Mathematics Question and Solution
Calculating length CH (x).
a = 9+6
a = 15 units
a is AH.
b = a+x
b = (15+x) units.
b is AC.
Notice.
EF = EH = 6 units.
6²+c² = 9²
c² = 81-36
c = √(45)
c = 3√(5) units.
c is AF.
3√(5) ~ 15
6 ~ d
Cross Multiply.
3√(5)d = 6*15
d = 6√(5) units.
d is O1H, the radius of the inscribed yellow half circle.
e = c+2d
e = 3√(5)+2*6√(5)
e = 15√(5) units.
e is AB, the ascribed of the ascribed half circle.
It implies, length x is;
3√(5) ~ (15+x)
9 ~ 15√(5)
Cross Multiply.
9(15+x) = 3√(5)*15√(5)
15+x = 25
x = 25-15
x = 10 units.
x is CH, the required length.
