“Mathematics is the most beautiful and most powerful creation of the human spirit.”

Stefan Banach

“To not know math is a severe limitation to understanding the world.” Richard Feynman

Math solutions and review, a good medication for the brain.

“The study of mathematics, like the Nile, begins in minuteness but ends in magnificence.”

Charles Caleb Colton

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OnlineEdumath

Year of Establishment
March, 2020

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We mentor/educate/teach learners Mathematics online via Google Meet App. Our Certified, Resilient and Productive Mathematics Educators make teaching and learning Mathematics fun for learners. Communicate us to mentor your child/children to become a lover of Mathematics, and a Mathematician

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We are smart and clever!

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We are smart and clever!

By OnlineEdumath | 5th November, 2024

“Mathematics is the most beautiful and most powerful creation of the human spirit.” Stefan Banach

Welcome to Online Edumath

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Welcome to Online Edumath

By OnlineEdumath | 4th September, 2024

This is Online Edumath website created by Ogheneovo Daniel Ephivbotor. Online Edumath falls in EDUCATION line of business. You can visit us offline at our office located at : Lugbe, Federal...

We are smart and clever!

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We are smart and clever!

By OnlineEdumath | 3rd July, 2024

For enquiry on what we do and on our shared Mathematics Questions and Solution review, please communicate us via our WhatsApp contact: +2349076614992 We are kindly to respond to your question(s)/...

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Thank You, Sir Bill.

By OnlineEdumath | 18th April, 2024

The Management and Educators of Online Edumath kindly appreciate your words of affirmation and encouragement, Sir Bill. We are grateful! We pledge to keep working hard as we mentor/educate our lea...

We are smart and clever!

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We are smart and clever!

By OnlineEdumath | 18th April, 2024

Online Edumath Educators and Learners are Super Smart and Amazingly, Very Clever. Communicate us to mentor/teach/educate your child/children Mathematics online at affordable tuition, helping them be...

Mr. Daniel (Mathematics Educator)

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Mr. Daniel (Mathematics Educator)

By OnlineEdumath | 26th August, 2023

Mr. Daniel is one of our Educators, He is a certified, hardworking, dedicated and passionate Mathematics Educator that aim at taking the sincere, profound knowledge of Mathematics to the comfort of...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 10th May, 2025

Radius R of the big circle is 50 unit. (R-10)²=R(R-18) R²-20R+100=R²-18R 2R=100 R=50 units. Radius r of the small inscribed unshaded circle is 41 unit. 2r=2R-18, and R=50 2r=100-18 2r=82...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th May, 2025

Let the radius of the ascribed quarter circle be 2x. Therefore the radius of the inscribed yellow half circle is x. Calculating x. ¼(π(2x)²)-½(πx²) = 17 πx²-½(πx²) = 17 2πx²-πx² = 34...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th May, 2025

a = 180-30-45 a = 105° (1/sin105) = (b/sin30) b = 0.51763809021 units. c = √(2)-b c = 0.89657547217 units. (0.89657547217/sin105) = (d/sin30) d = 0.46410161514 units. It implies, ar...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th May, 2025

a = (r+R) b = (R-r) It implies; 8²+b² = a² R²+2Rr+r² = 64+R²-2Rr+r² 4Rr = 64 Rr = 16 R = 16/r --- (1). It implies; a = r+(16/r) a = (16+r²)/r b = (16/r)-r b = (16-r²)/r The...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th May, 2025

Each of the triangles is equilateral with single side length; (√(24)÷3^(1/4)) units. Total yellow area will be; (√(24)÷3^(1/4))²x(3/4)x0.5sin60 + (√(24)÷3^(1/4))²x(2/3)x(0.5)²sin60 + (√(24...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th May, 2025

Diameter of circle Z will be; ½(Diameter of the ascribed circle - length of the inscribed square) = ½(√(16²+16²) - 16) = ½(16√(2)-16) = (8√(2)-8) cm The radius of circle Z will be;...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th May, 2025

The required angle is; 180° - (11.25°+33.75°) = 180° - 45° = 135°

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th May, 2025

Let the single side length of the regular pentagon be 4 unit. Therefore angle x degree will be; Sinx = (2/4) Sinx = ½ Therefore; x = sin–¹(½) x = 30°

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 4th May, 2025

Let R be radius of the quarter circle. Let r be radius of the inscribed circle. R will be; √(3²+4²) R=√(25) R= 5 units. Therefore r will be; (5-r)²=(3+r)²+r² 25-10r+r²=9+6r+r²+r...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 3rd May, 2025

Kindly move the question right/left twice to review the complete solution. Thank you amazingly.

