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OnlineEdumath

Year of Establishment
March, 2020

6
 Experienced Faculty

We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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Our Updates

We are smart and clever!

By OnlineEdumath   |  5th November, 2024
“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach
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Welcome to Online Edumath

By OnlineEdumath   |  4th September, 2024
This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...
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We are smart and clever!

By OnlineEdumath   |  3rd July, 2024
For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992  We are kindly to respond to your question(s)/...
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Thank You, Sir Bill.

By OnlineEdumath   |  18th April, 2024
The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...
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We are smart and clever!

By OnlineEdumath   |  18th April, 2024
Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...
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Mr. Daniel (Mathematics Educator)

By OnlineEdumath   |  26th August, 2023
Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2025
Calculating Blue Area. a = 8+2 a = 10 units. a is the side length of the ascribed square and the radius of the bigger inscribed quarter circle. b = 8 units. b is the radius of the big insc...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2025
Let angle AOB be a. Let b = AD = OB = OD. b is the radius of the quarter circle. Calculating b. 2² = 2b²-2b²cosa 2b²cosa = 2b²-4 b²cosa = b²-2 cosa = (b²-2)/b² --- (1). 4² = b²+(2b)²-4b²cosa 16...
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Mathematics Question and Solution

By OnlineEdumath   |  20th June, 2025
Let r = 1 unit. a = (R+1) units. b = (R-1) units. c²+b² = a² c²+(R-1)² = (R+1)² c² = R²+2R+1-(R²-2R+1) c = √(4R) c = 2√(R) units. d = R+2-R d = 2 units. e = R+R e = 2R units. Calculating R....
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2025
Notice. The ascribed quadrilateral is regular (square). Let a be it's side length. ½*ab = 3 ab = 6 b = (6/a) units. b is the base of the red area. ½*ac = 4 ac = 8 c = (8/a) units....
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2025
tan60 = a/(0.5*8) a = 4tan60 a = 4√(3) cm. a is the diameter of the circle. b = ½(a) b = 2√(3) cm. b is the radius of the circle. c = ¼(8) c = 2 cm. c is the radius of the two equal half circles....
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Mathematics Question and Solution

By OnlineEdumath   |  19th June, 2025
a = 4+4 a = 8 units. a is the radius of the quarter circle. cosb = ⅛(0.5*4) b = acos(¼)° cosb = c/8 c = 8cos(acos(¼)) c = ¼(8) c = 2 units. c is the width of the inscribed rectangle. sinb = d/8...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2025
Let AD = BC = 1 unit. a = 180-100-30 a = 50° a is angle BAC. (1/sin50) = (b/sin30) b = 0.65270364467 units. b is AC. Therefore, the required angle theta is, let it be c. (0.65270364...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2025
Let BD = CD = 1 unit. a = 180-45-30 a = 105° a is angle CAD. (1/sin105) = (b/sin45) b = 0.73205080757 units. b is AC. c² = 0.73205080757²+2²-2*2*0.73205080757cos30 c = 1.41421356237 units. c is A...
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Mathematics Question and Solution

By OnlineEdumath   |  18th June, 2025
a = 180-60 a = 120° b = 180-120-45 b = 15° (1/sin15) = (c/sin45) c = 2.73205080757 units. sin60 = d/c d = 2.73205080757sin60 d = 2.36602540378 units. cos60 = e/c e = 2.73205080757...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2025
Area blue is; 2(area quarter circle with radius 8 cm - area isosceles right-angled triangle with equal lengths 8 cm) + 2(area quarter circle with radius 4 cm - area isosceles right-angled triang...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2025
Notice. 10 m is the radius of the circle. a = 10-3 a = 7 m. sinb = (7/10) b = asin(7/10)° Calculating length AB. tanb = 10/(AB) AB = 10/(tanb) AB = 10/tan(asin(7/10)) AB = 10.2020406122 m. Or...
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Mathematics Question and Solution

By OnlineEdumath   |  17th June, 2025
Calculating angle x. Let the longest ascribed quadrilateral side length be 1 unit. a = = 180-25-2(35) a = 180-95  a= 85° (1/sin85) = (b/sin25) b = 0.42423259484 units. c = 180-35-2(25) c = 180-8...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2025
Calculating Area Triangle A. Let the two equal inscribed angles be a each. (0.5*14*12sina)÷(0.5*12*35sina) = 14/35 = 2/5 = 2:5 Where 2:5 is the ratio of the bases of the both triangles wi...
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Mathematics Question and Solution

