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Area of coloured region is;
Area triangle with height 53.3479501083 m and base 60sin(102.042575143) m + Area triangle with height 100.027406452 m and base √(5924)sin(12.5245961777) m
= (½*53.34795...
Observing Pythagoras Rule.
(n³)² = (n²)²+n²
n⁶ = n⁴+n²
n⁶-n⁴-n² = 0
n²(n⁴-n²-1) = 0
Let n² = p.
It implies;
p(p²-p-1) = 0
p²-p-1 = 0
Resolving the above quadratic equation, applying c...
Sir Mike Ambrose is the author of the question.
Let beta be x.
x = (½*atan(5/4))
Let alpha be y.
y = (½*atan(4/5))°
Therefore;
Area blue exactly in cm² decimal is;
Area triangle with hei...
Let the two equal red lengths of the triangle, ABC be 1 unit.
Therefore;
AB = CE = 1 unit.
a = 180-100-20
a = 60°
(b/sin100) = (1/sin20)
b = 2.8793852416 units.
b is BC.
c = 2.8793852416-1
c = 1...
Sir Mike Ambrose is the author of the question.
Calculating a.
½((0, 6√(3)) (-3, 3√(3)) (a, (16a/3)) (0, 6√(3))) = ¼(9+20√(3))
Therefore;
a = x = ½√(3) unit
y = 16a/3 = (16/3)(√(3)/2)
y = ⅓(8√(3))...
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a² = (2+1)²+2²
a² = 9+4
a = √(13) units.
Where a is blue length + red length.
b² = 1+2²
b = √(5) units.
tanc = 2/3
c = atan(2/3)°
tand = 2/1
d = atan(2)°
e = 90-d
e = 90-atan(2)
e = atan(½)°
f...
Notice.
Radius of the semi circle is 5 cm.
Let the width of the blue rectangle be a.
Therefore;
Blue rectangle length is 2a.
b² = a²+a²
b = √(2a²)
b = √(2)a
c = ½(b)
c = ½(√(2)a)...
Calculating the length and width of the rectangle.
Let the length be a.
Let the width be b.
Notice;
½(a) = b
Or
2b = a
It implies;
b²+b² = 4²
2b² = 16
b² = 8
b = 2√(2) cm.
The...
