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A Kind And humble Call For Your Donation/Contribution/Support/Assistance Financially To Assist Us Purchase Website Subscription Plan

https://onlineedumath.com/update/a-kind-and-humble-call-for-your-donationcontribut/3215982

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“Hello! As a valued supporter of our cause, we kindly, nicely ask for your donation/contribution/support/assistance financially to help us purchase subscription plan to keep our website active as we continue making a positive impact. Your donation will go a long way in supporting our cause and efforts.” Our USD MiniPay Wallet Details. Name: Ephivbotor Ogheneovo Daniel  Phone/Wallet Number: +2349076614992 Our Naira (Nigeria Currency) Account Details. Holder Name: Ogheneovo Daniel Ephi...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3381588

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Sir Mike Ambrose is the author of the question. Calculating Area Orange, exactly in square cm. Let AB be x. Therefore BC = 2x cm. Calculating x. Yellow area + Area triangle with height 2x cm and base ½(3x)sin60 cm = Area trapezoid with two parallel side ½(3x) cm and 2x cm, and height ½(3√(3)x) cm. Therefore; 30√(3)+¾*√(3)x² = (21√(3)x²)/8 30+¾x² = (21x²/8)  240+6x² = 21x² 15x² = 240 Therefore; x = 4 cm. Calculating Area Orange, exactly in square cm decimal...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3380818

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Sir Mike Ambrose is the author of the question. Calculating Blue Area. Area blue exactly in cm² decimal form is; Area trapezoid with two parallel sides 12 units and (12-16tan15) units, and height 16 units - Area triangle with height (12-16tan15) units and base 4 units - Area triangle with height and base 12 units each - Area triangle with height 8√(2) units and base (8-8tan15)sin45 units. = ½*16(12+12-16tan15) - ½*4(12-16tan15) - ½(12²) - ½*8√(2)*(8-8tan15)sin45 = 157.702503369 -...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3380814

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Calculating x, the last term of the series. a = 7, first term. d = 10-7 = 13-10 = 3, common difference. S = 282, sum of the series. It implies, calculating n, number of terms. S = ½(n)(2a+d(n-1)) Therefore; 282 = 0.5n(14+3(n-1)) 564 = n(11+3n) 3n²+11n-564 = 0 (n+(11/6))² = (564/3)+(11/6)² (n+(11/6))² = 6889/36 n = -(11/6)±√(6889/36) n = -(11/6)±(83/6) It implies; n ≠ -(11/6)-(83/6) n = -(11/6)+(83/6) n = 72/6 n = 12 Calculating x, Las Term....

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3379579

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Calculating Blue Area Total. tana = 10/5 a = atan(2)° b = 180-a b = (180-atan(2))° (10/sin(180-atan(2))) = (5/sinc) c = 26.5650511771° d = 180-(180-atan(2))-26.5650511771 d = 36.8698976458° It implies; Area Blue (1) is; (36.8698976458π*10*10/360)-(0.5*10*5sin36.8698976458) = 32.1750554396-15 = 17.1750554396 cm² e = (½*10*5)-Area Blue (1). e = 25-17.1750554396 e = 7.8249445604 cm² It implies; Area Blue (2) is; 10²-(¼*10*10π)-e = 100-25π-7.8249445...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3378640

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Calculating the blue shaded area. Let x be the radius of the half circle. a = (x-2) cm. Calculating x. It implies; x² = 4²+(x-2)² x² = 16+x²-4x+4 4x = 20 x = 5 cm. Again, x is the radius of the half circle. Or 4*4 = 2*(x+(x-2)) 16 = 2(2x-2) 8 = 2x-2 2x = 10 x = 5 cm. Again, x is the radius of the half circle. Recall. a = (x-2) cm. And x = 5 cm. a = 5-2 a = 3 cm. tanb = 4/3 b = atan(4/3)° Therefore, area shaded blue is; Area sector with radius...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3378514

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Sir Mike Ambrose is the author of the question. Calculating Area Green ÷ Area Yellow to 3 d. p. Let the side length of the regular pentagon be 2 units. Therefore the angle theta is; asin(2sin42÷1.65418183057) = 54° Area green is; Area triangle with height (1/cos54) units and base 2.45859333557sin12 units - Area triangle with height 2cos54 units and base 2cos54*tan12 units  = (0.5*2.45859333557sin12*(1/cos54)) - (0.5*2cos54*2cos54*tan12) = 0.43482742672 - 0.14687297185...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3377735

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Calculating x. 8 = 2³ It implies; 2^(3x)+2^(x) =130 Let 2^(x) = p. p³+p = 130 130 = 1*2*5*13 It implies; p = 5 Calculating x. Recall. p = 2^(x)  And p = 5 5 = 2^(x) log5 = xlog2 x = (log5)/(log2) x = 2.32192809489

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3377563

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Calculating angle x. Let 1 unit be the side length of the square. Let y be the equal red lengths. It implies; a = (1-y) units. b² = y²+1² b = √(y²+1) units. c² = 1²+1² c² = 2 c = √(2) units. c is the diagonal of the square. d² = 1²+a² d² = 1²+(1-y)² d² = 1+1-2y+y² d = √(y²-2y+2) units. e = d-y e = (√(y²-2y+2)-y) units. Calculating y. Observing Similar Triangles Rule. y ~ (√(y²-2y+2)-y) (1-y) ~ 1 Cross Multiply. y = (√(y²-2y+2)-y)(1-y) y = √(y...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3377559

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Sir Mike Ambrose is the author of the question. Area Purple ÷ Area ABCD (square) in its simplest form. Let the single side length of the regular dodecagon be be 1 unit. Therefore; Area purple is; Area triangle with height √(3) units and base 1 unit. = ½*√(3)*1 = ½√(3) square units. Area ABCD (square) is; Area square with side (1+√(3)) units. = (1+√(3))² = 1+2√(3)+3 = 2(2+√(3)) square units. It implies; Area Purple ÷ Area ABCD (square) in its simplest fo...
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