By OnlineEdumath   |  3rd July, 2025
Calculating x, the side length of the ascribed square. a²+x² = 8² a = √(64-x²) units. b²+x² = 10² b = √(100-x²) units. It implies;. c = (x-√(64-x²)) units. d = (x-√(100-x²)) units. Therefore;...
By OnlineEdumath   |  2nd July, 2025
Let the radius of the quarter circle be 1 unit. b = (a+1) units. a is AD = DE. a² = 2-2cosx 2cosx = 2-a² cosx = ½(2-a²) --- (1). cosx = 1/(1+a) --- (2). Calculating a. Equating (1...
By OnlineEdumath   |  2nd July, 2025
Calculating Area Inscribed Red Circle. a = ½(8) a = 4 units. a is the radius of the two congruent half circles. b = (4+x) units. x is the radius of the red inscribed circle. c = (4-x) units. The...
By OnlineEdumath   |  1st July, 2025
Calculating r, radius of the circle. Notice that the plane shape is not drawn to scale. r² = (7+a)²+(0.5*10)² r² = 49+14a+a²+25 r² = 74+14a+a² --- (1). Again. r² = a²+(7+5)² r² = a²+...
By OnlineEdumath   |  1st July, 2025
Calculating r, radius of the half circle. Let the two equal lengths be a each. Therefore; r = 2a units. Calculating a. (2a)² = a²+9²-2a*9cosb 3a² = 81+18acosb cosb = (3a²-81)/(18a) cosb = (a...
By OnlineEdumath   |  30th June, 2025
Calculating shaded area. tana = 5/10 a = atan(½)° Therefore; b = atan(2)° c = 90-2a c = 90-2atan(½) c = 36.8698976458° d = 180-2b d = 180-2atan(2) d = 53.1301023542° Shaded A...
By OnlineEdumath   |  30th June, 2025
Calculating x. a = 2*120 a = 240° b = 360-a b = 120° c = ½(180-120) c = 30° d = 2*140 d = 280° e = 360-d e = 80° f = ½(180-80) f = 50° It implies; x = c+f x = 30+50 x = 80°
By OnlineEdumath   |  30th June, 2025
Notice. r is the radius of the inscribed yellow half circle. r = ½(10) r = 5 units. Calculating R, radius of the ascribed circle. Calculating R. a = x+10+5 a = (x+15) units. b = ½(a) b = ½(x+1...
By OnlineEdumath   |  30th June, 2025
Kindly move the question right or left one time to review the solution and answer. Solution and answer by Mehmet Kara. Thank you nicely.
By OnlineEdumath   |  29th June, 2025
Let AC = BD = DE = a. Calculating a. 14² = a²+(10+a)²-2a(10+a)cosb 96 = 2a²+20a-(20a+2a²)cosb --- (1). 14² = a²+10²+2a*10cosb 96 = a²+20acosb cosb = (96-a²)/(20a) --- (2). Substituting (2) in (1...
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