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OnlineEdumath

Year of Establishment
March, 2020

3
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

Welcome to Online Edumath

By OnlineEdumath   |  18th April, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  24th June, 2024
The radius, r if the small circle will be; (5+r)²=2(5-r)² 25+10r+r²=50-20r+2r² Therefore r²-30r+25=0 (r-15)²=-25+225 r = 15±√(200) r = 15±10√(2) It implies; r ≠ 15+10√(2) r = 15...
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Mathematics Question and Solution

By OnlineEdumath   |  24th June, 2024
Sir Mike Ambrose is the author of the question. Notice! AB = BC Calculating AB. AB = (20sin60)/sin104 AB = BC = 17.85075169007 cm. Calculating BD BD = (20sin16)/sin104 BD = 5.6815...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
Let the side length of the inscribed green square be a. b = ½(10-a) units. c = b+a c = ½(10-a+2a) c = ½(10+a) units. Therefore, a² (area green inscribed triangle) is; 10² = a²+(½(10+a...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
Let OC be a. Let the radius of the inscribed blue half circle be b. Calculating area inscribed blue half circle. 20² = 2c² c = √(200) c = 10√(2) units. d = ½(c) d = 5√(2) units. d i...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
Let the side length of the two congruent inscribed squares be 1 unit each. a² = 1+2² a = √(5) units. a is the radius of the half circle. tanb = (½)  b = atan(½)° (√(5)/sin(atan(½))) = (...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
Let alpha be a. Let AB be b. tana = 2/b --- (1). tana = b/(2+6)  tana = b/8 --- (2). Equating (1) and (2). 2/b = b/8 b² = 16 b = 4 units. Again, b is AB. Therefore, the requir...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
Let a be the radius of the circle. b = 2a units. b is the diameter of the circle. Observing similar plane shape (right-angled) side length ratios. 6 - 2a a - 10 Cross Multiply. 2a²...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
Let BC be a. Let alpha be b. tanb = 24/a --- (1). tan(2b) = (24+26)/a tan(2b) = 50/a 2tanb/(1-tan²b) = 50/a --- (2). Substituting (1) in (2). 2(24/a)/(1-(24/a)²) = 50/a (48/a)/(...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
Sir Mike Ambrose is the author of the question. Let the single side length of the square be 2 unit. Calculating area S. It is; Area trapezoid of two parallel side lengths 2 unit and (2-√(3)...
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Mathematics Question and Solution

By OnlineEdumath   |  23rd June, 2024
a = 180-30-33 a = 117° b+117+15+33+30+39 = 360 b = 360-180-54 b = 126° c+126+30+9+39+57 = 360 c = 99° d = 180-99-9 d = 180-108 d = 72° e = a-57 e = 117-57 e = 60° f = 180-60-...
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We are smart and clever!

By OnlineEdumath   |  23rd June, 2024
Please, communicate us for effective Mathematics coaching/teaching/mentoring and learning activities online at affordable tuition.
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Mathematics Question and Solution

By OnlineEdumath   |  22nd June, 2024
Considering similar triangle (scalene) side length ratios.      n - 1 n+1 - n Cross multiply. Therefore; n²=n+1 n²-n-1=0 (n-½)²=1+¼ n =½±½(√(5)) Therefore; n ≠ ½(1-√(5)) n = ½(...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd June, 2024
Let length AB be x. A careful analysis carried out on the given composite plane shape lead to the derivation of right-angled tiangle EQX with hypotenuse QX ⅓(4x) and the two adjacent side of the...
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Mathematics Question and Solution

By OnlineEdumath   |  22nd June, 2024
Calculating x (length OD). a = (x+4) units. a is the radius of the quarter circle (length OA = length OB). It implies; (x+4)² = 8²+x² x²+8x+16 = 64+x² 8x = 48 x = 6 units. Again, x is...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2024
Area Coloured Region is; Area triangle with height and base 10 units - Area triangle with height and base 3√(2) units - Area triangle with height 5 units and base 7√(2)sin45 units = ½*10*10)...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2024
Calculating the area of the inscribed blue circle. a = ½(14+6) a = 10 units. a is the radius of the ascribed semi circle. b = a-6 b = 4 units. c²+4² = d² c is the radius of the inscrib...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2024
a² = 30²+40²-2*30*40cos150 a = 67.6643256752 units. (67.6643256752/sin(150)) = (30/sinb) b = 12.807876266° c = 83-b c = 70.192123734° It implies, the required length x is; x² = 50²+6...
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Mathematics Question and Solution

