Mathematics Question and Solution
Calculating 2R, diameter of the red inscribed circle.
a = ½(16)
a = 8 units.
a is the radius of the inscribed yellow half circle.
b = (16-R) units.
c²+R² = b²
c² = (16-R)²-R²
c = √(256-32R+R²-R²)
c = √(256-32R) units.
d = (8+R) units.
e = (8-R) units.
It implies, R is;
e²+c² = d²
(8-R)²+√(256-32R)² = (8+R)²
64-16R+R²+256-32R = 64+16R+R²
-16R+256-32R = 16R
256 = 64R
R = 4 units.
Again, R is the radius of the inscribed red square.
It implies 2R, diameter of the inscribed red circle is;
= 2(4)
= 8 units.