By OnlineEdumath   |  16th June, 2025
b = √(a) b = √(48) b = √(16*3) b = 4√(3) units. b is the radius of the ascribed quarter circle. c = ½(b) c = 2√(3) units. c is the radius of the inscribed half circle. tan30 = d/c ⅓√(3) = d/(2√(3)...
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2025
Calculating angle x. a = 3-1 a = 2 units. a is CD. tanb = 3/1 b = atan(3)° b is angle BCF equal angle ACD. It implies; ((⅕(3√(10)))/sin(atan(3))) = (2/sinc) c = asin(1) c = 90° c...
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Mathematics Question and Solution

By OnlineEdumath   |  15th June, 2025
Let a be 1 unit. e = ½(180-45) e = 67.5° tane = 1/f f = 1/tan(67.5) f = 0.41421356237 units  g = 1-f g = 1-0.41421356237 g = 0.58578643763 units. 2h² = a² 2h² = 1 h = ½√(2) units...
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Mathematics Question and Solution

By OnlineEdumath   |  14th June, 2025
Let the ascribed square side length be 1 units. Calculating area red inscribed circle. a = (1-b) units. Where b is the radius of the red inscribed circle  sin30 = b/(1-b) 2b = 1-b 3b =...
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Mathematics Question and Solution

By OnlineEdumath   |  14th June, 2025
Let a be the radius of the inscribed pink circle. b = (a+7) units. c = (7-a) units. d = (a-2) units. Calculating a. It implies; a ~ (a+7) (a-2) ~ (7-a) Cross Multiply. a(7-a) = (a-2)(a+7) 7a...
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Mathematics Question and Solution

By OnlineEdumath   |  13th June, 2025
Let 2 units be the side length of the ascribed square. Therefore; a = 1 units. a is the radius of the inscribed circle. Calculating angle x. b² = 2(1)² b = √(2) units. c = ½(b) c...
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Mathematics Question and Solution

By OnlineEdumath   |  13th June, 2025
Notice. Radius of the inscribed half circle is 5 units. tana = 10/5 a = atan(2)° b = 2a b = 2atan(2)° c = ½(180-b) c = ½(180-2atan(2)) c = 90-atan(2) c = atan(½)° It implies; tanc = d/5 tan(at...
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Mathematics Question and Solution

By OnlineEdumath   |  12th June, 2025
Calculating shaded area. tana = 10/5 a = atan(2)° b = 2a b = 2atan(2)° c = 180-b c = (180-2atan(2))° d = ½(c) d = (90-atan(2)) d = atan(0.5)° It implies; tan(atan(0.5)) = e/5...
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Mathematics Question and Solution

By OnlineEdumath   |  12th June, 2025
a² = r²+(½(r))² a = ½√(5)r units. 2r ~ ½√(5)r b ~ ½(r) Cross Multiply. ½√(5)rb = r² √(5)rb = 2r² b = 2r/√(5) b = ⅕(2√(5))r units. b is the height of the inscribed triangle. c²+b²...
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Mathematics Question and Solution

By OnlineEdumath   |  11th June, 2025
Let a be the radius of the circ. Calculating a. b = ½(12+2) b = 7 units. c = ½(4+6) c = 5 units. d = b-2 d = 7-2 d = 5 units. It implies; a² = c²+d² a = √(5²+5²) a = √(50)...
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Mathematics Question and Solution

By OnlineEdumath   |  11th June, 2025
Let a be the radius of the white inscribed circle. b = (10-a) units. Calculating a. b² = a²+5² (10-a)² = a²+25 100-20a+a² = a²+25 75 = 20a a = ¼(15) units. a = 3.75 units. c = ½(10)  c = 5 units...
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Mathematics Question and Solution

By OnlineEdumath   |  11th June, 2025
Let a be the radius of the half circle. b = (a-1) units. c²+1² = b² c² = a²-2a+1-1 c = √(a²-2a) units. d = a+c  d = (a+√(a²-2a)) units. d is the required length. e = (a+1) units....
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Mathematics Question and Solution

