By OnlineEdumath   |  9th March, 2026
Red Area is;7(area square with side 1 unit) - Area triangle with base 1 unit and height 4 units - Area square with side 1 unit - Area triangle with height and base 1 unit respectively.= 7(1*1) - 0.5(...
By OnlineEdumath   |  8th March, 2026
Sir Mike Ambrose is the author of the question.8 = 4a = (8-a) Cross multiply.64-8a = 4a64 = 12aa = ⅓(16) cm.b = 8-ab = ⅓(8) cm.c = atan(⅔)°d = atan(3/2)°⅔ = 8/ee = 12 cm⅔ = f/8f = ⅓(16) cm.g = 8-fg =...
By OnlineEdumath   |  7th March, 2026
Sir Mike Ambrose is the author of the question.Calculating Area Shaded.y = 2^(x)P coordinate is;P(1, 2)dy/dx = 2^(x)In2For x = 1dy/dx = 2In2It implies;Q coordinate is;Q(0, (2-2In2))Therefore;Shaded a...
By OnlineEdumath   |  6th March, 2026
Sir Mike Ambrose is the author of the question.a² = 11*11+10*10-2*11*10cos50a = 8.92113926968 cm.(8.92113926968/sin50) = (10/sinb)b = 59.16920318624°c = 180-50-59.16920318624c = 70.83079681376° d = 0...
By OnlineEdumath   |  5th March, 2026
Area m : Area n is;(√(2)x)² : (½(3x))²= 2x² : ¼(9x²)= 4(2x²) : 4(¼(9x²))= 8x² : 9x²= 8 : 9
By OnlineEdumath   |  4th March, 2026
Sir Mike Ambrose is the author of the question.Calculating a.½((0, 6√(3)) (-3, 3√(3)) (a, (16a/3)) (0, 6√(3))) = ¼(9+20√(3))Therefore;a = x = ½√(3) unity = 16a/3 = (16/3)(√(3)/2)y = ⅓(8√(3)) unit.The...
By OnlineEdumath   |  3rd March, 2026
Sir Mike Ambrose is the author of the question.Area green is;½*3*6sin120= ½(9√(3)) cm²Radius, r of the circle is;r = √(63)/√(3)r = √(21) cmTherefore;Area circle is;π(√(21))²= 21π cm²It implies;Area g...
By OnlineEdumath   |  2nd March, 2026
Sir Mike Ambrose is the author of the question.Calculating Exactly, Golden Area ÷ Large Square Area.Let the side of the large square be 2 units.Therefore;Area large square is;2²= 4 square units.Area...
By OnlineEdumath   |  1st March, 2026
Calculating Area Green.Let theta be x.a = 90-39a = 51°x+x+27 = 512x = 51-272x = 24x = 12°b+x+39 = 180b = 180-39-xAnd x = 12°b = 180-39-12b = 129°Let c be the hypotenuse of the ascribed right-angled t...
By OnlineEdumath   |  1st March, 2026
Calculating The Red Inscribed Semi Circle Area.Let x be the area of the inscribed half circle.a² = 2x²a = √(2)x units.Calculating x.1² = x²+(√(2)x)²1 = x²+2x²1 = 3x²x = 1/√(3) units.Again, x is the r...
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