By OnlineEdumath   |  9th June, 2023
Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplicit...
By OnlineEdumath   |  9th June, 2023
Screenshot of yesterday's teaching and learning activities with super smart and clever Adesuwa (year 5), and Oghosa (year 7). Educators; Mr. Daniel, Mr. Ovo We are smart and clever.
By OnlineEdumath   |  9th June, 2023
a² = 6²-1² a = √(35) units. b = atan(√(35)) cos(atan(√(35))) = c/2 c = ⅓ unit. Where c is CE. d = atan(√(35))-60 d = 20.40593177314° Where d is angle FCE. tan20.40593177314 = e/(1/3) e = 0.12400...
By OnlineEdumath   |  8th June, 2023
EG = DG = ½√(12²+6²) EG = DG = 3√(5) cm. Ang CDE = atan(½) It's implies; (CG)² = 45+144-2*36√(5)cos(atan(½)) CG = 3√(5) cm. CG = 6.7082039325 cm. tan(atan(½)) = a/6 a = 3 cm. b = 12-3 b = 9 cm....
By OnlineEdumath   |  8th June, 2023
Calculating angle ABD. Let it be a. Using cosine rule. 25 = 36+9-2*18cosa 36cosa = 45-25 a = acos(20/36)° a = acos(5/9)° Calculating x. Using cosine rule. x² = 36+144-2*6*12cos(acos(5/9)) x² =...
By OnlineEdumath   |  8th June, 2023
BC = √(√(3)²+1²) BC = 2 units. Let r be the radius of the circle. Using similar triangles ratio rule on triangle ACE and triangle BCE to calculate r. 1 = √(3) √(3) = AE Cross Multiply. AE= 3 un...
By OnlineEdumath   |  8th June, 2023
Let the square side be a. tan60 = a/b b = a/tan60 cm. Where b is BS. Calculating a. 2b+a = 6 2(a/tan60)+a = 6 a((2/tan60)+1) = 6 a = 6/((2/tan60)+1) a = 6(2√(3)-3) cm. Area Shaded STR is; ½(a²)...
By OnlineEdumath   |  8th June, 2023
Screenshot of today's teaching and learning activities with Prince, he is in year 4. Educator: Mr. Ogheneovo Prince is super smart and clever.
By OnlineEdumath   |  7th June, 2023
Our certified, experienced, resilient, productive and committed Math Educators will be glad to be at your service. We make teaching and learning Mathematics fun for learners, we expose the simplic...
By OnlineEdumath   |  7th June, 2023
Notice; Diameter of the ascribed semi circle is 20 cm. Radius, r will be 10 cm. Calculating Area Shaded. It will be; Area half circle with radius 10 cm - 2(area semi circle with radi...
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