By OnlineEdumath   |  10th June, 2025
x+a = y+2a 4+a = 3+2a a = 1 unit. It could be; a = √(4²+3²)-4 a = 5-4 a = 1 unit. Or 2a = √(4²+3²)-3 2a = 5-3 a = 1 unit. Which makes; b = y+a b = 4+a And a = 1 unit. b = 5 units. Or b = y+2a b =...
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Mathematics Question and Solution

By OnlineEdumath   |  10th June, 2025
c² = 5³+12² c = √(169) c = 13 units. Calculating a, radius of the inscribed yellow circle. 5a+12a+13a = (12*5) 30a = 60 a = 2 units. Calculating b, radius of the blue inscribed circle....
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Mathematics Question and Solution

By OnlineEdumath   |  10th June, 2025
a²+m² = 12² a = √(144-m²) units. Calculating m. (4m)² = (3m)²+√(144-m²)² 16m² = 9m²+144-m² 8m² = 144 2m² = 36 m² = 18 m = 3√(2) units. Recall. a = √(144-m²) And m = 3√(2) units. a = √(144-(3√(2)...
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Mathematics Question and Solution

By OnlineEdumath   |  10th June, 2025
Notice. 4 units is the radius of the inscribed circle. a² = 2(4)² a = 4√(2) units. 8² = (4√(2))²+4²-2*4*4√(2)cosb 64 = 32+16-32√(2)cosb 32√(2)cosb = 48-64 cosb = -16/(32√(2)) b = acos(-1/(2√(2)))...
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Mathematics Question and Solution

By OnlineEdumath   |  10th June, 2025
a²+9² = 15² a = √(15²-9²) a = 12 units. a is AF. c = (9-b) units. Therefore; 12 ~ b 9 ~ (9-b) Cross Multiply. 108-12b = 9b 21b = 108 b = ⅐(36) units. b is the radius of the inscribed half circl...
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Mathematics Question and Solution

By OnlineEdumath   |  9th June, 2025
Calculating x, length DE. a = ½(6)+x a = (3+x) units. Therefore; Length DE, x is; a = 8 3+x = 8 x= 8-3 x = 5 units.
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Mathematics Question and Solution

By OnlineEdumath   |  9th June, 2025
Calculating yellow area. It implies; 2a² = 4² Where a is the height of the yellow area. Therefore; 2a² = 4² 2a² = 16 a² = 8 a = √(8) a = 2√(2) units. Area Yellow is; ½*a*6 =...
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Mathematics Question and Solution

By OnlineEdumath   |  9th June, 2025
Calculating angle x. Let the two equal lengths be 1 unit each. (1/sin(180-24-30)) = (a/sin30) a = 0.61803398875 units. b = 1+a b = 1.61803398875 units. c = 24+30 c = 54° (1/sin(180-...
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Mathematics Question and Solution

By OnlineEdumath   |  9th June, 2025
Calculating the required angle, let it be x. Let a be the side length of the ascribed square. ½(ab) = 1 b = 2/a --- (1). 1+1+c = ½(a²) c = ½(a²)-2 c = ½(a²-4) square units. d = a-b...
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Mathematics Question and Solution

By OnlineEdumath   |  8th June, 2025
Calculating x. Let a be the height of the inscribed isosceles triangle. b = ½(7)+7 b = 10.5 units. c² = 10.5²+a² c = √(a²+110.25) units. Let d be one of the two equal inscribed angles. cosd = 1...
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Mathematics Question and Solution

By OnlineEdumath   |  8th June, 2025
Let a be the side length of the red inscribed square. b = (4-a) cm. Therefore; 4² = 2b² 4² = 2(4-a)² 16 = 2(16-8a+a²) 8 = 16-8a+a² a²-8a+8 = 0 (a-4)² = -8+(-4)² (a-4)² = 16-8 a = 4±√(8) a ≠ (4+2√...
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Mathematics Question and Solution

By OnlineEdumath   |  8th June, 2025
Calculating x. sina = 3.5/12.5 a = asin(3.5/12.5)° b = 2a b = 2asin(3.5/12.5)° sinc = 10/12.5 c = asin(10/12.5)° d = 2c d = 2asin(10/12.5)° e = 180-b-d e = 180-2asin(3.5/12.5)-2asin(10/12.5) e...
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Mathematics Question and Solution

