Sir Mike Ambrose is the author of the question.
Let the single side length of the square be 2 units.
Therefore;
Area Square is;
2²
= 4 square units.
Area Green is;
Area triangl...
Let the side length of the regular heptagon be 1 unit.
a = ⅐(180*5)
a = ⅐(900)°
b = 0.5(360-2(900/7))
b = ⅐(360)°
c = 2cos(360/7)+1
c = 2.24697960372 units.
d² = 2-2cos(90/7)
d = 1....
Sir Mike Ambrose is the author of the question.
Area S, exactly in square units is;
Area triangle with height 2 units and base (2sin120) units + Area triangle with height 2 units and base 2√(2)...
a² = 11*11+10*10-2*11*10cos50
a = 8.92113926968 cm.
(8.92113926968/sin50) = (10/sinb)
b = 59.16920318624°
c = 180-50-59.16920318624
c = 70.83079681376°
d = 0.5a
d = 4.46056963484 cm....
sin30 = (4√(3))/a
a = 8√(3) units.
a is AC.
AB = ⅓(a)
AB = ⅓(8√(3)) units.
cos30 = b/⅓(8√(3))
b = ⅓(8√(3))*½√(3)
b = 4 units.
sin30 = c/⅓(8√(3))
c = ⅓(4√(3)) units.
d = 4+b
d = 8...
Sir Mike Ambrose is the author of the question.
Please, move the above question left/right one time to review the question.
Thank you kindly.
Area Orange is;
87/10 square unit.
Calculating x, side length of the inscribed regular hexagon.
a = 2x units.
a is twice the side length of the inscribed regular hexagon.
b = ⅙*180(6-2)
b = 120°
b is the single interior ang...
Sir Mike Ambrose is the author of the question.
Area blue exactly is square units decimal form is;
½(Area triangle with height (2√(2)+2√(2+√(3))) units and base 12.9282032303sin75 units - Area...
Radius, r of one of the five congruent, inscribed circles is;
8r²+√(3)r-1=0
r = (√(35)-√(3))/16 m.
Therefore;
Total area of the five congruent, inscribed yellow circles is;
5πr²
=...
a² = 4²+3²
a = √(25)
a = 5 units.
a is MN, the side length of the inscribed square.
b² = 2(5²)
b = 5√(2) units.
b is MK, the diagonal of the inscribed square.
tanc = 4/3
c = atan(4/3)°...
