By OnlineEdumath   |  17th September, 2025
Sir Mike Ambrose is the author of the question. Calculating Red Shaded Area ÷ Blue Shaded Area to 2 decimal places. Let the side of the regular pentagon be 1 unit. a = 360-2(108)-90 a = 54°...
By OnlineEdumath   |  17th September, 2025
Sir Mike Ambrose is the author of the question. Calculating Shaded Area ÷ Green Area to 2 decimal places. Let the side of the regular pentagon be 1 unit. a = 108-90 a = 18° b = 180-108-...
By OnlineEdumath   |  16th September, 2025
Calculating Blue Area. Area Blue (Star) is; Area circle of radius 20 cm - 5(area triangle with two length 14.5308505601 cm and angle 108°, the angle they form) - 5(Area sector of radius 20 cm...
By OnlineEdumath   |  16th September, 2025
Sir Mike Ambrose is the author of the question. Calculating Shaded Area ÷ Green Area to 2 decimal places. Let the single side length of the two congruent inscribed regular pentagon be 1 unit....
By OnlineEdumath   |  15th September, 2025
Calculating Area Triangle ABC. Let CM be x. Calculating x. x+1 ~ x+3     1 ~ 2  Cross multiply. 2x+2=x+3 x = 1 unit. Therefore, CM = 1 unit. Therefore angle C will be;...
By OnlineEdumath   |  15th September, 2025
Calculating Area Blue Inscribed Circle. a = (x+1) units. b = (4-x) units. It implies; (x+1)² = 1²+(4-x)² Where x is the radius of the inscribed blue circle. Calculating x. x²+2...
By OnlineEdumath   |  14th September, 2025
Sir Mike Ambrose is the author of the question. Calculating Area purple ÷ Area brown exactly. Area purple is; Area trapezium with two parallel side length (58/15) cm and (46/5) cm, and hei...
By OnlineEdumath   |  14th September, 2025
Calculating Angle x. Let the base of the ascribed quadrilateral be 1 unit. (1/sin78) = (a/sin(18+30)) a = 0.75974712295 units. (1/sin78) = (b/sin54) b = 0.82709091529 units. (0.827090...
By OnlineEdumath   |  14th September, 2025
Calculating Ascribed Square Area. Let the ascribed square side length be x. a² = 5 a = √(5) cm. a is the side length of the inscribed red square. b² = 20 b = √(20) b = 2√(5) units. b...
By OnlineEdumath   |  13th September, 2025
Calculating x, the base of the ascribed right-angled triangle. a² = 15²+x² a = √(15²+x²) units. a is the hypotenuse of the ascribed right-angled triangle. Therefore, x is; 3*15+3*x +3√(1...
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