By OnlineEdumath   |  29th June, 2025
Calculating Purple Area. tanb = 2/1 b = atan(2)° tanc = ½ c = atan(½)° d = 180-b d = (180-atan(2))° e = 180-d-c e = 180-(180-atan(2))-atan(½) e = (atan(2)-atan(½))° It implies; (1/sin(atan(2)-...
By OnlineEdumath   |  29th June, 2025
Let 1 unit be the side length of the green square. Therefore; EN = ½ units. a = (1+2x) units. a is the diameter of the bigger circle. b = ½(a) b = ½(1+2x) units. b is the radius of the...
By OnlineEdumath   |  28th June, 2025
R ~ (a+b) r ~ a Cross Multiply. aR = r(a+b) R/r = (a+b)/a R/r = 1+(b/a) And R/r = phi (golden ratio) Let phi be x. x-1 = b/a a/b = 1/(x-1) Where x (phi) is; x = ½(1+√(5))...
By OnlineEdumath   |  28th June, 2025
Calculating Area A Divided By Area B (A/B). Let a be the two equal lengths. b = (3-a) units. c² = 4²+3² c = 5 units. Therefore; Calculating a. 5 ~ (3-a) 4 ~ a Cross Multiply. 5x = 12-4a 9a = 1...
By OnlineEdumath   |  28th June, 2025
Let DC = 1 unit. a = 180-36+30 a = 114° a is angle BDC. (1/sin36) = (b/sin114) b = 1.55421636402 units. b is BC. c = 180-60-54 c = 180-114 c = 66° c is angle BAC. Therefore; (1.55421636402/sin6...
By OnlineEdumath   |  28th June, 2025
Calculating R. 3R+4R+5R = 3*4 12R = 12 R = 1 units. Calculating r. tana = 3/4 a = atan(3/4)° b = ½(a) b = ½(atan(3/4))° tan(½(atan(3/4))) = r/c c = 3r units.    d = 4-1-3r d = (3-3r) units. e...
By OnlineEdumath   |  27th June, 2025
Let the height and base of the brown area be x and y respectively. Therefore; ½(3+x)(4+y)-42 = ½(xy) 12+3y+4x+xy-84 = xy 3y+4x = 72 --- (1). 3 ~ (3+x) 4 ~ (y+4) Cross Multiply. 4(...
By OnlineEdumath   |  27th June, 2025
a² = 2(1)² a = √(2) units. a is the diagonal of the inscribed square and also the side length of the two congruent inside bigger regular triangle. b = ½(a)  b = ½√(2) units. c²+b² = a² c² = √(2)²-...
By OnlineEdumath   |  27th June, 2025
a = 2(20) a = 40 units. b = 60+20 b = 80 units. c = 2(20) c = 40 units. d = atan(80/40)+atan(20/40) d = 90° d is angle ACB Area Triangle ABC is; ½*√(80²+40²)*√(40²+20²) = ½*√(6400+1600)*√(1600...
By OnlineEdumath   |  27th June, 2025
Let the inscribed green square side length be a. 2b² = a² b = ½√(2)a units. c² = 2(4)² c = 4√(2) units. c is the diagonal of the ascribed bigger square. It implies; 4+a+½(a) = c...
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