC = y. ½*xa = 10 a = 20/x units. a is BQ. ½*xb = 6 b = 12/x units. b is the horizontal height of area 6 (area triangle APB). c = y-b c = y-(12/x...
By OnlineEdumath   |  23rd July, 2025
Calculating area ABCD. Let x be the radius of the inscribed circle. a = ½(16) a = 8 units. x² = 8²+a² a = √(x²-64) units. b = ½(25) units. It implies; x ~ 8 ½(25) ~ x Cross Multiply. x² = 10...
By OnlineEdumath   |  23rd July, 2025
Calculating Area Yellow. ½*a²sin60 = 24 √(3)a² = 24*4 a² = 96/√(3) a = √(96/√(3)) a = 7.44483887282 units.  a is the radius of the circle. b = a-x b = (7.44483887282-x) units. Calcul...
By OnlineEdumath   |  23rd July, 2025
Sir Mike Ambrose is the author of the question. Let the single side length of the square be 2 units. Area square is; 2² = 4 square units. Calculating green area. It will be; Area square of side...
By OnlineEdumath   |  22nd July, 2025
Let the single side length of the ascribed square be 2 units. Calculating yellow area . It is; Area sector with radius 2 units and angle (90-2tan–¹(½))°). = (90-2tan–¹(½))x4π÷360 = 1.287...
By OnlineEdumath   |  22nd July, 2025
Calculating Area Red. a = (1+x) units. a is the diameter of the circle. b = ½(a) b = ½(1+x) units. b is the radius of the circle. c = ½(1-x) units. Calculating x. (½(1+x))² = 2(½(1-x))² ¼(1+2x+...
By OnlineEdumath   |  21st July, 2025
Calculating x. Let r be the radius of the inscribed green circle. Let R be the radius of the ascribed quarter circle. (R-r)² = r²+5² --- (1). (R-r)²+5² = a² --- (2). a² = x²+r² --- (3...
By OnlineEdumath   |  21st July, 2025
Calculating the area of the ascribed regular octagon. Let the equal longest length of the both inscribed yellow triangles be x. a = ⅛*180(8-2)) a = ⅛(180*6) a = ½(45*6) a = 135° a is the single in...
By OnlineEdumath   |  21st July, 2025
Calculating Length AB. Let AB = (a+7+b) units. Calculating a and b. c = (7+b) units. Therefore; a(7+b) = 60 a = 60/(7+b) --- (1). Again. d = (a+7) units. Therefore; b(a+...
By OnlineEdumath   |  21st July, 2025
Shaded Area is; Area circle with radius 4 cm - 4(area quarter circle with radius 4 cm - area isosceles right-angled triangle with equal adjacent lengths 4 cm). = π*4²-4(¼(4²π)-½(4²)) = 16π-4(4π-8...
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