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OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

We are smart and clever!

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
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Welcome to Online Edumath

By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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We are smart and clever!

By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Let the radius of the inscribed semi circle be 1 unit. Therefore; Shaded area ÷ Rectangle area in it's simplest decimal form will be; (0.25...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Sir Mike Ambrose is the author of the question. Let the radius of one of the two equal circles be 1 unit. Total shaded area ÷ Rectangle area will be; (½(2x4)-π-(1-¼(4-π)-((180-2tan–¹(0.5))π÷...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Let x be the radius of the sector. b = (x-1) units. c = x+b c = x+(x-1) c = (2x-1) units. Therefore; 5*3 = (2x-1)*1 15 = 2x-1 2x = 16 x = 8 units. Again, a is the radius of the se...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
x ~ 7 7 ~ y Cross Multiply. y = 49/x units. Notice. 7 units is the radius of the green inscribed half circle. x = 5 units. x is the radius of the red inscribed half circle. Therefor...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
tana = 3/1.5 a = atan(2)° b = 3+1.5 b = 4.5 units. c = 3+1+x c = (4+x) units. Calculating x. It implies; tan(atan(2)) = c/b 2 = (4+x)/4.5 2 = (4+x)/(9/2) 2 = 2(4+x)/9 18 = 8...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Notice. Calculating the required angle, alpha. 4 units is the radius of the quarter circle. It implies; 3² = 4²+4²-2*4*4cosa 9 = 32-32cosa 32cosa = 32-9 a = acos(23/32) a = 44.04862...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Calculating area of the red inscribed circle. Let a be the radius of the blue ascribed circle. πa² =144π a² = 144 a = 12 cm. b = 2a b = 24 cm. b is the diameter of the blue ascribed ci...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
a = ½(2+7) a = 4.5 units. a is the radius of the ascribed half circle. Let b be the radius of the inscribed circle. c = (4.5-2b) units. d = (4.5-b) units. e = 4.5-2-b e = (2.5-b) uni...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Let the side length of the regular heptagon be 1 unit. Calculating angle x. a = ⅐*180(7-2) a = ⅐(900)° a is the single interior angle of the regular heptagon. b = ½(360-2*⅐(900)) b = 18...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Calculating x. a = ⅙*180(6-2) a = 120° a is the single interior angle of the green regular hexagon. b = ½(x) units. c = ⅙(x) units. It implies; d ~ b b ~ c Therefore; d ~ ½(...
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Mathematics Question and Solution

By OnlineEdumath   |  31st May, 2025
Let a be the side length of the two equal inscribed lengths. r = 2+1 r = 3 units. r is the radius of the ascribed half circle. b²+(a/2)² = 3² b²= 9-¼(a²) b = √(9-¼(a²)) b = ½√(36-a²) uni...
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Mathematics Question and Solution

By OnlineEdumath   |  28th May, 2025
Let the side length of the ascribed square be 1 unit. Therefore, the side length of the inscribed green regular triangle 1 unit. a = 90-60° a = 30° b² = 2-2cos30 b = 0.51763809021 units....
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Mathematics Question and Solution

By OnlineEdumath   |  28th May, 2025
sina = 4/(4+1) a = asin(4/5)° b² = 1²+4²-2*1*4cos(asin(4/5)) b = ⅕√(305) units. b = 3.49284983931 units. (3.49284983931/sin(asin(4/5))) = (4/sinc) c = asin(0.9161573349) c = 113.62937773...
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Mathematics Question and Solution

By OnlineEdumath   |  28th May, 2025
a² = (3+5)²+x² a² = a²-64 a = √(64+x²) cm. b = (8-x) cm. It implies; 5 ~ 8 (8-x) ~ √(64+x²) Cross Multiply. 8(8-x) = 5√(64+x²) (64-8x)² = 25(64+x²) 4096-1024x+64x² = 1600+25x² 2...
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Mathematics Question and Solution

By OnlineEdumath   |  28th May, 2025
Let single side of the square be x. Notice; PB=¼(AB)=¼(x). Calculating single side length of square ABCD. It will be; Area triangle ADP of height x and base (x-¼(x)) + area triangle...
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Mathematics Question and Solution

By OnlineEdumath   |  28th May, 2025
Sir Mike Ambrose is the author of the question. Let the bigger inscribed square be 2 units. BC = 1+2+x = (3+x) units. Calculating x. (3+x)²=1²+8-4√(2)cos135 3+x=√(13) x = (√(13)-3)...
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Mathematics Question and Solution

