Sir Mike Ambrose is the author of the question.At x = 0, y = 2.At y = 16, x = 1.Gradient of the curve at x = 1 or at the tangent is;dy/dx = 3In2*2^(3x+1)For x = 1dy/dx = 48In2Therefore coordinate Q i...
Calculating Area Pink.a*b = 4*(4+1)ab = 20a = 20/b units.c = a+bc = (20/b)+bc = (b²+20)/b units.c is the diameter of the ascribed pink circle.d = ½(c)d = (b²+20)/(2b) units.d is the radius of the pin...
Calculating Area Red.a = 1+(161/9)+(10/9)a= 1+(171/9)a = 1+19a = 20 units.a is the diameter of the ascribed circle.b = ½(a)b = 10 units.b is the radius of the ascribed circle.Let x be the radius of t...
Calculating Area of the yellow Hexagon.Let x be the side length of the hexagon.a²+3² = x²a = √(x²-9) cm.b² = 2x²-2x²cos120b = √(3x²)b = √(3)x cm.It implies;Calculating x.sinc = √(x²-9)/x --- (1).sinc...
Calculating Area Red.a² = 6²+8²a = √(100)a = 10 cm.a is the side length of the square.6b+8b+10b = 8*624b = 48b = 2 cm.b is the radius of the inscribed circle.tanc = 6/8c = atan(3/4)°cosc = 2/dd = 2/c...
Sir Mike Ambrose is the author of the question.Let the side length of the square be 1 unit.Therefore;Area square is;1² = 1 square units.It implies;Area R is;Area square - Area equilateral triangle wi...
Sir Mike Ambrose is the author of the question.Let the side length of the be 2 units.Therefore;BC = 2 units.It implies;Area orange is;½(1*2) = 1 square units.Area green is;½(1*2) + ½(2/√(5))(4/√(5))=...
Calculating Area Red.a = (2x+6) cm.a is the height of the ascribed right-angled triangle.b = (9x+6) cm.b is the base of the ascribed right-angled triangle.c = 13x cm.c is the hypotenuse of the ascrib...
Sir Mike Ambrose is the author of the question.Calculating Area of the Triangle.Let alpha be x.Therefore;(12/sin2x)=(8/sinx)And;Sin2x = 2sinxcosxTherefore;(12/2sinxcos)=(8/sinx)6 = 8cosxx = acos(6/8)...
Sir Mike Ambrose is the author of the question.Calculating Area Green.Area green exactly in cm² is;Area ABCD - Area trapezoid with parallel sides (9-2√(3)) cm and (24√(3)-39) cm, and height 6 cm.= (5...
