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A Kind And humble Call For Your Donation/Contribution/Support/Assistance Financially To Assist Us Purchase Website Subscription Plan

https://onlineedumath.com/update/a-kind-and-humble-call-for-your-donationcontribut/3215982

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“Hello! As a valued supporter of our cause, we kindly, nicely ask for your donation/contribution/support/assistance financially to help us purchase subscription plan to keep our website active as we continue making a positive impact. Your donation will go a long way in supporting our cause and efforts.” Our USD MiniPay Wallet Details. Name: Ephivbotor Ogheneovo Daniel  Phone/Wallet Number: +2349076614992 Our Naira (Nigeria Currency) Account Details. Holder Name: Ogheneovo Daniel Ephi...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3219517

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Calculating Area Blue Inscribed Circle. Let it's radius be x. a = ½(16)+x a = (8+x) units. b = (8-x) units. c = (16-x) units. It implies; d²+x² = (16-x)² d² = 256-32x+x²-x² d = √(256-32x) units. Calculating x. √(256-32x)²+(8-x)² = (8+x)² 256-32x+64-16x+x² = 64+16x+x² 256-32x+64-16x = 64+16x 256 = 64x 32 = 8x x = 4 units. Therefore, area inscribed blue circle is; πx² = π(4²) = 16π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3219513

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Sir Mike Ambrose is the author of the question. Calculating Exactly Green Area. Let x be the side length of each of the three inscribed congruent squares. a² = 2x² a = √(2)x a is the diagonal of the squares. b = 45-30 b = 15° cos15 = c/(√(2)x) c = ½(√(3)+1)x units. c = 1.36602540378x units. d = c+x d = ½(1+√(3))x+x d = ½(3+√(3))x units. d is the height of the ascribed regular hexagon. e² = 2²+2²-2*2*2cos120 e = √(8+4) e = 2√(3) units. e = d. Calculating x....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3218401

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Calculating FB. a = 8+9 a = 17 units. b = 9-8 b = 1 unit. c² = 17²+1² c = √(290) units. c = 17.0293863659 units. c is DE. 2d² = c² 2d² = √(290)² d² = 145 d = √(145) units. d = 12.0415945788 units. d is the radius of the ascribed half circle. Calculating Length FB. Let it be e. e²+1² = d² e² = √(145)²-1² e² = 145-1 e² = 144 e = See √(144) units. e = 12 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3218392

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Calculating The Required Shaded Area. a = ¼(2R) a = ¼(6) a = 1.5 units. b² = 2(3)² b = 3√(2) units. c² = 1.5²+3²-2*3*1.5cos150 c = ½(3√(7)) units. c = 4.36396936676 units. d² = (3√(2))²+1.5²-2*1.5*3√(2)cos45 d = ½(3√(5)) units. d = 3.35410196625 units. 3² = 3.35410196625²+4.36396936676²-2*4.36396936676*3.35410196625cose 29.2743964674cose = 21.294228634 e = acos(21.294228634/29.2743964674) e = 43.331039462° Required Shaded Area is; (0.5*4.36396936676*3.35410196...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3216951

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Calculating Shaded Area. a² = 11²+8² a = √(185) units. b²+4² = a² b² = 185-16 b = √(169) b = 13 units. b is the length of the equal rectangles. Shaded Area is; (13*8)-½(11*8)-2(½(13*4))+½(2+13)*8 = 104-44-52+60 = 164-96 = 68 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3216933

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Calculating Shaded Blue Area. a²+(0.5*6)² = 5² a² = 25-9 a = √(16) a = 4 cm. It is; Area isosceles right-angled triangle with equal sides 6 cm+Area trapezoid with parallel lengths 3 cm and 6 cm, and height 4 cm. = ½(6*6)+½(3+6)*4 = ½(36)+½(36) = 18+18 = 36 cm²

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3216919

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Calculating FB. Let a be OC = OE = CE. b = (a+16) units. b is the radius of the ascribed half circle (OD = OA). c = b-5 c = (a+16)-5 c = (a+11) units. c is OB. d = c+a d = (a+11)+a d = (2a+11) units. d is BC. Calculating a. e² = (a+11)²+a²-2a(a+11)cos120 e² = 2a²+22a+121+a²+11a e² = 3a²+33a+121 --- (1). e² = (a+11)²+(a+16)²-2(a+11)(a+16)cos60 e² = a²+22a+121+a²+32a+256-((a+11)(a+16)) e² = 2a²+54a+377-(a²+27a+176) e² = a²+27a+201 --- (2). Calculating a. E...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3215742

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Sir Mike Ambrose is the author of the question. Calculating Area yellow ÷ Area BDE. Area BDE is; Area triangle with side 2 units and 3 units, and angle 120° = ¼(6√(3)) = ½(3√(3)) square units. = 2.59807621135 square units. Area yellow is; Area triangle with side 2 units and 3 units, and angle 120° - Area triangle with side 2 units and 1.74355957742 units, and angle (60-atan(3√(3)/7))° + Area triangle with side 1.30766968306 units and 3 units, and angle at an(3√(3)/7)° -...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3215510

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Calculating inscribed regular hexagon shaded area ÷ Ascribed regular hexagon area. Let the side length of the inscribed shaded regular hexagon be 1 unit. a² = 2-2cos120 a = √(2) units. Shaded inscribed area is  2(½*1*1sin120)+(1*√(3)) = ½√(3)+√(3) = ½(3√(3)) square units. = 2.59807621135 square units. Let x be the side length of the ascribed regular hexagon. b = ½(x) units. Calculating x. 2² = x²+(½(x))²-2*x*½(x)cos120 4 = x²+¼(x²)+½(x²) 16 = 4x²+x²+2x² 7x² = 16 x...
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