Mathematics Question and Solution
r, radius of the inscribed circle is;
2(r/tan22.5) = 12√(2)
r = 6√(12)tan22.5
r = 3.51471862576 cm.
a = 12-3.51471862576
a = 8.48528137424 cm.
b = (8.48528137424-c) units.
c is the radius of the inscribed half circle.
c² = (8.48528137424-c)²+3.51471862576²)
c² = 72-16.97056274848c+c²+12.35324701826
16.97056274848c = 84.35324701826
c = 4.97056274848 cm.
d = 12-4.97056274848-3.51471862576
d= 3.51471862576 cm.
Therefore, AB is;
√(3.51471862576²+8.48528137424²)
AB = 9.18440237676 cm.
