By OnlineEdumath   |  21st May, 2025
Sir Mike Ambrose is the author of the question. Let a be the equal lengths inscribing triangle ABC. Calculating a. ½(a)² = 15 a = √(30) units. b = 180-60-45 b = 75° b is angle BAC....
By OnlineEdumath   |  21st May, 2025
Let R=the bigger inscribed circle radius. Let r=the smaller inscribed circle radius. It implies; R+r=6√(3)-6=4.4  R+r=4.4 -------(1). And the radius of the ascribed semi circle is 6...
By OnlineEdumath   |  21st May, 2025
Notice. Radius rod the half circle is 5 units. a = (5-x) units. Calculating x. 5² = 3²+(5-x)² 16 = 25-10x+x² x²-10x+9 = 0 x = 1 unit. It implies; a = 5-x And x = 1 unit. a = 4...
By OnlineEdumath   |  20th May, 2025
a = (2r-14) units. b = ½(a) b = (r-7) units. Calculating r, radius of the half circle. Therefore; 2r ~ 6 6 ~ (r-7) Cross Multiply. 2r(r-7) = 36 r²-7r-18 = 0 Resolving the qu...
By OnlineEdumath   |  20th May, 2025
Length x is; 15² = 9*x x = ⅑(15*15) x = 25 units.
By OnlineEdumath   |  20th May, 2025
Sir Mike Ambrose is the author of the question. Equation of the curve is; y = ⅔(8x-x²) Calculating Area E. (Area under the curve at x = (3/2) and x = 4) - Area trapezium with parallel sid...
By OnlineEdumath   |  20th May, 2025
Notice; Blue area = yellow area. Let the single side length of blue area be 2 units. Let the single side length of red area be y. Therefore; Tanx=y/(4+y) ------ (1) Tanx=2/(2+y) -...
By OnlineEdumath   |  20th May, 2025
a = ½(6) a = 3 units. a is the radius of the circle. b = (5-c) units. 6² = d²+(5-c)² d² = 36-(25-10c+c²) d = √(11+10c-c²) units. e = ½(d) e = ½√(11+10c-c²) units. f = (3-c) units....
By OnlineEdumath   |  19th May, 2025
Sir Mike Ambrose is the author of the question. Let the side length of the square be 1 unit. Area square is; 1² = 1 square unit. Calculating Area Orange. a = 45+60 a = 105° b = ½(...
By OnlineEdumath   |  19th May, 2025
Calculating angle x. Let the base of the ascribed quadrilateral be 1 unit. a = 180-20-60-50 a = 50° (1/sin50) = (b/sin80) b = 1.28557521937 units. (1/sin40) = (c/sin60) c = 1.347296355...
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