OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

Our Updates

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
By OnlineEdumath   |  12th July, 2025
Green Area is; Area square with length 4 units - Area quarter circle with radius 2 units - Area square with length 2 units - 3(Area square with length 1 unit) - Area square with length 3 units +...
By OnlineEdumath   |  12th July, 2025
Calculating Length x. 7² = x²+(x+5)²-2*(5+x)xcosa 49 = 2x²+10x+25-(10x+2x²)cosa (10x+2x²)cosa = 2x²+10x-24 cosa = (2x²+10x-24)/(10x+2x²) --- (1). 7² = x²+5²+2*x*5cosa 49-25-x² = 10xcosa 24-x² = 10...
By OnlineEdumath   |  12th July, 2025
Calculating length c. cosd = 9/12 d = acos(3/4)° e = 2d e = 2acos(¾)° Therefore, length c is; cose = c/a cos(2acos(¾)) = c/12 c = 12cos(2acos(¾)) c = 12*⅛ c = ½(3) units. c = 1.5 units.
By OnlineEdumath   |  11th July, 2025
Let a be the diameter of the circle. x² = 6²+6²+2*6*6cosb x² = 72+72cosb --- (1). x² = 14²+a²-2*14acosb x² = 196+a²-28acosb --- (2). Notice. x is length AC b is angle ADC. cosb =...
By OnlineEdumath   |  11th July, 2025
Let a = AB = AD = CD. b² = 2a² b = √(2)a units. b is BD. Notice. Triangle BCD is a right-angled triangle, where BC is the hypotenuse. c² =(√(2)a)²+a² c = 3a² c = √(3)a units. c is BC. cosd = (0....
By OnlineEdumath   |  10th July, 2025
Sir Mike Ambrose is the author of the question. Calculating Exactly Green Area. Let x be the side length of each of the three inscribed congruent squares. a² = 2x² a = √(2)x a is the diago...
By OnlineEdumath   |  10th July, 2025
Let a be the radius of the quarter circle. b = (a-6) units. c = (a-8) units. Let x be the side length of the square. x² = (a-8)²+(a-6)² x² = a²-16a+64+a²-12a+36 x² = 2a²-28a+100 x =...
By OnlineEdumath   |  10th July, 2025
Calculating the radius of the inscribed circle. a²+6² = 10² a = √(64) a = 8 units. Let x be the radius of the inscribed half circle. Calculating x. b = (8-x) units. c = (6-x) units. It implies...
By OnlineEdumath   |  9th July, 2025
Let the three equal lengths be x. a = x+x+x+8+8 a = (16+3x) units. a is the diameter of the ascribed half circle. b = ½(a) b = ½(16+3x) units. b is the radius of the ascribed half circle....
By OnlineEdumath   |  9th July, 2025
Calculating r2, radius of the smaller inscribed circle. r2 will be; Let it be x. Therefore; (4+x)²=(8-x)²+(4-x)² 16+8x+x²=64-16x+x²+16-8x+x²  x²-32x+64=0 (x-16)²=-64+256 x = 16±8√(3) x ≠ 16...
By OnlineEdumath   |  8th July, 2025
Kindly move the question left/right one time to review the analysis of the question (plane shape). Thank you nicely. Calculating R, radius of the quarter circle. a = 3+4 a = 7 units. b² = 2...
By OnlineEdumath   |  8th July, 2025
Calculating shaded blue area. The radius, r if the small circle will be; (5+r)²=2(5-r)² 25+10r+r²=50-20r+2r² Therefore r²-30r+25=0 (r-15)²=-25+225 r = 15±√(200) r = 15±10√(2) I...
By OnlineEdumath   |  8th July, 2025
Calculating shaded inscribed area. a = 6+6 a = 12 units. a is the side length of the ascribed square. b = a-4 b = 8 units. tanc = 8/6 c = atan(4/3)° d = 180-2c d = 2atan(3/4)° e = ½(d) e = atan...
By OnlineEdumath   |  7th July, 2025
Calculating area blue. a²+1² = 2² a = √(3) units. a is the diameter of the inscribed white circle. b = ½(a) b = ½√(3) units. b is the radius of the inscribed white circle. cos30 = 1/c...
By OnlineEdumath   |  7th July, 2025
a² = 9²+12² a = √(81+144) a = √(225) a = 15 cm. It implies; Calculating r. (9*3r)+(12*r)+(15*r) = (9*12) 27r+12r+15r = 9*12 54r = 9*12 6r = 12 r = 2 cm.
By OnlineEdumath   |  6th July, 2025
Let XM be x. Let AZ be y. b = (8-x) units. b is MY. c = (4-y) units. c is AY. Therefore; ½(4x) = ½(8y) 2x = 4y x = 2y --- (1). Recall. b = 8-x And x = 2y b = (8-2y) units...
