Let x be 4 units.
Calculating total blue length of arc.
It implies;
½(circumference of a circle with radius 2 units + circumference of a circle with radius 1 unit + circumference of a circle with...
Sir Mike Ambrose is the author of the question.
P coordinate is;
P(3, 9)
Q coordinate is;
Q(2, 5), Q(3, 5)
It implies;
Shaded area exactly in its square units simplest form is;
(Area under the...
Sir Mike Ambrose is the author of the question.
Calculating the circle's radius, r.
The radius of the circle is;
Area triangle with base 21 cm and height r cm + Area triangle with base 15 cm and h...
3²+4²+2*3*4cosa = 5²+6²-2*5*6cosa
25+24cosa = 61-60cosa
84cosa = 36
cosa = (36/84)
cosa = (3/7)
a = acos(3/7)
a = 64.6230664748°
b = 2a
b = 129.2461329497°
c² = 5²+6²-2*5*6cos64.6230664748
c = 5.9...
Calculating the shaded area.
a² = 4²+6²-2*4*6cos30
a = 3.2296719057 units.
sin15 = b/6
b = 1.5529142706 units.
c = 90-15
c = 75°
Or
cosc = 1.5529142706/6
c = acos(1.5529142706/6)
c = 75°
(3.22...
2r² = 2²
r = √(2) units.
r is the radius of the circle.
Area circle is;
πr²
= π√(2)²
= 2π square units.
Sir Mike Ambrose is the author of the question.
Let the radius of the ascribed semicircle be 2 units.
Therefore;
Radius of the inscribed circle is 1 unit.
It implies;
Area R is;
Area sector with...
Length DG is;
cos15 = 0.5(12)/(DG)
DG = 6/cos15
DG = 6.21165708246 cm.
x = 12.416666 - (1).
10x = 124.16666 - (2).
100x = 1241.6666 - (3).
1000x = 12416.6666 - (4).
Subtracting (3) from (4).
900x = 11175
It implies x (p/q) is;
x = 11175/900
x = 2235/180
x = 447/36
x...
a² = 4²+2²
a² = 20
a = √(20)
a = 2√(5) units.
tanb = 2/4
b = atan(½)°
b is angle theta.
c = 180-2b
c = (180-2atan(½))°
d = 360-90-c-b
d = 360-90-(180-2atan(½))-atan(½)
d = (90+atan(½))°
e² = √(...