By OnlineEdumath   |  28th May, 2025
Notice. The ascribed right-angled triangle is not drawn to scale. Let a be the side length of the inscribed square. Calculating Area Inscribed Square. tanb = 3√(3)/(9√(3)) b = atan(⅓)°...
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Mathematics Question and Solution

By OnlineEdumath   |  27th May, 2025
Calculating Length x (AD). Let a be the diameter of the green inscribed circle. Therefore; x ~ a (b+x) ~ 2a Cross Multiply. 2ax = ab+ax 2ax-ax = ab ax = ab x = b units. Theref...
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Mathematics Question and Solution

By OnlineEdumath   |  27th May, 2025
Let OF be r, radius of the ascribed circle. a²+r² = (2+3)² a = √(25-r²) units. b = a+r b = (r+√(25-r²)) units. c = r-a c = (r-√(25-r²)) units. Therefore; 4*(2+3) = (r-√(25-r²))(r+...
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Mathematics Question and Solution

By OnlineEdumath   |  27th May, 2025
Total area of the ascribed composite plane shape is; (¼*12*12π) + (½*6*6π) = 36π+18π = 54π cm² Calculating the inscribed shaded area. Let re be the radius of the inscribed shaded half ci...
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Mathematics Question and Solution

By OnlineEdumath   |  27th May, 2025
a² = 3²+4² a = √(25) a = 5 units. a is the hypotenuse of the ascribed right-angled triangle. tanb = 3/4 b = atan(3/4)° tanc = 4/3 c = atan(4/3)° Let d be the radius of the inscribed c...
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Mathematics Question and Solution

By OnlineEdumath   |  27th May, 2025
Let BH be a. It implies; 25 ~ a a ~ 4 Cross Multiply. a² = 100 a = 10 units. b² = 25²+10² b = √(725) units. b is AB, the side length of the ascribed square. c² = 10²+4² c = √...
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Mathematics Question and Solution

By OnlineEdumath   |  26th May, 2025
Notice. The angle formed at the meet point (vertex) of length 4 units and x units is equal the angle formed at the meet point (vertex) 9 units and x units. Therefore, as a result, two similar...
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Mathematics Question and Solution

By OnlineEdumath   |  26th May, 2025
Sir Mike Ambrose is the author of the question. Let the square side be 1 unit. Therefore; Area B is; Area triangle with height 1 unit and base sin(53.13010235416) units - Area triangle wi...
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Mathematics Question and Solution

By OnlineEdumath   |  26th May, 2025
Calculating Area Blue. (2/sin120) = (1/sina) a = 25.6589062733° b = 180-120-a b = 60-25.6589062733 b = 34.3410937267° Therefore, shaded blue area is; Area sector with radius 2 units...
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Mathematics Question and Solution

By OnlineEdumath   |  26th May, 2025
a = ½(4+6) a = 5 units. a is radius. 10² = x²+b² b = √(100-x²) units. c = 10-½(4) c = 8 units. x² = c²+d² x² = 8²+d² d = √(x²-64) units. Calculating x. Therefore; 8 ~ √(x²-6...
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Mathematics Question and Solution

By OnlineEdumath   |  26th May, 2025
Notice. r, radius of the ascribed quarter circle is (25/√(2)) units. r = ½(25√(2)) units. (AD)² = 2(½(25√(2)))² (AD)² = 2*¼*625*2 AD = √(625) AD = 25 units. It implies; AB+BC+CD = AD 10+BC+4 =...
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Mathematics Question and Solution

By OnlineEdumath   |  26th May, 2025
Calculating Area Blue. a = 4+8 a = 12 cm. a is the radius of the ascribed quarter circle. b² = 12²+4² b = √(144+16) b = √(160) b = 4√(10) units. tanc = 12/4 c = atan(3)° (12/sin(60+atan(3))) =...
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Mathematics Question and Solution

By OnlineEdumath   |  24th May, 2025
Let FC=x. Let CE=y Therefore; 5+x=y+4 x=y-1 ------- (1). Notice; Triangle AEF is similar to triangleEFC. It implies; 5+x=y     4=x, cross multiply. x²+5x=4y ----- (2). Subs...
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Mathematics Question and Solution

By OnlineEdumath   |  24th May, 2025
a = (r+9) units. b = (r-9) units. a² = b²+c² (r+9)² = (r-9)²+c² c² = r²+18r+81-r²+18r-81 c² = 36r c = 6√(r) units. d = (r+4) units. e = (r-4) units. f²+e² = d² f² =...
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Mathematics Question and Solution