By OnlineEdumath   |  6th July, 2025
Let the radius of the quarter circle be 1 unit. 2a² = 1 a² = ½ a = ½√(2) units. a is the side length of the inscribed square. b = 1-a b = 1-½√(2) b = ½(2-√(2)) units. b is the side length of the g...
By OnlineEdumath   |  5th July, 2025
a = ½(10) a = 5 units. a is the radius of the ascribed half circle. cosb = 4/5 b = 36.8698976458° b is angle alpha. c²+8² = 10² c = √(100-64) c = 6 units. sin(2acos(4/5)) = d/10 d = 9.6 units. c...
By OnlineEdumath   |  5th July, 2025
Sir Mike Ambrose is the author of the question. Let the single side length of the square be 2 units. Calculating area S. It will be; Area trapezoid of two parallel side lengths 2 units an...
By OnlineEdumath   |  4th July, 2025
Using similar triangle approach. It implies;      n ~ 1 n+1 ~ n Cross multiply. Therefore; n²=n+1 n²-n-1=0 (n-½)²=1+¼ n =½±½(√(5)) Therefore; n ≠ ½(1-√(5)) n = ½(1+√(5))...
By OnlineEdumath   |  4th July, 2025
Let length AB be x. A careful analysis carried out on the given composite plane shape lead to the derivation of right-angled tiangle EQX with hypotenuse QX ⅓(4x) and the two adjacent side of the tr...
By OnlineEdumath   |  3rd July, 2025
Calculating the radius of the two congruent inscribed circles. Let the radius of the two congruent inscribed circles be a each. b² = 3²+(2+2)² b = √(25) b = 5 units. It implies; (4*(3...
By OnlineEdumath   |  3rd July, 2025
Calculating x, the side length of the ascribed square. a²+x² = 8² a = √(64-x²) units. b²+x² = 10² b = √(100-x²) units. It implies;. c = (x-√(64-x²)) units. d = (x-√(100-x²)) units. Therefore;...
By OnlineEdumath   |  2nd July, 2025
Let the radius of the quarter circle be 1 unit. b = (a+1) units. a is AD = DE. a² = 2-2cosx 2cosx = 2-a² cosx = ½(2-a²) --- (1). cosx = 1/(1+a) --- (2). Calculating a. Equating (1...
By OnlineEdumath   |  2nd July, 2025
Calculating Area Inscribed Red Circle. a = ½(8) a = 4 units. a is the radius of the two congruent half circles. b = (4+x) units. x is the radius of the red inscribed circle. c = (4-x) units. The...
By OnlineEdumath   |  1st July, 2025
Calculating r, radius of the circle. Notice that the plane shape is not drawn to scale. r² = (7+a)²+(0.5*10)² r² = 49+14a+a²+25 r² = 74+14a+a² --- (1). Again. r² = a²+(7+5)² r² = a²+...
By OnlineEdumath   |  1st July, 2025
Calculating r, radius of the half circle. Let the two equal lengths be a each. Therefore; r = 2a units. Calculating a. (2a)² = a²+9²-2a*9cosb 3a² = 81+18acosb cosb = (3a²-81)/(18a) cosb = (a...
By OnlineEdumath   |  30th June, 2025
Calculating shaded area. tana = 5/10 a = atan(½)° Therefore; b = atan(2)° c = 90-2a c = 90-2atan(½) c = 36.8698976458° d = 180-2b d = 180-2atan(2) d = 53.1301023542° Shaded A...
By OnlineEdumath   |  30th June, 2025
Calculating x. a = 2*120 a = 240° b = 360-a b = 120° c = ½(180-120) c = 30° d = 2*140 d = 280° e = 360-d e = 80° f = ½(180-80) f = 50° It implies; x = c+f x = 30+50 x = 80°
By OnlineEdumath   |  30th June, 2025
Notice. r is the radius of the inscribed yellow half circle. r = ½(10) r = 5 units. Calculating R, radius of the ascribed circle. Calculating R. a = x+10+5 a = (x+15) units. b = ½(a) b = ½(x+1...
By OnlineEdumath   |  30th June, 2025
Kindly move the question right or left one time to review the solution and answer. Solution and answer by Mehmet Kara. Thank you nicely.
By OnlineEdumath   |  29th June, 2025
Let AC = BD = DE = a. Calculating a. 14² = a²+(10+a)²-2a(10+a)cosb 96 = 2a²+20a-(20a+2a²)cosb --- (1). 14² = a²+10²+2a*10cosb 96 = a²+20acosb cosb = (96-a²)/(20a) --- (2). Substituting (2) in (1...
