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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2990381

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Sir Mike Ambrose is the author of the question. Let the base of the parallelogram be 2 units. Therefore the area of the parallelogram is; 2(area triangle with height (sin70/sin35) unit and base 2sin75 unit). = 2*½*(sin70/sin35)*2sin75 = 3.16496046094 square units. Area shaded is; Area triangle with height 0.55803775975 unit and base 1.17917770336sin55 unit. = ½*0.55803775975*1.17917770336sin55 = 0.26951154209 square unit. It implies; The percentage of the shaded part of the parallelo...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2989231

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Sir Mike Ambrose is the author of the question. Let the side of the regular hexagon be 1 unit. Therefore; Area green is; Area triangle with height ½ units and base √(3) units + Area triangle with height 1.30930734142 units and base 1.13389341903 units. = ½*½*√(3) + ½*1.13389341903*1.30930734142 = ¼√(3) + 0.74230748896 = 1.17532019085 square units. Area orange is; Area triangle with height (2/5) units and base (½sin60) units. = ½*(2/5) )*½*sin60 = √(3)/20 square...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2989096

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Area yellow is; 2(area triangle with height (4.5/cos15) cm and base (4.5/cos15)sin60 cm + Area square with side (4.5/cos15) cm. = 2*½*(4.5/cos15)²(√(3)/2) + (4.5/cos15)² = (4.5/cos15)²(√(3)/2) + (4.5/cos15)² = 18.7961154131 + 21.7038845869 = 40.5 cm²
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