By OnlineEdumath   |  24th May, 2025
Sir Mike Ambrose is the author of the question. Let the side of the regular hexagon be 1 unit. Therefore; Length Blue is; √(2-2cos108) = 1.61803398875 unit. Length Red is; √(1²+...
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Mathematics Question and Solution

By OnlineEdumath   |  24th May, 2025
a = ⅕*180(5-2) a = 108° a is the single interior angle of the regular pentagon. b = 180-a-42 b = 180-150 b = 30° (12/sin108) = (c/sin30) c = 6.30877334543 cm. c is the side length of th...
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Mathematics Question and Solution

By OnlineEdumath   |  24th May, 2025
Let r be the radius of the half circle. a²+2² = r² a = √(r²-4) units. b = 2a b = 2√(r²-4) units. c = (r-2) units. Calculating r. √(r²-4) ~ 2√(r²-4) (r-2) ~ 9 Cross Multiply....
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Mathematics Question and Solution

By OnlineEdumath   |  23rd May, 2025
2πr = 13π r = ½(13) cm. r is the radius of the ascribed large circle. a = 2r a = 2*½(13) a = 13 cm. a is the diameter of the ascribed large circle. It implies; c = a-3b c = (13-3b) c...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd May, 2025
Calculating R, radius of the circle. R² = (½(9))²+a² a² = R²-(81/4) a = √(R²-(81/4)) units. b = ½(9)+3 b = ½(15) units. c = a-4 c = (√(R²-(81/4))-4) units. There, R is; R² = b²+c...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd May, 2025
a² = 2²+2² Where; a is radius of the ascribed half circle. 2 is the side length of the inscribed blue square. a² = 8 a = 2√(2) cm. Again, a is the radius of the circle. Therefore, leng...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd May, 2025
Notice. R-r = 10 cm. It implies; R = (10+r) cm. R is the side length of the ascribed square. Calculating length AB. a = R-r a = 10 cm. b = ½(R) units. It implies; R² = 10²+...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd May, 2025
Sir Mike Ambrose is the author of the question. Calculating Yellow Area. It is; Area triangle with height 4sin(atan(⅔)) units and base 8√(13)/9 units - Area triangle with height 1 unit and b...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd May, 2025
Sir Mike Ambrose is the author of the question. Let the square aide length be 1 unit. Square Area is; 1² = 1 square unit. Calculating Green Area. a² = 1²+1² a = √(2) units. a is AB....
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Mathematics Question and Solution

By OnlineEdumath   |  21st May, 2025
Let a be the side length of the big inscribed square. Let b be the side length of the bigger inscribed square. Therefore; 27 ~ b a ~ 64 Cross Multiply. ab = 27*64 b = (1728)/a unit...
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Mathematics Question and Solution

By OnlineEdumath   |  21st May, 2025
Sir Mike Ambrose is the author of the question. Let a be the equal lengths inscribing triangle ABC. Calculating a. ½(a)² = 15 a = √(30) units. b = 180-60-45 b = 75° b is angle BAC....
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Mathematics Question and Solution

By OnlineEdumath   |  21st May, 2025
Let R=the bigger inscribed circle radius. Let r=the smaller inscribed circle radius. It implies; R+r=6√(3)-6=4.4  R+r=4.4 -------(1). And the radius of the ascribed semi circle is 6...
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Mathematics Question and Solution

By OnlineEdumath   |  21st May, 2025
Notice. Radius rod the half circle is 5 units. a = (5-x) units. Calculating x. 5² = 3²+(5-x)² 16 = 25-10x+x² x²-10x+9 = 0 x = 1 unit. It implies; a = 5-x And x = 1 unit. a = 4...
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Mathematics Question and Solution

By OnlineEdumath   |  20th May, 2025
a = (2r-14) units. b = ½(a) b = (r-7) units. Calculating r, radius of the half circle. Therefore; 2r ~ 6 6 ~ (r-7) Cross Multiply. 2r(r-7) = 36 r²-7r-18 = 0 Resolving the qu...
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Class with Ellis, year 2 pupil.

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Class with Ellis, year 2 pupil.

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Mathematics and Science

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Identifying Prime Numbers

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Quadratic Equation Using Formula

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Constructing and Bisecting Lines and Angles

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Math Story

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Mathematics is not difficult, it is a language

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Comparing Numbers

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Place Value

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Telling Time

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Young Sheldon

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Young Sheldon

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Math Story

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Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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