Calculating x, length OP.
a² = 2²+6²
a = √(40) units.
a is BC.
tanb = 6/2
b = atan(3)°
b is angle PBC.
cosc = (0.5√(40))/√(50)
c = acos(√(10)/√(50))
c is angle PBC.
d = b-c
d = atan(3)-acos(√(10)/√(50))
d = 8.13010235416°
d is angle PBO.
It implies, length x is;
x² = 2²+√(50)²-2*2√(50)cos8.13010235416
x² = 54-4√(50)cos8.13010235416
x = √(26) units.
x = 5.09901951359 units.
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