OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

Our Updates

By OnlineEdumath   |  20th August, 2025
“Hello! As a valued supporter of our cause, we kindly, nicely ask for your donation/contribution/support/assistance financially to help us purchase subscription plan to keep our website active as w...
By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
By OnlineEdumath   |  22nd August, 2025
Calculating FB. a = 8+9 a = 17 units. b = 9-8 b = 1 unit. c² = 17²+1² c = √(290) units. c = 17.0293863659 units. c is DE. 2d² = c² 2d² = √(290)² d² = 145 d = √(145) units. d =...
By OnlineEdumath   |  22nd August, 2025
Calculating The Required Shaded Area. a = ¼(2R) a = ¼(6) a = 1.5 units. b² = 2(3)² b = 3√(2) units. c² = 1.5²+3²-2*3*1.5cos150 c = ½(3√(7)) units. c = 4.36396936676 units. d² = (3√...
By OnlineEdumath   |  21st August, 2025
Calculating Shaded Area. a² = 11²+8² a = √(185) units. b²+4² = a² b² = 185-16 b = √(169) b = 13 units. b is the length of the equal rectangles. Shaded Area is; (13*8)-½(11*8)-2(½(13*...
By OnlineEdumath   |  21st August, 2025
Calculating Shaded Blue Area. a²+(0.5*6)² = 5² a² = 25-9 a = √(16) a = 4 cm. It is; Area isosceles right-angled triangle with equal sides 6 cm+Area trapezoid with parallel lengths 3 cm...
By OnlineEdumath   |  21st August, 2025
Calculating FB. Let a be OC = OE = CE. b = (a+16) units. b is the radius of the ascribed half circle (OD = OA). c = b-5 c = (a+16)-5 c = (a+11) units. c is OB. d = c+a d = (a+11)+a...
By OnlineEdumath   |  20th August, 2025
Sir Mike Ambrose is the author of the question. Calculating Area yellow ÷ Area BDE. Area BDE is; Area triangle with side 2 units and 3 units, and angle 120° = ¼(6√(3)) = ½(3√(3)) squar...
By OnlineEdumath   |  20th August, 2025
Calculating inscribed regular hexagon shaded area ÷ Ascribed regular hexagon area. Let the side length of the inscribed shaded regular hexagon be 1 unit. a² = 2-2cos120 a = √(2) units. Shade...
By OnlineEdumath   |  20th August, 2025
Calculating the required angle. Notice. The ascribed plane shape is a square, let it's side length be x. Let the longest side length of the inscribed red lengths triangle be 1 unit. a =...
By OnlineEdumath   |  19th August, 2025
Notice. The ascribed quadrilateral is a square. Calculating x, the side length of the square. a²+x² = 8² a = √(64-x²) units. b²+x² = 10² b = √(100-x²) units. It implies;. c = (x-√(...
By OnlineEdumath   |  19th August, 2025
Calculating Inscribed Blue Rectangle Area. a = 15+5 a = 20 units. a is the radius of the circle. Let b be the length of the blue inscribed rectangle. b² = 2(20)²-2(20)²cos(90-x) b² = 800...
By OnlineEdumath   |  19th August, 2025
Kindly move the question right/left one time to review the framework/analysis. Thank you nicely. Calculating Area Inscribed Blue Rectangle. a = 15+5 a = 20 units. a is the radius of the circl...
By OnlineEdumath   |  19th August, 2025
Calculating Area Green. a = ⅙*180(6-2)-90 a = 120-90 a = 30° b = ½(a) b = 15° c = 180-15-120 c = 45° It implies; (d/sin45) = (1/sin15) d = (1+√(3)) units. d = 2.73205080757 uni...
By OnlineEdumath   |  19th August, 2025
Calculating x, side length of the largest ascribed square. a =14+9 a = 23 units. b² = 23²+7² b = √(578)  b = 17√(2) units. b is the diagonal of the largest square. It implies, x is;...
By OnlineEdumath   |  18th August, 2025
Calculating Shaded Blue Area. Notice. ½(10) = 5 cm is the radius of the inscribed circle. a² = 2(10)² a = 10√(2) cm. a is the diagonal of the ascribed square. b = ½(a) b = 5√(2) cm....
