You Searched for "j2"

61 result found.

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2030918

mathematics-question-and-solution_1691223890nbCPKa.jpeg
Let AO be 1 unit. AB will be 2 units. Therefore, radius r of the ascribed semi circle is; = 3 units. Area semi circle is; ½(3²)π = ½(9π) square units. tana = (1/3) a = atan(⅓)° b = (180-2atan(½))° c = b-90 c = (180-2atan(⅓)°))-90 c = (90-2atan(⅓))° sin(90-2atan(⅓)) = d/1 d = (4/5) units. cos(90-2atan(⅓)) = e/1 e = (3/5) units. f = r-e f = 3-(3/5) f = (12/5) units. g² = 3²-(3/5)² g² = 9-(9/25) g = ⅕(6√(6)) units. h = g-d h = ⅕(6√(6))-(4/5) h = ⅕(6√(6)-4) units. j² = d²+f² j² = (4/5)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2027792

mathematics-question-and-solution_1691114948r4Tp98.jpeg
Sir Mike Ambrose is the author of the question. ⅓(4) = a/9 a = 12 cm. let alpha be b. Calculating b. (2tanb/(1-tan²b)) = (4/3) 2tan²b+3tanb-2= 0 b = atan(½)° ½ = c/9 c = 4.5 cm. d = ½(12-c) d = 3.75 cm. ½ = 3.75/e e = 7.5 cm f² = 8.25²+7.5² f = 11.14955156049 cm. g = ½(90-atan(½))° g = 31.71747441146° h = 90-31.71747441146-atan(8.25/7.5) h = 10.55621459463°  Let r be the radius of the inscribed circle. sin31.71747441146 = r/i i = 1.90211303259r  j²...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/2020152

mathematics-question-and-solution_1690877100njWcgP.jpeg
Let AB be 1 unit. Therefore; BC = 2 units. It implies, the regular hexagon side length is 3 units. a = 120-108 a = 12° b² = 2²+3²-2*2*3cos12 b = 1.1234895599 units. (1.1234895599/sin12) = (2/sinc) c = 21.72287686377° d = 120-c d = 120-21.72287686377 d = 98.27712313623° Calculating Length Blue. Let it be e. e² = 3²+1.1234895599²-2*3*1.1234895599cos98.27712313623 e = 3.35151630086 units. f = 180-12-21.72287686377 f = 146.27712313623° (3.35151630086/sin98.27712313623) = (3/sing) g = 62...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1996244

mathematics-question-and-solution_1690109604zQR17p.jpeg
Let the radius R, of the half circle be 1 unit. sin30 = c/1 c = ½ units. c = 0.5 units. cos30 = d/1 d = ½√(3) units. d = 0.86602540378 units. e = 1-0.86602540378  e = 0.13397459622 units. f² = (0.13397459622)²+(0.5)² f = 0.51763809021 units. Calculating r, radius of the small inscribed yellow circle. Considering similar triangle ratios. 0.51763809021 = (1-r) 0.5 = (0.5+r) Cross Multiply. 0.5-0.5r = 0.51763809021r+0.2588190451  0.5-0.2588190451 = 0.5r+0.51763809...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1966632

mathematics-question-and-solution_1689215824Ie0zKC.jpeg
a² = 5²+2² a = √(29) cm. b² = 3²+2² b = √(13) cm c = atan(2/5)° d = atan(1/3)° e = atan(2/3)° f = 90-c-d f = 90-atan(2/5)-atan(1/3) f = 49.76364169073° g = atan(3)° h = g-e h = atan(3)-atan(2/3) h = 37.8749836511° cos49.76364169073 = j1/√(29) j1= 3.47850542618 cm sin49.76364169073 = j2/√(29) j2 = 4.11096095822 cm. cos37.8749836511 = k1/√(13) k1 = 2.84604989415 cm. sin37.8749836511 = k²/√(13) k2 = 2.21359436212 cm. Therefore, Blue Area is; 0.5*j1*j2 + 0.5*k1*k2 0.5*3.47850542618*4...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1946655

