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Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3468425

Calculating Area Red.a² = 6²+8²a = √(100)a = 10 cm.a is the side length of the square.6b+8b+10b = 8*624b = 48b = 2 cm.b is the radius of the inscribed circle.tanc = 6/8c = atan(3/4)°cosc = 2/dd = 2/cos(atan(3/4))d = 2.5 cm.e = 90-ce = atan(4/3)°tane = f/2.5(4/3) = f/2.5f = 2.5(4/3)f = ⅓(10) cm.f = 3.333 cm.g = (½(c)+90)°g = (0.5atan(3/4)+90)°h² = (8-2)²+2²h² = 40h = 2√(10) cm.j² = 10²+(2√(10))²-2*10*2√(10)cos(0.5atan(3/4)+90)j = 13.416407865 cm.(13.416407865/sin(0.5atan(3/4)+90)) = (2√(10)/sink...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3441948

Sir Mike Ambrose is the author of the question.Calculating Area Orange.yB = 6Area OABC = 161/5 square units.Let xB be a.Calculating g, gradient of length AB.(y2-y1)/(x2-x1) = gg = (6-4)/(a-0)g = 2/aTherefore, h, gradient at the perpendicular is;h = -1/gh = -1/(2/a)h = -a/2Let xC be b.It implies;(6-0)/(a-b) = hCalculating b.6/(a-b) = -a/212 = -a²+abb = (a²+12)/a units.Again, b is xC = OC.c = xC-xBc = ((a²+12)/a)-ac = 12/a units.Calculating a, observing trapezoid area formula and triangle area fo...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3361473

Calculating the required angle, let it be x. Let 1 unit be the side length of the both congruent inscribed equilateral triangles. a = ⅑*180(9-2) a = 140° a is the single interior angle of the regular nonagon. b = ½(a) b = 70° c = 180-2b c = 40° d² = 2-2cos40 d = 0.68404028665 units. d is the side length of the regular ascribed nonagon. e = 60+70 e = 130° f² = 1²+0.68404028665²-2*1*0.68404028665cos130° f = 1.53208888624 units. (1.53208888624/sin130) = (1/sing)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3255141

Calculating Angle x. Let 1 unit be the side length of the ascribed square. a = 90-70 a = 20° b = 90-20-45 b = 25° c = 90-25 c = 65° sin70 = 1/d d = 1.06417777248 units. tan20 = e/1 e = 0.36397023427 units. f = 1-e f = 0.63602976573 units. tan65 = 1/g g = 0.46630765815 units. h = 1-g h = 0.53369234185 units. j² = f²+h² j² = 0.63602976573²+0.53369234185² j = 0.83027789242 units. Therefore, Angle x is; (0.83027789242/sin45) = (1.06417777248/sinx)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3221344

Calculating x, the required angle. Let the side length of the regular pentagon be 1 unit. a = ⅕*180(5-2) a = 108° a is the single interior angle of the regular pentagon. b² = 1²+0.5²-2*1*0.5cos108 b = 1.24860602048 units. (1.24860602048/sin108) = (1/sinc) c = 49.6138224406° d = 180-108-c d = 72-49.6138224406 d = 22.3861775594° e = 180-c-d e = 180-49.6138224406-22.3861775594 e = 108° e = a. (0.5/sin108) = (f/sin49.6138224406) f = 0.40044657145 units. g = b-f g...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3133538

b = √(a) b = √(48) b = √(16*3) b = 4√(3) units. b is the radius of the ascribed quarter circle. c = ½(b) c = 2√(3) units. c is the radius of the inscribed half circle. tan30 = d/c ⅓√(3) = d/(2√(3)) d = 2 units. e = b-d e = (4√(3)-2) units. e = 4.92820323028 units. e is the side length of the inscribed regular triangle. f = ½(e) f = (2√(3)-1) units. tan60 = g/f g = √(3)(2√(3)-1) g = (6-√(3)) units. g = 4.26794919243 units. g shares the inscribed regular triangle to two equal right-angled t...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3126404

Let a be the radius of the circle. 2πa = 14π a = 7 cm. Calculating x. cos49 = b/7 b = 7cos49 b = 4.59241320293 cm. c = 2b c = 9.18482640587 cm. c is CD d = 180-49-37.5 d = 93.5° (9.18482640587/sin93.5) = (e/sin37.5) e = 5.60181656513 cm. Notice. e = AB. f = ½(AB) f = 2.80090828257 cm. Therefore, angle x is; cosx = 2.80090828257/7 x = acos(2.80090828257/7) x = 66.4137096823° Calculating AD. g = 49-37.5 g = 11.5° h = 180-2(11.5) h = 157°...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3121933

Let 1 unit be the side length of the regular hexagon. a = ⅙*180(6-2) a = 120° a is the single interior angle of the regular hexagon. cos75 = 0.5/b b = 1.93185165258 units. c² = 1²+0.5²-2*1*0.5cos120 c = 1.32287565553 units. d = 120-75 d = 45° (0.5/sine) = (1.32287565553/sin120) e = 19.1066053506° f = 120-e f = 100.893394649° g = 360-120-100.893394649-75 g = 64.106605351° h = 90-g h = 25.893394649° j² = 1.32287565553²+1.93185165258²-2*1.32287565553*1.9318516...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3121237

Let the radius of the circle be a. sinb = a/(a+a) b = 30° cos30 = c/2a c = √(3)a units. d = 2-c d = (2-√(3)a) units. sin30 = e/d e =½(2-√(3)a) units. cos30 = f/d ½√(3) = f/(2-√(3)a) f = ½(2√(3)-3a) units. g = a+a+a g = 3a units. h = f+g h = ½(2√(3)-3a)+3a h = ½(2√(3)+3a) units. h is the diameter of the half circle. j = ½h j = ¼(2√(3)+3a) units. j is the radius of the half circle. k = a+j k = a+¼(2√(3)+3a) k = ¼(2√(3)+7a) units. l = j-a l = ¼(2√(3)...

Mathematics Question and Solution

https://onlineedumath.com/update/mathematics-question-and-solution/3117610

Let the side length of the ascribed square be 1 unit. Therefore, the side length of the inscribed green regular triangle 1 unit. a = 90-60° a = 30° b² = 2-2cos30 b = 0.51763809021 units. c = ½(180-30) c = 75° d = c+60 d = 135° (1/sin135) = (0.51763809021/sine) e = 21.4707014327° f = 180-135-e f = 45-21.4707014327 f = 23.5292985673° (1/sin135) = (g/sin23.5292985673) g = 0.56457945531 units. h = 1-g h = 1-0.56457945531 h = 0.43542054469 units. j² = 0.4354...

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Please, highlight and open/browse the links below to view videos of our teaching and learning activities. Thank you. Video 1. Class with Adesuwa (year 5) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid02VGXZkxZYksDaBSZXhbkir8GKETEiU2fCQobAVZE4Yv84HRaQ3NL1XvAMTRTxsNs3l/?app=fbl Video 2. Class with Zino and Ruemu (year 4) 27/06/2023 https://www.facebook.com/100003984568865/posts/pfbid038EyeWYY8Du4XgbEb7mbz33DS7XAvYWjXTwrE6HRfC4qpFTqCX6YVFYmnCeDBfEWHl/?app=fbl Video 3. Class with A...

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Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

Mathematics Question and Solution

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