Mathematics Question and Solution.

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Mathematics Question and Solution.

By OnlineEdumath | 3rd May, 2025

Sir Mike Ambrose is the author of the question. Exact Area R in its simplest from will be; Area semi circle of radius 2 units - Area right-angled triangle of height 2√(2+√(2)) units and width 2√...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 2nd May, 2025

Blue Area is; Area square of single side 4cm - 2(area circle of radius 1cm) - 8(area square of single side 1cm) + 8(area quarter circle of radius 1cm). = 16 - 2π - 8 + ¼(8π) = 8 - 2π + 2π...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 1st May, 2025

Blue Area will be; Area square of single side 4cm - 3(Area circle of radius 1cm) It will be; (4x4) - 3(1²(π)) It is; 16 - 3π Answer is; (16-3π) square units.

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 30th April, 2025

The radius of the circle with the inscribed square will be; ½(√(4²+4²)) = ½(√(32)) = ½(4√(2)) = 2√(2) cm. Therefore Blue Area will be; 2(area circle of radius 2cm) - area circle o...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 29th April, 2025

Shaded/green area will be; Area semi circle of radius 9unit - 2(area sector of radius 9unit and angle 60°) + area equilateral triangle of single side length 9unit - area sector of radius 9unit a...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 28th April, 2025

Notice; Single interior angle of a regular polygon with 6 sides (regular hexagon) is 120°. The formula to get it is; (180°(n-2))/n. Where n is the side number of the regular polygon....

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 27th April, 2025

Let the radius of the bigger circle be 2 unit. Therefore the radius of the smaller circle will be; ½(2)=1 unit. Let the radius of the semi circle be r. It implies; 2² + r² = (1 + r)²...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 26th April, 2025

Blue area will be; Area square of single side length 4cm - 5(area circle of radius 1cm) + area square of single side 2cm. = 16 - 5π + 4 = 20 - 5π = 5(4 - π) cm²

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 25th April, 2025

Let x be a side length of the largest possible inscribed square of the scalene triangle with sides 13 cm, 14 cm and 15 cm respectively. It implies; x = 14÷((1/tan(53.13))+1+(1/tan(67.38)))...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 24th April, 2025

Calculating x (radius of the small inscribed circle) 28² + x² = (56-x)² 784 + x² = 3136 - 112x + x² 112x = 2351 x = 21 units.

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 23rd April, 2025

Calculating r, radius of the four congruent circles. Area square with side 2r cm - Area circle with radius r cm = Area green. (2r)² - πr² = 144π 4r² - πr² = 144π (4-π)r² = 144π r² =...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 22nd April, 2025

Area Area Blue is; Area semi circle with radius √(2) units - Area quarter circle with radius 2 units + Area triangle with height and base 2 units respectively. = ½(√(2)²)π - ¼(2²)π + ½(2²)...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 21st April, 2025

Area Blue is; Area triangle with height 4 cm and base (4sin150) cm = ½*4*(4sin150) = 2(4sin150) = 8sin150 = ½(8) = 4 cm²

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 20th April, 2025

Shaded Area is; Area circle with diameter 30 cm - 7(area circle with diameter 10 cm) = π(½(30))² - 7π(½(10))² = π(15)² - 7π(5)² = 225π - 175π = 50π cm²

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 19th April, 2025

Sir Mike Ambrose is the author of the question. Let CD = 2 units. Therefore; Calculating AB. AB = 1 + (2sin18*tan72 + 2sin36)tan54 AB = 1 + 3.07768353717tan54 AB = 1 + 4.23606797749...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 18th April, 2025

x² = (r+1)² - (r-1)² Therefore x = 2√(r) unit. y² = (r+1)² - (2√(r))² Therefore y = √(r²-2r+1) y = √(r-1)² y = (r-1) unit z = (r+1) - y z = (r+1) - (r-1) Therefore z = 2 units a = r+...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 17th April, 2025

Area R is; Area sector with radius 8 cm and angle 20.16632290743° - Area triangle with height 8 cm and base (4.2sin 20.16632290743) cm = ( 20.16632290743 *64π÷360) - (½*8*4.2sin 20.166322907...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 16th April, 2025

Area coloured is; Area sector with radius 3 units and angle 120° - Area triangle with height 3 units and base 3sin120 units + Area triangle with height 3 units and base 3sin60 = (120*9π÷360)...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 15th April, 2025

Shaded area is; Area sector with radius 10 cm and angle 60° (100π*60)/360 = (100π)/6 = ⅓(50π) cm²

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 14th April, 2025

Let the side length of the regular heptagon be 1 unit. a = ⅐(180*5) a = ⅐(900)° b = 0.5(360-2(900/7)) b = ⅐(360)° c = 2cos(360/7)+1 c = 2.24697960372 units. d² = 2-2cos(90/7) d = 1....