By OnlineEdumath   |  21st June, 2024
c²+12² = b² c = √(b²-144) units. For b = 15 units. c = √(15²-144 c = 9 units. tana = 12/9 a = atan(4/3)° cos(atan(4/3)) = 12/d ⅗ = 12/d d = 20 units. e = 24-d e = 4 units. It im...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2024
Let the single side length of the regular pentagon be 1 unit. Therefore; Area blue is; ½(sin108) square unit. Area red is; (1-cos36)sin108 square unit. Therefore; Area blue : Area...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2024
Coloured region is; Area triangle with height 6√(2) units and base 4.5sin45 units + Area triangle with height 3 units and base 5.65685424949sin45 units + Area triangle with height 1.5 units and...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2024
x = 6+7 x = 13 unit.
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2024
Sir Mike Ambrose is the author of the question. Area Red is; Area triangle with height 2 units and base 2sin(180-2ata(¾)) units. = ½*2*2sin(180-2ata(¾)) = 2sin(180-2ata(¾)) = 48/25 squar...
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2024
Calculating Shaded Black Area. a² = 9²+12² a = √(81+144) a = 15 units. a is the hypotenuse of the ascribed right-angled triangle. b = ½(a) b = 7.5 units. tanc = 9/12 c = atan(3/4)°...
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2024
a = ⅑*180(9-2) a = 140° a is the single interior angle of the regular nonagon. b = ½(180-140) b = 20° c = 140-20 c = 120° d = ½((180(5-2))-3*140) d = ½(540-420) d = ½(120) d = 60°...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2024
6² = a²+(2+3)² a² = 36-25 a = √(11) units. b² = 3²+c² b = √(9+c²) units. b is the diameter of the circle. d = c-a d = (c-√(11)) units. e² = 2²+(c-√(11))² e = √(4+c²-2c√(11)+11) e =...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2024
a = 0.5*5*5sin40 a = 8.0348451211 square units. (b/sin40) = (5/sin70) b = 3.4202014333 units.   c = 0.5*3.4202014333*3.4202014333sin40 c = 3.7595933295 square units. Shaded Area is: a...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2024
sin60 = 0.5d/a a = ⅓√(3)d units. a is the radius of the half circle. Therefore, total blue area in terms of d is; 2(60π*⅓√(3)d*⅓√(3)d/360)+(0.5*⅓√(3)d*⅓√(3)dsin120)-(0.5*⅓√(3)d*⅓√(3)dsin60)...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2024
a = ½(d) units. a is the radius of the green half circle. b = d+a b = ½(3d) units. c² = (½(3d))²-(½(d))² c² = ¼(8d²) c = √(2(d)²) c = √(2)d units. c is the diameter of the small blue se...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2024
Notice! Triangle ABM is equilateral. Calculating a:b. Let AB be 1 unit. c = 90-60 c = 30° cos30 = (0.5*1)/d d = ½÷½√(3) d = 1/√(3) d = ⅓√(3) units. d is the radius of the semi cir...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2024
a = ⅓(90) a = 30° sin30 = b/4 b = 2 cm. sin60 = c/4 c = 2√(3) cm. d = √(4²-2²)-√(4²-(2√(3))²) d = √(12)-√(4) d = (2√(3)-2) cm. d = 1.4641016151 units. Area Blue is; Area trapez...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2024
Let a be 1 unit. b = 1+(2*1)+1 b = 4 units. c = ½(b) c = 2 units. 2d² = 4² d² = 8 d = 2√(2) units. e² = 1²+(2√(2))²-2*2√(2)cos45 e = √(9-4) e = √(5) units. (√(5)/sin45) = (1/si...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2024
Let the side length of the inscribed square be a. Calculating the area of the inscribed red square. 2b² = a² b = ½√(2)a unit. c² = 2a² c = √(2)a unit. c is the diagonal of the inscribed...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2024
Calculating area of the inscribed blue half circle. a = ½(6+4) a = 5 units. a is the radius of the ascribed semi circle. b = a-4 b = 1 unit. c²+1² = d² d = √(c²+1) units. c is the rad...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2024
Notice! Triangle ABC is equilateral. Let AB be 1 unit. a = 180-42-12 a = 126° a is angle BDC. (1/sin126) = (b/sin42) b = 0.8270909153 units. b is CD. c² = 1+0.8270909153²-2*0.827...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2024
a² = 4²+1² a = √(17) units. b = a-1 b = (√(17)-1) units. b = 3.1231056256 units. c² = (√(17)-1)²+3² c² = 17-2√(17)+1+9 c = √(27-2√(17)) units. c = 4.3305644838 units. tand = (√(17)-1...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2024
a = 10+10 a = 20 cm. a is twice the radius of the quarter circle. b = ½(10) b = 5 cm. c² = 5²+10² c √(125) c = 5√(5) cm. Observing similar plane shape (right-angled triangle) side len...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2024
