Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3116021

Notice. The angle formed at the meet point (vertex) of length 4 units and x units is equal the angle formed at the meet point (vertex) 9 units and x units. Therefore, as a result, two similar plane shapes, quadrilaterals are observed. Calculating x. x ~ 9 4 ~ x Cross Multiply. x² = (9*4) x = √(36) x = 6 units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3115944

Sir Mike Ambrose is the author of the question. Let the square side be 1 unit. Therefore; Area B is; Area triangle with height 1 unit and base sin(53.13010235416) units - Area triangle with height 1 unit and base (0.71428571429sin(53.13010235416)) units. = ½*1(sin(53.13010235416)) - ½*1*(0.71428571429sin(53.13010235416)) = 0.4 - 0.28571428572 = 0.11428571428 square units. Area A is; Area triangle with height 1 unit and base 0.5 units + Area triangle with height 0....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3115937

Calculating Area Blue. (2/sin120) = (1/sina) a = 25.6589062733° b = 180-120-a b = 60-25.6589062733 b = 34.3410937267° Therefore, shaded blue area is; Area sector with radius 2 units and angle 34.3410937267° - Area triangle with height 2 units and base sin34.3410937267 units. = (34.3410937267π*2*2/360)-(½*2sin34.3410937267) = 1.19873030853-0.56411839885 = 0.63461190968 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3115931

a = ½(4+6) a = 5 units. a is radius. 10² = x²+b² b = √(100-x²) units. c = 10-½(4) c = 8 units. x² = c²+d² x² = 8²+d² d = √(x²-64) units. Calculating x. Therefore; 8 ~ √(x²-64) √(x²-64) ~ 2 Cross Multiply. √(x²-64)² = 16 x²-64 = 16 x² = 80 x = √(80) x = 4√(5) units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3115438

Notice. r, radius of the ascribed quarter circle is (25/√(2)) units. r = ½(25√(2)) units. (AD)² = 2(½(25√(2)))² (AD)² = 2*¼*625*2 AD = √(625) AD = 25 units. It implies; AB+BC+CD = AD 10+BC+4 = 25 BC = 25-14 BC = 11 units. a = 25-2(4) a = 17 units. b = ½(a) b = ½(17) units. sinc = ½(17)/(½(25√(2))) c = asin(17√(2)/50)° c = 28.7397952917° d = 2c d = 2asin(17√(2)/50)° e = ½(90-d) e = (45-asin(17√(2)/50))° f = ½(180-e) f = ½(180-45+asin(17√(2)/50)) f = (0.5(135+asin(17√(2)/50)))° g = f...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3114959

Let FC=x. Let CE=y Therefore; 5+x=y+4 x=y-1 ------- (1). Notice; Triangle AEF is similar to triangleEFC. It implies; 5+x=y 4=x, cross multiply. x²+5x=4y ----- (2). Substituting (1) in (2). (y-1)²+5(y-1)=4y y²-2y+1+5y-5=4y y²-y-4=0 (y-½)²=4+(¼) y=½±½√(17) Therefore; y≠½-½√(17) y=½+½√(17) y=½(√(17)+1) Therefore; x will be; At (1). x=y-1, and y=½(√(17)+1) x=½(√(17)+1)-1 x=½(√(17)-1) Therefore length EF will be; √(y²+...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3114832

a = (r+9) units. b = (r-9) units. a² = b²+c² (r+9)² = (r-9)²+c² c² = r²+18r+81-r²+18r-81 c² = 36r c = 6√(r) units. d = (r+4) units. e = (r-4) units. f²+e² = d² f² = r²+8r+16-r²+8r-16 f = 16r f = 4√(r) units. It implies; g = c-f g = 6√(r)-4√(r) g = 2√(r) units. h = 2r-9-4 h = 2r-13 h = (2r-13) units. j² = h²+g² j² = (2r-13)²+(2√(r))² j² = 4r²-52r+169+4r j² = 4r²-48r+169 j = √(4r²-48r+169) units. Therefore r, radius of the inscribed h...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3114668

Sir Mike Ambrose is the author of the question. Let the side of the regular hexagon be 1 unit. Therefore; Length Blue is; √(2-2cos108) = 1.61803398875 unit. Length Red is; √(1²+(0.48469364308)²-(2*1*0.48469364308cos168)) = 1.4775424785 unit. It implies; Length Red ÷ Length Blue to 2 decimal places is; 1.4775424785 ÷ 1.61803398875 = 0.91317147153 ≈ 0.91

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3114658

a = ⅕*180(5-2) a = 108° a is the single interior angle of the regular pentagon. b = 180-a-42 b = 180-150 b = 30° (12/sin108) = (c/sin30) c = 6.30877334543 cm. c is the side length of the regular pentagon. d² = 2(6.30877334543)²-2(6.30877334543)²cos108 d = 10.2078097002 cm. e = 108-½(180-108) e = 108-36 e = 72° Therefore, area regular pentagon is; 2(0.5*6.30877334543²cos(108))+(0.5*6.30877334543*10.2078097002sin(72) = 37.8526400726+30.6234291006 = 68.4760691732...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3114293

Let r be the radius of the half circle. a²+2² = r² a = √(r²-4) units. b = 2a b = 2√(r²-4) units. c = (r-2) units. Calculating r. √(r²-4) ~ 2√(r²-4) (r-2) ~ 9 Cross Multiply. 9√(r²-4) = (2r-4)√(r²-4) 9 = 2r-4 2r = 13 r = ½(13) units. r = 6.5 units. Recall. b = 2√(r²-4) units. And r = ½(13) units. b = 2√((½(13))²-4) b = 2√(¼(169-16)) b = 2√(¼(153)) b = √(153) units. b = 3√(17) units. tand = 9/(3√(17)) d = atan(3/√(17))° d = 36.0398934303° e =...

You Searched for "update"

177 result found.

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

OnlineEdumath

Socials

Facebook Page

Quick Links

Reach Us

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?

Search

You Searched for "update"

177 result found.

Subscribe to our mailing list for latest updates.

Safety and Abuse Reporting

Thanks for being awesome!

Are you sure you want to report abuse against this website?