mathematics-question-and-solution_1688618794RLXSpo.jpeg
Let the height and base of area triangle C be 2 units and 3 units respectively. Therefore; Area Triangle C is; ½*2*3 = 3 square units. tana = (2/3) a = atan(2/3)° b = 189-a b = 180-atan(2/3) b = 146.30993247402° c = ½(180-146.30993247402) c = 16.84503376299° Let the radius of the big circle be d. Calculating d. e = ½(146.30993247402) e = 73.15496623701° f = (3-d) units. tan73.15496623701 = d/(3-d) d = 9.9083269132-3.30277563773d 4.30277563773d = 9.9083269132 d = 9.9083269132/4.3027...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1945925

mathematics-question-and-solution_1688588660lYN2rA.jpeg
Let the side of the regular pentagon be 1 unit. Notice; The regular pentagon side is equal the regular heptagon side. a = ⅐(180*5) a = ⅐(900)°, the single interior angle of the regular heptagon. b = 2a b = ⅐(450)° tan(⅐(450)) = c/0.5 c = 1.03826069829 units. cos(⅐(450)) = 0.5/d d = 1.15238243548 units. Where d is the radius of the ascribed circle. e = 180-⅐(900) e = ⅐(360)° tan18 = 0.5/f f = 1.53884176859 units. g² = 1.15238243548²-0.5² g = 1.03826069828 units. h = f-g h = 0.5005810...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1923070

mathematics-question-and-solution_1687882482HyQRuO.jpeg
Let GD (inscribed square side) be a. Calculating a. 2(a/(tan60))+a = 12 a = 12/((2/√(3))+1) a = 5.56921938165 cm. b = ½(12-5.56921938165) b = 3.21539030918 cm. Where b is BD = CE. c = 3.21539030918+5.56921938165 c = 8.78460969083 cm. Where c is CD. d² = 3.21539030918²+12²-24*3.21539030918cos60 d = 10.75890566601 cm. Where d is AD. (10.75890566601/sin60) = (12/sine) e = 105° Where e is angle ADB. f = 105-90 f = 15° Where f is angle ADG. cos15 = 5.56921938165/g g = 5.7656801693 cm. Where...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1921900

mathematics-question-and-solution_1687852156LPTgq2.jpeg
Let the regular pentagon side length be 1 unit. Single interior angle of the regular pentagon is; ⅕(180*3) = 108° a = 108-90 a = 18° b = 180-18-108 b = 54° (1/sin54) = c/sin108) c = 1.17557050458 units. d = 108-36 d = 72° tan72 =e/0.5 e = 1.53884176859 units. f = 54-18 f = 36° g² = 1.53884176859²+1.17557050458²-2*1.17557050458*1.53884176859cos36 g = 0.9071653746 units. (0.9071653746/sin36) = (1.17557050458/sinh) h = 49.61382244038° j² = 1+1.53884176859²-2*1.53884176859cos54 j = 1.248...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/1900719

mathematics-question-and-solution_1687143492PsrJUu.jpeg
Let the square side be 3 cm. Therefore; Observing similar triangle ratios. 3 = 2 1 = a Cross Multiply. a = ⅔ units. b = √(3²+1²) b = √(10) cm. c = √(2²+(⅔)²) c = ⅓(2√(10)) cm. d = √(√(10)²+(⅓(2√(10)))²) d = ⅓√(130) cm. e =½(d) e = ⅙√(130) cm. tanf = (√(10)/(2√(10)/3)) f = 56.30993247402° g = 180-56.30993247402-atan(2/(2/3)) g = 52.1250163489° h = 90-52.1250163489 h = 37.8749836511°   j² = (⅙√(130))²+(⅓(2√(10)))²-2(⅙√(130))(½(2√(10)))cos56.30993247402 j = 1.90029237517 cm. (1.900292375...
WhatsApp Google Map
✕

Safety and Abuse Reporting

Thanks for being awesome!

We appreciate you contacting us. Our support will get back in touch with you soon!

Have a great day!

Are you sure you want to report abuse against this website?

Please note that your query will be processed only if we find it relevant. Rest all requests will be ignored. If you need help with the website, please login to your dashboard and connect to support

Cancel Confirm