a = ½(12) cm.
a = 6 cm.
b = ⅙*180(6-2)
b = 120°
b is the single interior angle of the regular hexagon.
c² = 6²+12²-2*6*12cos120
c = 15.8745078664 cm.
c = 6√(7) cm.
c = 15.8745078664 cm....
a²+8² = 10²
a = 6 units.
a is AC,the height of triangle ABC.
Calculating b, radius of the inscribed circle.
10b+8b+6b = 8*6
24b = 48
b = 2 units.
c = 6-b
c = 4 units.
d = 8-b
d =...
Sir Mike Ambrose is the author of the question.
The equation of the curve is;
y = (8/(x-3)) + 2
Area blue is;
Area trapezoid with two parallel side 5 units and 6 units, and height 2 units -...
Blue area is;
2(area circle with radius 2 cm) + Area square with single side length 4 cm.
= 2(4π) + 16
= 8π + 16
= 8(π+2) cm²
Notice;
The single side length of the ascribed regular hexagon, the inscribed regular pentagon, the inscribed square, and the inscribed equilateral triangle are equal.
It is 39 units.
Ther...
Let the side length of the regular hexagon be 1 unit.
It implies;
x+y = 1
a = ⅙*180(6-2)
a = 120°
a is the single interior angle of the regular hexagon.
b = 360-2a-45
b = 360-285
b...
Let the side length of the inscribed square be a.
b² = 2a²
b = √(2)a cm.
b is the diagonal of the inscribed square.
c²+a² = (4+6)²
c = √(100-a²) cm.
d = c-a
d = (√(100-a²)-a) cm.
14...
a = (4-b) m.
Calculating b.
3 - 5
b - (4-b)
Cross Multiply.
3(4-b) = 5b
12-3b = 5b
8b = 12
b = 1.5 m.
Recall.
a = (4-b)
And b = 1.5 m.
a= 4-1.5
a= 2.5 m.
c = √(3²+1.5²)+...
Let the side length of the regular octagon be 1 unit.
a = ⅛*180(8-2)
a = 135°
a is the side length of the regular octagon.
2b² = 1²
b = √(1/2) units.
b = ½√(2) units.
c = 1+b
c = (1+½...
Sir Mike Ambrose is the author of the question.
Area Blue exactly in cm² decimal form is;
Area trapezoid with two parallel side (7√(2)+14) cm and 15.3137084989 cm, and height 18.4852813742 cm....
