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We are smart and clever!

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“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach

We are smart and clever!

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For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992 We are kindly to respond to your question(s)/correction(s) as quickly as possible. Thank you!

We are smart and clever!

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Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them become a lover of Mathematics, and also, a Mathematician. Call/WhatsApp: +2349076614992 or +2348152827445 Email: [email protected] [email protected] [email protected] Facebook Page: Online Edumath We are super smart and amazingly, very clever!

Thank You, Sir Bill.

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The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our learners Mathematics, assisting them appreciate and love Mathematics, and become a Mathematician. Sir Bill is Online Edumath Patron, he is one of Educator Daniel's Mentors. Sir Bill is smart and clever!

Mr. Daniel (Mathematics Educator)

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Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of learners. Mr. Daniel is smart and clever!

Welcome to Online Edumath

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This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal Housing Authority, Federal Capital Territory, Abuja, Nigeria. You can contact us by phone call +2349076614992 or WhatsApp +2349076614992 or our Facebook page 'Online Edumath' or email us on [email protected] or use the Contact Form.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2987380

Let a be the side of the inscribed square. Calculating a. tan60 = a/b b = a/(tan60) cm. Where b is BS = CR. Therefore; 2b+a = 10 2a/(tan60)+a = 10 a((2/tan60)+1) = 10 a = 10(2√(3)-3) cm. a = 4.64101615138 cm. c = ½(10-a) c = 0.5(10-4.64101615138) c = 2.67949192431 cm. Where c = b. d = c+a d = 2.67949192431+4.64101615138 d = 7.32050807569 cm. Where d is BR. e = atan(4.64101615138/7.32050807569) e = 32.37365912705° It implies; Calculating TI, let it be f. tan32.37365912705 = f/g g = f/...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2985798

Sir Mike Ambrose is the author of the question. Area green exactly in decimal is; Square side is (16/√(17)) units. Area trapezoid with parallel sides (16/√(17)) units and (4/√(17)) units, and height (16/√(17)) units - Area triangle with height (16/√(17)) units and base (4/√(17)) units - Area triangle with height (16/√(17)) units and base 3.1067961165sin(atan(13/16)) units. = ½*(16/√(17))((16/√(17))+(4/√(17))) - ½*(16/√(17))(4/√(17)) - ½*(16/√(17))*3.1067961165sin(atan(13/16)) =...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2984060

Let the bigger inscribed side of the square be 2 units. Therefore, the big inscribed square side is 1 unit. The marked angle is; ½(atan(½)+atan(2)) = ½(90°) = 45°

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2982438

Area blue is; Area square with side 10 cm - Area quarter circle with radius 10 cm - Area square with side 5 cm + Area quarter circle with radius 5 cm. = (10*10) - (¼*10*10*π) - (5*5) + (¼*5*5*π) = 100 - 25π - 25 + ¼(25π) = 75 - 25π + ¼(25π) = ¼(300 - 100π + 25π) = ¼(300-75π) cm²

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Short Videos of Our Teaching and Learning Activities

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Please, highlight and open/browse the links below to view videos of our teaching and learning activities. Thank you. Video 1. Class with Adesuwa (year 5) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid02VGXZkxZYksDaBSZXhbkir8GKETEiU2fCQobAVZE4Yv84HRaQ3NL1XvAMTRTxsNs3l/?app=fbl Video 2. Class with Zino and Ruemu (year 4) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid038EyeWYY8Du4XgbEb7mbz33DS7XAvYWjXTwrE6HRfC4qpFTqCX6YVFYmnCeDBfEWHl/?app=fbl Video 3. Class with A...

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We are smart and clever!

We are smart and clever!

We are smart and clever!

Thank You, Sir Bill.

Mr. Daniel (Mathematics Educator)

Welcome to Online Edumath

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

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Short Videos of Our Teaching and Learning Activities

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