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 11th April, 2025

18² = 14²+16²-2*14*16cosa 448cosa = 14²+16²-18² a = acos((14²+16²-18²)/448) a = 73.39845040098° (18/sin73.39845040098) = (14/sinb) b = 48.18968510422° c = 180-48.18968510422-73.3984504009...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 10th April, 2025

8 = 4 a = (8-a) Cross multiply. 64-8a = 4a 64 = 12a a = ⅓(16) cm. b = 8-a b = ⅓(8) cm. c = atan(⅔)° d = atan(3/2)° ⅔ = 8/e e = 12 cm ⅔ = f/8 f = ⅓(16) cm. g = 8-f g = ⅓(...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 9th April, 2025

Area coloured regions is; Half the area of the ascribed square. = ½(2*2) = 2 square units.

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 8th April, 2025

Sir Mike Ambrose is the author of the question. Let AC = 2 units. Therefore; AB = ⅖ unit. BC = (8/5) unit. It implies; Area Blue is; Area triangle with height ⅖ unit and base 2si...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 7th April, 2025

Let AC be 1 unit. Area smaller pentagon is; ½(5)*(1/(2tan(36))) = 1.72047740059 square units. a² = 1²+0.5²-cos108 a = 1.24860602048 units. Where a is CD. (1.24860602048/sin108) =...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 6th April, 2025

Sir Mike Ambrose is the author of the question. Area R is; Area triangle with height 4 cm and base (4tan52.5) cm - Area sector with angle 52.5° and radius 4 cm. = ½*4(4tan52.5) - (52.5*4*4π)...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 5th April, 2025

a² = 10²+16²-2*10*16cos120 a = 2√(129) units. Where a is length AC. (3√(129)/sin120) = (16/sinb) b = 37.58908946897° c = 90-b c = 52.41091053103° d = 60-b d = 22.41091053103° e...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 4th April, 2025

Let the radius of the inscribed half circle be 1 unit. Area rectangle is; 2*1 = 2 square units. Calculating Shaded Area as a single fraction.. It is; ½(1*2) - 1² + ¼(1)²π - ((180-2a...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 3rd April, 2025

Let the two congruent lengths be 1 unit. tan40 = a/1 a = 0.83909963118 unit. cos40 = 1/b b = 1.30540728933 units. Calculating r, radius of the red inscribed circle. (r/tan(20)) + (r/t...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 2nd April, 2025

Let the radius of the semi circle be 1 unit. cos20 = a/2 a = 1.87938524157 units. cos20 = 1/b b = 1.06417777248 units. c = a-b c = 0.81520746909 unit. Where c is AB, the side of the...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 1st April, 2025

Let the side of the regular pentagon be 1 unit. Calculating Area Red. a² = 1²+1²-2*1*1cos108 a = 1.61803398875 units. b = 108-36-60 b = 12° (c/sin12) = (1.61803398875/sin96) c = 0.33...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 31st March, 2025

a² = 15²+12²-2*12*15cos120 a = 23.43074902772 cm. Where a is the side length of the equilateral triangle ABC. (23.43074902772/sin120) = (12/sinb) b = 26.32950349168° c = 60-b c = 33.67...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 30th March, 2025

Sir Mike Ambrose is the author of the question. Let the side length of triangle ABC be 1 unit. a = 120-78 a = 42° b = 60-42 b = 18° (1/sin42) = (c/sin18) c = 0.4618186516 unit. tan6...

Mathematics Question and Solution

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Mathematics Question and Solution

By OnlineEdumath | 29th March, 2025

a² = 12²+6² a = 6√(5) cm. a = AE. b = atan(1/2)° b = angle DAE. c = 180-atan(2) c = 116.56505117708° c = angle AFC. d = 180-116.56505117708-atan(1/2) d = 36.86989764584° (6/sin36....

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