By OnlineEdumath   |  24th March, 2025
Let the side of the regular pentagon be 1 unit. Notice; The regular pentagon side is equal the regular heptagon side. a = ⅐(180*5) a = ⅐(900)°, the single interior angle of the regular he...
By OnlineEdumath   |  23rd March, 2025
a = 360-140-80 a = 140° cos20 = 1/b b = 1.06417777248 units. (1.06417777248/sin30) = (c/sin70) c = 2 units. d² = 4+1.064177772482²-4*1.06417777248cos140 d = 2.89711998506 units. (2...
By OnlineEdumath   |  22nd March, 2025
Let the side of the regular pentagon be 1 unit. a = 360-2(108)-90 a = 54° tan72 = b/0.5 b = 1.53884176859 units. tan54 = 1.53884176859/c c = 1.11803398875 units. d = c-0.5 d = 0.618...
By OnlineEdumath   |  21st March, 2025
Notice; The diameter of the semicircle is 8 units. Therefore radius is 4 units. tan30 = a/2 a = ⅔(√(3)) units. b = 3a b = 2√(3) units. c² = 2²+(⅔(√(3)))² c = (4/√(3)) units. d...
By OnlineEdumath   |  20th March, 2025
Let the side of the regular hexagon which is equal the side of the square be 1 unit. a = ½(180-108) a = 36° tan36 = b/0.5 b = 0.363271264 unit. Area Blue is; 0.5*0.363271264*0.5 =...
By OnlineEdumath   |  19th March, 2025
Sir Mike Ambrose is the author of the question. Let the side of the inscribed square be 2 units. Therefore; Area S is; Area triangle with two side 1.03528 units and 0.53589838486 units, and angl...
By OnlineEdumath   |  18th March, 2025
Sir Mike Ambrose is the author of the question. P coordinate is; P(3, 9) Q coordinate is; Q(2, 5), Q(3, 5) It implies; Shaded area exactly in its square units simplest form is; (...
By OnlineEdumath   |  17th March, 2025
Sir Mike Ambrose is the author of the question. Calculating the circle's radius, r. 21r + 15r + 12√(2)r = 21*12√(2)sin45 (36+12√(2))r = 252 r = 252/(36+12√(2)) cm r = 3(3-√(2)) cm I...
By OnlineEdumath   |  16th March, 2025
Sir Mike Ambrose is the author of the question. Let the radius of the ascribed semicircle be 2 units. Therefore; Radius of the inscribed circle is 1 unit. It implies; Area R is; Are...
By OnlineEdumath   |  15th March, 2025
Let a be the side of the square. cos30 = b/8 b = 4√(3) cm. sin30 = c/8 c = 4 cm. a = b+12 a = (12+4√(3)) cm. Area Square is; a² = (12+4√(3))² = 358.27687752661 cm²  d² = 12²+4²...
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