By OnlineEdumath   |  18th August, 2025
Calculating fraction of yellow shaded area. Let the single side length of the square be 2 units. Area yellow (shaded area) is; ½(4) square units. = 2 square units. Area square is; 2...
By OnlineEdumath   |  17th August, 2025
Kindly move the question right/left one time to review the framework/analysis of the question. Thank you nicely. Calculating length DG. Let x be the side length of the square. Let h be th...
By OnlineEdumath   |  17th August, 2025
Calculating Shaded Area. Let the radius of the semi circle be r. Calculating r. 2+√(5/2)r  ~  ½(3r)              2r  ~  √(5/2)r Cross multiply. 3r² = 2√(5/2)r + (5/2)r² (½)r² = 2√(...
By OnlineEdumath   |  17th August, 2025
Calculating the area of each rectangle. Let the length and width of the rectangle be y and z respectively. Therefore; 7+7+x+y+z+7+7+x+y+z=66 Where 7 is the single side length of the squar...
By OnlineEdumath   |  17th August, 2025
Sir Mike Ambrose is the author of the question. Calculating Area Orange ÷ Area Triangle ABC. Let the single side length of the regular hexagon be 2 units. Therefore; Area orange is; 1.25264388762...
By OnlineEdumath   |  16th August, 2025
Sir Mike Ambrose is the author of the question. Let alpha be x. Calculating Cot²x and (Red length ÷ Blue length)² as single fractions. Let the side length of the square be 2 units. tan30...
By OnlineEdumath   |  16th August, 2025
Calculating Red Area. Let x be length AB equal length BD. a²+3² = x² a = √(x²-9) units. It implies; Calculating x  ½(4+x)*3 = (3*x)+½(3√(x²-9)) 12+3x = 6x+3√(x²-9) 12-3x = 3√(...
By OnlineEdumath   |  16th August, 2025
Calculating Length x. a = 12+8 a = 20 units. cosb = 20/24 b = acos(5/6)° c = 90-b c = (90-acos(5/6))° c = 56.4426902381° Therefore, the required length x is; cos56.4426902381 = 8/x x = 8/cos56...
By OnlineEdumath   |  15th August, 2025
Sir Mike Ambrose is the author of the question. Calculating Blue Area + Red Area Exactly. Let x be the side length of the regular octagon. a = ⅛*180(8-2) a =135° a is the single interior a...
By OnlineEdumath   |  15th August, 2025
Calculating angle x. a = 180-2(58)-48 a = 180-116-48 a = 180-164 a = 16° a is angle BAD. Let 1 unit be the let AB equal length AC. (a')² = 2-2cos(a+48) a' = √(2-2cos64) a' = 1.059838...
By OnlineEdumath   |  15th August, 2025
Calculating Area Inscribed Green Circle. Let a be the radius of the inscribed green circle. b = 8-2 b = 6 units. tanc = 6/8 c = atan(3/4)° d = ½(90+c) d = ½(90+atan(3/4))° e = (2-a) units. It...
By OnlineEdumath   |  14th August, 2025
Calculating Required Shaded Area. Notice. The three circles are congruent. Therefore, the required shaded area is; Area equilateral triangle with side r units+3(area sector with radius r...
By OnlineEdumath   |  14th August, 2025
Sir Mike Ambrose is the author of the question. Calculating Area Blue. It is; Area triangle with height 25 units and base ⅓(100) units - Area square with single side length 5 units - Area...
By OnlineEdumath   |  14th August, 2025
Calculating yellow area. Notice. Area of the ascribed square is 12 square units. Area yellow is; ½(12) - (½(⅔√(3))²sin(atan(3))÷sin(135-atan(3)))sin(45) = 6 - (½) = ½(12-1) = ½(11)...
By OnlineEdumath   |  14th August, 2025
Calculating Area Red. Area red is; ½(3*4) - (atan(4/3)*9π÷ 360) - (atan(3/4)*4π÷ 360) = 0.54016930141 square units.
By OnlineEdumath   |  13th August, 2025
