Mathematics Question and Solution
a² = 5²+2²
a = √(29) cm.
b² = 3²+2²
b = √(13) cm
c = atan(2/5)°
d = atan(1/3)°
e = atan(2/3)°
f = 90-c-d
f = 90-atan(2/5)-atan(1/3)
f = 49.76364169073°
g = atan(3)°
h = g-e
h = atan(3)-atan(2/3)
h = 37.8749836511°
cos49.76364169073 = j1/√(29)
j1= 3.47850542618 cm
sin49.76364169073 = j2/√(29)
j2 = 4.11096095822 cm.
cos37.8749836511 = k1/√(13)
k1 = 2.84604989415 cm.
sin37.8749836511 = k²/√(13)
k2 = 2.21359436212 cm.
Therefore, Blue Area is;
0.5*j1*j2 + 0.5*k1*k2
0.5*3.47850542618*4.11096095822+0.5*2.84604989415*2.21359436212
= 10.3 cm²
