Let r be the radius of the quarter circle.
Let x be the interior angle facing 1 cm.
a = (x+45)°
a is alternate to y, the angle formed by the meet point of r and 2 cm at the circumference of...
Let a be the radius of the inscribed half circle.
b²+8² = (2a)²
b = √(4a²-64) units.
It implies;
Calculating a.
2a ~ 8
a ~ √(4a²-64)
Cross Multiply.
8a = 2a√(4a²-64)
4 = √(4a²-...
Let a be the radius of the red inscribed circle.
b = (4-a) units.
tan30 = a/b
⅓√(3) = a/(4-a)
3a = 4√(3)-√(3)a
(3+√(3))a = 4√(3)
a = 4√(3)/(3+√(3))
a = ⅙(12√(3)-12)
a = (2√(3)-2) units....
Let a be the radius of the circle.
c = (a-1) units.
Calculating a.
7² = a²+(a-1)²-2a(a-1)cosb
49 = a²+a²-2a+1-(2a²-2a)cosb
48 = 2a²-2a-(2a²-2a)cosb
(2a²-2a)cosb = 2a²-2a-48 --- (1)....
Let a be the radius of the inscribed circle.
b² = 2(10)²
b = 10√(2) cm.
b is the diagonal of the square.
10²+a² = c²
c = √(100+a²) cm.
d = b-c
d = (10√(2)-√(100+a²)) cm.
Calculating a.
2a² = (1...
Let a be the radius of the circle.
b² = a²+√(5)²
b = √(a²+5) units.
It implies;
2a ~ √(a²+5)
8 ~ a
Cross Multiply.
2a² = 8√(a²+5)
a² = 4√(a²+5)
a⁴ = 16a²+80
a⁴-16a²-80 = 0
Le...
r will be;
½(½(AB))
= ¼(AB)
Therefore;
r = ¼(1)
r = ¼ units.
Let the ascribed semi circle radius be R.
Let the inscribed circle radius be r.
Notice;
R=2r
It implies;
R²=1²+r²
(2r)²=1+r²
4r²=1+r²
4r²-r²=1
3r²=1
Therefore;
r =...
a ~ 6
6 ~ 8
Cross Multiply.
8a = 6*6
2a = 9
a = ½(9) units.
b = a+8
b = ½(9)+8
b = ½(25) units.
b is the diameter of the ascribed half circle.
c = ½(b)
c = ¼(25) units.
c is the...
Calculating area of the red inscribed circle.
Let a be the radius of the blue ascribed circle.
πa² =144π
a² = 144
a = 12 cm.
b = 2a
b = 24 cm.
b is the diameter of the blue ascribed cir...
