Area Coloured Region is;
Area triangle with height and base 10 units - Area triangle with height and base 3√(2) units - Area triangle with height 5 units and base 7√(2)sin45 units
= ½*10*10)...
Calculating the area of the inscribed blue circle.
a = ½(14+6)
a = 10 units.
a is the radius of the ascribed semi circle.
b = a-6
b = 4 units.
c²+4² = d²
c is the radius of the inscrib...
a² = 30²+40²-2*30*40cos150
a = 67.6643256752 units.
(67.6643256752/sin(150)) = (30/sinb)
b = 12.807876266°
c = 83-b
c = 70.192123734°
It implies, the required length x is;
x² = 50²+6...
c²+12² = b²
c = √(b²-144) units.
For b = 15 units.
c = √(15²-144
c = 9 units.
tana = 12/9
a = atan(4/3)°
cos(atan(4/3)) = 12/d
⅗ = 12/d
d = 20 units.
e = 24-d
e = 4 units.
It im...
Let the single side length of the regular pentagon be 1 unit.
Therefore;
Area blue is;
½(sin108) square unit.
Area red is;
(1-cos36)sin108 square unit.
Therefore;
Area blue : Area...
Coloured region is;
Area triangle with height 6√(2) units and base 4.5sin45 units + Area triangle with height 3 units and base 5.65685424949sin45 units + Area triangle with height 1.5 units and...
Sir Mike Ambrose is the author of the question.
Area Red is;
Area triangle with height 2 units and base 2sin(180-2ata(¾)) units.
= ½*2*2sin(180-2ata(¾))
= 2sin(180-2ata(¾))
= 48/25 squar...
Calculating Shaded Black Area.
a² = 9²+12²
a = √(81+144)
a = 15 units.
a is the hypotenuse of the ascribed right-angled triangle.
b = ½(a)
b = 7.5 units.
tanc = 9/12
c = atan(3/4)°...
a = ⅑*180(9-2)
a = 140°
a is the single interior angle of the regular nonagon.
b = ½(180-140)
b = 20°
c = 140-20
c = 120°
d = ½((180(5-2))-3*140)
d = ½(540-420)
d = ½(120)
d = 60°...