By OnlineEdumath   |  29th June, 2025
Calculating Purple Area. tanb = 2/1 b = atan(2)° tanc = ½ c = atan(½)° d = 180-b d = (180-atan(2))° e = 180-d-c e = 180-(180-atan(2))-atan(½) e = (atan(2)-atan(½))° It implies; (1/sin(atan(2)-...
By OnlineEdumath   |  29th June, 2025
Let 1 unit be the side length of the green square. Therefore; EN = ½ units. a = (1+2x) units. a is the diameter of the bigger circle. b = ½(a) b = ½(1+2x) units. b is the radius of the...
By OnlineEdumath   |  28th June, 2025
R ~ (a+b) r ~ a Cross Multiply. aR = r(a+b) R/r = (a+b)/a R/r = 1+(b/a) And R/r = phi (golden ratio) Let phi be x. x-1 = b/a a/b = 1/(x-1) Where x (phi) is; x = ½(1+√(5))...
By OnlineEdumath   |  28th June, 2025
Calculating Area A Divided By Area B (A/B). Let a be the two equal lengths. b = (3-a) units. c² = 4²+3² c = 5 units. Therefore; Calculating a. 5 ~ (3-a) 4 ~ a Cross Multiply. 5x = 12-4a 9a = 1...
By OnlineEdumath   |  28th June, 2025
Let DC = 1 unit. a = 180-36+30 a = 114° a is angle BDC. (1/sin36) = (b/sin114) b = 1.55421636402 units. b is BC. c = 180-60-54 c = 180-114 c = 66° c is angle BAC. Therefore; (1.55421636402/sin6...
By OnlineEdumath   |  28th June, 2025
Calculating R. 3R+4R+5R = 3*4 12R = 12 R = 1 units. Calculating r. tana = 3/4 a = atan(3/4)° b = ½(a) b = ½(atan(3/4))° tan(½(atan(3/4))) = r/c c = 3r units.    d = 4-1-3r d = (3-3r) units. e...
By OnlineEdumath   |  27th June, 2025
Let the height and base of the brown area be x and y respectively. Therefore; ½(3+x)(4+y)-42 = ½(xy) 12+3y+4x+xy-84 = xy 3y+4x = 72 --- (1). 3 ~ (3+x) 4 ~ (y+4) Cross Multiply. 4(...
By OnlineEdumath   |  27th June, 2025
a² = 2(1)² a = √(2) units. a is the diagonal of the inscribed square and also the side length of the two congruent inside bigger regular triangle. b = ½(a)  b = ½√(2) units. c²+b² = a² c² = √(2)²-...
By OnlineEdumath   |  27th June, 2025
a = 2(20) a = 40 units. b = 60+20 b = 80 units. c = 2(20) c = 40 units. d = atan(80/40)+atan(20/40) d = 90° d is angle ACB Area Triangle ABC is; ½*√(80²+40²)*√(40²+20²) = ½*√(6400+1600)*√(1600...
By OnlineEdumath   |  27th June, 2025
Let the inscribed green square side length be a. 2b² = a² b = ½√(2)a units. c² = 2(4)² c = 4√(2) units. c is the diagonal of the ascribed bigger square. It implies; 4+a+½(a) = c...
By OnlineEdumath   |  26th June, 2025
Calculating x, length AD. c² = x²+3² c = √(x²+9) units. c is AC. d²+2² = c² d² = √(x²+9)²-4 d² = x²+5 d = √(x²+5) units. d is AB. Notice. a-b = 30 Therefore; a = (30+b)° sinb = x/√(x²+9) --- (1...
By OnlineEdumath   |  26th June, 2025
Let b = 1 unit. Calculating a. c² = 2a² c = √(2)a units. c is the diagonal of each of the three identical squares. d = c-a d = (√(2)a-a) units. It implies; 1² = a²+(√(2)a-a)²-2a(√(2)a-a)cos45...

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Class with Tejiri (year 12) and Vwarhe (year 10)

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Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Vwarhe, js3 student (year 9).

Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Joshua, year 1 pupil.

Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

media video Math Story

Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

media video Telling Time

Telling Time

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

media video Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

media video Maths at The Mela

Maths at The Mela

media video Math Story

Math Story

media video The Map of Mathematics

The Map of Mathematics

media video Mathematics Knowledge

Mathematics Knowledge

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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