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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3267350

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Calculating Area Red Inscribed Half Circle. Let x be the radius of the inscribed half circle. Calculating x. 2(6*x) = 6*6sin60 12x = 36sin60 x = 3*½√(3) x = ½(3√(3)) units. Again, x is the radius of the inscribed red half circle. Calculating area red half circle. ½*πx² = ½*π(½(3√(3)))² = ⅛(27)π square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3255144

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Calculating area of the ascribed square. Let x be each of the two equal lengths. a = 2x units. a is the side length of the ascribed square. tanb = 2x/x b = atan(2)° c = 180-45-atan(2) c = (45+atan(½))° (x/sin(45+atan(½))) = (d/sin45) d = 0.7453559925x units. d is the adjacent base of the blue inscribed triangle. cos(atan(½)) = x/e e = 1.11803398875x units. e is the adjacent height of the blue inscribed triangle. Calculating x. 0.5*d*e = 10 0.7453559925x*1.118...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3255141

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Calculating Angle x. Let 1 unit be the side length of the ascribed square. a = 90-70 a = 20° b = 90-20-45 b = 25° c = 90-25 c = 65° sin70 = 1/d d = 1.06417777248 units. tan20 = e/1 e = 0.36397023427 units. f = 1-e f = 0.63602976573 units. tan65 = 1/g g = 0.46630765815 units. h = 1-g h = 0.53369234185 units. j² = f²+h² j² = 0.63602976573²+0.53369234185² j = 0.83027789242 units. Therefore, Angle x is; (0.83027789242/sin45) = (1.06417777248/sinx)...

A Kind And humble Call For Your Donation/Contribution/Support/Assistance Financially To Assist Us Purchase Website Subscription Plan

https://onlineedumath.com/update/a-kind-and-humble-call-for-your-donationcontribut/3254676

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“Hello! As a valued supporter of our cause, we kindly, nicely ask for your donation/contribution/support/assistance financially to help us purchase subscription plan to keep our website active as we continue making a positive impact. Your donation will go a long way in supporting our cause and efforts.” Our USD MiniPay Wallet Details. Name: Ephivbotor Ogheneovo Daniel  Phone/Wallet Number: +2349076614992 Our Naira (Nigeria Currency) Account Details. Holder Name: Ogheneovo Daniel Ephi...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3254454

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Sir Mike Ambrose is the author of the question. Calculating Blue Area Exactly. Calculating Area Brown. a = (180(12-2))/12 a = 1800/12 a = 300/2 a = 150° a is the single interior angle of the regular polygon with 12 sides. b = ½(360-300) b = 30° c = ½(360-240) c = 60° sin30 = d/4 d = 2 cm. sin60 = e/4 e = 2√(3) cm. f = 2e+4 f = (4+4√(3)) cm. sin30 = g/4 g = 2 cm. sin60 = h/4 h = 2√(3) cm. j = 2g+f j = 2(2)+(4+4√(3)) j = (8+4√(3)) cm. Brown Area is...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3254211

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Calculating Area Square. Let x be the side length of the square. a²+x² = 13² a = √(169-x²) cm  b = x-a b = (x-√(169-x²)) cm. c² = 2x² c = √(2)x c is the diagonal of the square. Calculating x², area of the square. x² = 3(½(x)√(169-x²)) 2x² = 3x√(169-x²) 2x = 3√(169-x²) 4x² = 9(169-x²) 4x²+9x² = 9*169 13x² = 9*169 x² = 9*13 x² = 117 cm² Again, x² is the area of the square.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3254203

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Calculating Area Shaded. a = (x+6) cm. a is the radius of the ascribed circle. b = a-8 b = (x+6)-8 b = (x-2) cm. c = b+a c = (x-2)+(x+6) c = (2x+4) cm. c is the diameter of the inscribed circle. d = ½(c) d = (x+2) cm. d is the radius of the inscribed circle. e = d-b e = (x+2)-(x-2) e = 4 cm. Calculating x. x²+4² = (x+2)² x² +16 = x²+4x+4 12 = 4x x = 3 cm. Recall. d = (x+2) cm. Where d = r, radius of the inscribed circle. And x = 3 cm. d = r = 3+2 r...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3253085

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Sir Mike Ambrose is the author of the question. Let the side length of the square be 10 units. Area square is; 10² = 100 square units. Therefore; Area R is; Area semi circle with radius 5 units - Area sector with radius 5 units and angle (180-2atan(2))° - Area kite with diagonal lengths √(10²+5²) units and √(200-200cos(2atan(½))) units + Area sector with radius 10 units and angle 2atan(½)° - 2(area quarter circle with radius 5 units - area triangle with height and base 5 un...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3253081

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Calculating Area Blue. a = √(9)  a = 3 units. a is the side length of the big square. b = √(16) b = 4 units. b is the side length of the bigger square. It implies; ½*3*4sinx = 3 12sinx = 6 sinx = ½ x = 30° y = 180-x y = 150° z = 360-90-90-150 z = 30° Therefore, area shaded blue is; ½*3*4sinz = ½*12sin30 = ¼*12 = 3 square units.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3253079

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x/y = golden ratio (½(1+√(5)). Therefore, the prove. Let the side length of the regular pentagon be 1 unit. a = ⅕*180(5-2) a = 108° a is the single interior angle of the regular pentagon. b = 108-90 b = 18° c = 180-108-18 c = 180-126 c = 54° Calculating y. (y/sin18) = (1/sin54) y = (sin18)÷(sin54) y = ½(3-√(5)) units. It implies; x = 1-y x = 1-½(3-√(5)) x = ½(2-3+√(5)) x = ½(√(5)-1) units. Therefore, x/y (golden ratio) is; ½(√(5)-1)÷½(3-√(5)) = (√(5)-...
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