Calculating Area Rectangle. Let r be the radius of the half circle and also, the width of the rectangle. a = r+r a = 2r units. a is the diameter of the half circle. b = (2r-x) units. b...
By OnlineEdumath   |  13th August, 2025
Sir Mike Ambrose is the author of the question. Let the single side length of the regular hexagon be 2 units. Area rectangle is; 2.5x√(3) = ½(5√(3)) square units. Area green is; Are...
By OnlineEdumath   |  13th August, 2025
Calculating Area Green. Let x be the side length of the ascribed square. a = ½(x) units. tanb = x/(½(x)) b = atan(2)° c = 180-45-atan(2) c = (45+atan(½))° It implies; (0.5x/sin(...
By OnlineEdumath   |  12th August, 2025
Calculating Angle x. Let AC = 1 units. sin(10+10) = a/1 a = 0.34202014333 units. a is BC. tan40 = b/0.34202014333 b = 0.28698897612 units. c = 180-10-30-40 c = 100° (1/sin100) =...
By OnlineEdumath   |  12th August, 2025
Calculating Yellow Area. 2a² = 2² a = √(2) units. a is the radius of each of the two congruent half circles. 2b² = (2+1)² b² = ½(9) b = ½(3√(2)) units. b is the radius of the circle....
By OnlineEdumath   |  12th August, 2025
Calculating angle x. a = 180-2(48) a = 180-96 a = 84° b = 180-72-a b = 180-72-84 b = 180-156 b = 24° c = ½(180-72) c = ½(108) c = 54° d = 90-c d = 90-54 d = 36° Therefore, t...
By OnlineEdumath   |  11th August, 2025
Calculating Area Blue. a = 5+3 a = 8 units. a is the side length of the big square. b² = 3²+8² b² = 9+64 b = √(73) units. c = ½(b) c = ½√(73) units. c is the side length of the two e...
By OnlineEdumath   |  11th August, 2025
Calculating Shaded Area Blue. a² = 4²+3² a = √(25) a = 5 units. a is the radius of the quarter circle. 5 ~ 4 3 ~ b Cross Multiply. 5b = 12 b = 2.4 units. d² = 5²+3² d = √(34) units...
By OnlineEdumath   |  11th August, 2025
Let 1 unit be AB = BC = CD. a² = 2-2cos150 a = 1.93185165258 units. a is BD. b = 90-½(180-150) b = 90-15 b = 75° b is angle ABD. c² = 1+1.93185165258²-2*1.93185165258cos75 c = 1.93185165258 units...
By OnlineEdumath   |  10th August, 2025
Sir Mike Ambrose is the author of the question. Calculating Area Shaded ÷ Area Purple to 2 decimal places. Let AB be 5 units. Radius, r of the inscribed circle is; r = 5*(2/5) r = 2 un...
By OnlineEdumath   |  10th August, 2025
Calculating Area Blue. a = 5+3 a = 8 units. It implies; b*4 = 3*8 4b = 24 b = 6 units. b is BC. c = 4+b c =10 units. d² = 10²+5² d² = 125 d = √(125) d = 5√(5) unit. d is the...
By OnlineEdumath   |  10th August, 2025
Calculating area of the circle. Let the radius of the circle be r. Therefore; (2r)²=2(√(20))² 4r²=40 r = √(10) units. Therefore area of the circle is; π√(10)² = 10π square u...
By OnlineEdumath   |  10th August, 2025
Calculating R, radius of the inscribed circle. Let a be the radius of the inscribed half circle. Calculating a. b²+9² = 15² b² = 225-81 b = √(144) b = 12 units. c = (12-a) units....
By OnlineEdumath   |  9th August, 2025
Calculating the inscribed angle beta, let it be y. Let (x+3) units be the side length of the square. a²+x² = 4² a = √(16-x²) units. b = 1+a b = (1+√(16-x²)) units. b is the side length...

Our Media

media video Class with Tejiri (year 12) and Vwarhe (year 10)

Class with Tejiri (year 12) and Vwarhe (year 10)

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

media video Mathematics Knowledge

Mathematics Knowledge

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

WhatsApp Google Map

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support