Calculating area of the blue a. b² = 2a² b = √(2)a cm. b is the diagonal of the blue square. c = 7-5 c = 2 cm. d = 7+5 d = 12 units. It implies; (√(2)a)² = 2²+12² 2a² = 148 a²...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2024
a = 2+2 a = 4 units. a is the radius of the quarter circle. b² = 4²-2² b² = 16-4 b = √(12) b = 2√(3) units. Therefore; Area triangle green is; ½*2√(3)*2 = 2√(3) square units.
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2024
Let the radius of the circle be a. b = (3+a) units. c = (8+a) units. d² = (3+a)²-a² d = √(9+6a) units. Observing similar plane shape (right-angled) side length ratios. a - √(9+6a)...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2024
Diameter of the ascribed circle is; 2R = 2*3 = 6 units. a²+2² = 6² a = √(32) a = 4√(2) units. Observing similar plane shape (right-angled) side length ratios. 3 - 4√(2) b - 2 Cros...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2024
Let the base of the ascribed triangle be 1 unit. a = 180-70-70 a = 40° (b/sin40) = (1/sin70) b = 0.6840402867 units. Considering similar plane shape (isosceles triangle) side length rati...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2024
a = 4+5 a = 9 units. b² = 9²+3² b = √(90) b = 3√(10) units. c = ½(b) c = ½(3√(10)) units. c is the radius of the quarter circle. d² = 5²-(½(3√(10)))² d = √(25-(45/2)) d = √(½(5)) d...
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2024
a = 180-(180-104)-60 a = 104-60 a = 44° b = 2a b = 88° Calculating x, the required angle. x = 180-88-(180-104) x = 92-76 x = 16° x is the required angle.
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2024
Let a be the radius of the ascribed semi circle. tanb = (3/4) b = atan(3/4)° It implies; 3² = 2a²-2a²cos(atan(3/4)) 9 = 2a²-(8a²/5) 9 = ⅕(2a²) 2a² = 9*5 a² = ½(9*5) a = ½(3√(10)) uni...
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2024
Let a be the radius of the inscribed half circle. b = (12+a) units. c = (12-a) units. It implies; (12+a)² = 12²+(12-a)² 144+24a+a² = 144+144-24a+a² 48a = 144 4a = 12 a = 3 units....
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2024
a² = 6²+4² a = √(36+16) a = √(52) a = 2√(13) units. a is AD = CD. tanb = 6/4 b = atan(3/2)° b is angle ADB. c = 180-b c = (180-atan(3/2))° c is angle BDC. Calculating x, length BC....
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Class with Ellis, year 2 pupil.

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Class with Vwarhe, js3 student (year 9).

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

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Class with Joshua, year 1 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Adesuwa, year 6 pupil.

Class with Adesuwa, year 6 pupil.

media video Class with Prince, year 5 pupil.

Class with Prince, year 5 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Class with Ellis, year 2 pupil.

Class with Ellis, year 2 pupil.

media video Mathematics and Science

Mathematics and Science

media video Identifying Prime Numbers

Identifying Prime Numbers

media video Quadratic Equation Using Formula

Quadratic Equation Using Formula

media video Introduction to Decimals

Introduction to Decimals

media video Constructing and Bisecting Lines and Angles

Constructing and Bisecting Lines and Angles

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Math Story

media video Mathematics is not difficult, it is a language

Mathematics is not difficult, it is a language

media video Comparing Numbers

Comparing Numbers

media video Place Value

Place Value

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Telling Time

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Young Sheldon

media video Young Sheldon

Young Sheldon

media video Young Sheldon

Young Sheldon

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Student Bullied For Being Dumb, Turns Out He's Genius Neurosurgeon

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Maths at The Mela

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Math Story

media video The Map of Mathematics

The Map of Mathematics

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Mathematics Knowledge

media video Math Story

Math Story

Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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