By OnlineEdumath   |  21st July, 2023
Let the equal lengths be 1 unit. (1/sin54) = (a/sin84) a = 1.22929666779 units. b² = 1.22929666779+1-2*1.22929666779cos126 b = 1.98904379074 units. Calculating the required angle x. (1.989043790...
By OnlineEdumath   |  21st July, 2023
Let the biggest regular pentagon side length be 2 units. sin72 = a/2 a = 1.90211303259 units. tan72 = (1.90211303259/b) b = 0.61803398875 unit. c = 2b c = 1.2360679775 units. Where c is the side...
By OnlineEdumath   |  21st July, 2023
Angle ABC is; atan(3/4)° Therefore; sin(atan(3/4)) = 3/(BC) BC = 5 units. Angle ACB is; atan(4/3)° Angle EAC is; (180-2atan(4/3))° Calculating CE. (3/sin(atan(4/3))) = (CE/sin(180-2atan(4/3))...
By OnlineEdumath   |  20th July, 2023
Let the radius of the 3 congruent circles be r. Therefore, the general formula for the area of green section is; ½(πr²)-3(60πr²)/360+2(½*r²*sin60) = ½(πr²)-½(πr²)+r²sin60 = r²sin60 = ½(√(3)r²) squ...
By OnlineEdumath   |  20th July, 2023
Let BD be 1 unit. Therefore; (1/sin100) = (d/sin70) d = 0.95418889414 units. (1/sin80) = (AB/sin70) AB = 0.95418889414 units. AB is c. It implies; d = c. Calculating a. (a/sin20) = (0.9541888...
By OnlineEdumath   |  20th July, 2023
Let r be 1 unit. Calculating R. (R+1)² = x²+(R-1)² Calculating x. x² = R²+2R+1-R²+2R-1 x = √(4R)  x = 2√(R) units. It implies; (2R)² = (2√(R))²+2² 4R² = 4R+4 R²-R-1= 0 Solving the quadratic equ...
By OnlineEdumath   |  20th July, 2023
Let the two congruent lengths be 1 unit. (1/sin50) = (a/sin80) a = 1.28557521937 units. (1.28557521937/sin110) = (b/sin60)  b = 0.46791111376 units. (1/sin70) = (c/sin80) c = 1.04801052092 units....
By OnlineEdumath   |  20th July, 2023
Thank you for your feedback/testimonial, Sir Amadin. We, the Management and Educators of Online Edumath are humble and grateful. We will continue working hard to improve our standard because succe...
By OnlineEdumath   |  20th July, 2023
The side length of the congruent Hexagons is 2 unit. Area hexagon is; (6*2²)/(4tan30) = 6√(3)) square units. a² = 8-8cos30 a = √(8-4√(3)) unit. Area ABC is; ½(√(8-4√(3)))²sin60 = (2√(3)-3) squa...
By OnlineEdumath   |  20th July, 2023
25 = 49+64-14*8cosa 112cosa = 113-25 a = acos(88/112) a = 38.21321070174° a = Angle ACB. 5b+7b+8b = 56sin38.21321070174  b = (56sin38.21321070174)/20 b = √(3) cm b = 1.73205080757 cm. b = radius o...
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