By OnlineEdumath   |  8th June, 2025
cosa = (2√(5))/(3√(5)) a = acos(⅔)° a is angle PRT. tana = 25/b b = 25/(tan(acos(⅔))) b = 22.360679775 units. b = 10√(5) units. Therefore, area triangle TRP is; ½*25b = ½*25*10√(5) = 125√(5) squa...
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Mathematics Question and Solution

By OnlineEdumath   |  8th June, 2025
Let the radius of the ascribed half circle be 1 unit. a² = 2x² a = √(2)x units. b²+1² = a² b = √(2x²-1) units. c = 1-b c = (1-√(2x²-1)) units. d = ½(c) d = ½(1-√(2x²-1)) units. e...
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Mathematics Question and Solution

By OnlineEdumath   |  7th June, 2025
Let a be the radius of the circle. b² = 2(2)² b = √(8) b = 2√(2) cm. c = (2√(2)-a) cm. It implies; 2a² = c² 2a² = (2√(2)-a)² 2a² = 8-4√(2)a+a² a²+4√(2)a-8 = 0 (a+2√(2))² = 8+(2√(2...
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Mathematics Question and Solution

By OnlineEdumath   |  7th June, 2025
Let the bigger inscribed semi circle radius be 2 units. Let the big inscribed semi circle radius be r. Let the inscribed circle radius be q. Calculating r. (2+r)² = 2²+(4-r)² 4+4r+r²...
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Mathematics Question and Solution

By OnlineEdumath   |  7th June, 2025
Let a be the radius of the circle. 2πa = 14π a = 7 cm. Calculating x. cos49 = b/7 b = 7cos49 b = 4.59241320293 cm. c = 2b c = 9.18482640587 cm. c is CD  d = 180-49-37.5 d = 93....
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Mathematics Question and Solution

By OnlineEdumath   |  6th June, 2025
Calculating Total Shaded Area, Area Grey, Purple and Blue. Notice. KLMN is a square. Calculating area grey. a = 6-4 a = 2 units. sinb = 2/6 b = asin(⅓) b = 19.4712206345° c²+2² = 6² c = 4√(2) u...
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Mathematics Question and Solution

Mathematics Question and Solution

By OnlineEdumath   |  6th June, 2025
Sir Mike Ambrose is the author of the question. tan30 = a/3 a = √(3) units. b = a+3 b = (3+√(3)) units. tan30 = c/b ⅓√(3) = c/(3+√(3)) c = ⅓(3√(3)+3) units. c = (1+√(3)) units. It im...
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Class with Ellis, year 2 pupil.

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Class with Ellis, year 2 pupil.

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Mathematics and Science

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Identifying Prime Numbers

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Quadratic Equation Using Formula

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Constructing and Bisecting Lines and Angles

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Math Story

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Mathematics is not difficult, it is a language

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Comparing Numbers

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Young Sheldon

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Young Sheldon

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Maths at The Mela

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Math Story

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Learner's Feedback/Testimonial


Sir, my first term Mathematics result, I scored 99% and got first position

Ogheneruno

Ogheneruno

Online Edumath

Learner's Feedback/Testimonial


Sir, I was the third best pupil in class out of 30 pupils at the end of Autumn assessment

Prince

Prince

Online Edumath

Learner's Feedback/Testimonial


I was awarded Century Champion Award certificate as a celebrated Century Champion for completing my Century Work in Mathematics in my School

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


My Math Teacher in school do sometimes administer year 6 Math assessment to me, a year 5 pupil, and I often score 100%

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I got Bronze Certificate representing my School in the junior (year 7 and 8) Mathematics Challenge Competition, 2023 organized by United Kingdom Mathematics Trust. Oghosa is in year 7

Oghosa

Oghosa

Online Edumath

Learner's Feedback/Testimonial


Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Adesuwa

Adesuwa

Online Edumath

Learner's Feedback/Testimonial

I scored 92% in Mathematics in my third term final Mathematics Examination assessment, Sir.

Ogheneruemu

Ogheneruemu

Online Edumath

Learner's Feedback/Testimonial

Sir, I got A+, the highest score in my final summer Mathematics assessment score in my class.

Oghosa

Oghosa

Online Edumath

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