The side length of the congruent Hexagons is 2 unit.
Area hexagon is;
(6*2²)/(4tan30)
= 6√(3)) square units.
a² = 8-8cos30
a = √(8-4√(3)) unit.
Area ABC is;
½(√(8-4√(3)))²sin60
= (2√(3)-3) square un...
Once upon a time, there was a 7 year old boy named Mike. One day, as Mike was walking through the playground at school, he found something half buried in the dirt. He took a good look at it but w...
Let the biggest regular pentagon side length be 2 units.
sin72 = a/2
a = 1.90211303259 units.
tan72 = (1.90211303259/b)
b = 0.61803398875 unit.
c = 2b
c = 1.2360679775 units.
Where c is the side len...
a = atan(⅓)°
⅓ = b/3
b = 1 unit.
It implies;
Area Red is;
Area triangle with height 1 unit and base 3 units + ½(2(area quarter circle with radius 3 units - area triangle with height and base 3 u...
Lucas was a bright child who needed to know every single thing that was happening around him.
The teachers were always scolding him in class because he always spoke, distracting the other kids.
O...
Let DE be 1 unit.
AC = 4 units.
Area ABC is;
8sin60
= 4√(3) square units.
a² = 1+2²-4cos45
a = 1.47362575821 units.
(1.47362575821/sin45) = (1/sinb)
b = 28.6750500631°
c = 60-b
c = 31.32494993...
Let the side of the regular octagon be a.
Calculating a.
a² = 8
a = √(8)
a = 2√(2) units.
2b² = (2√(2))²
b = 2 units.
c = 2√(2)+2+2
c = (2√(2)+4) units.
Where c is the length of the inscribed r...
Let the square side be 2 units.
tan30 = a/2
a = ⅓(2√(3)) unit.
sin60 = 2/b
b = ⅓(4√(3)) units.
c = 2-a
c = ⅓(6-2√(3)) units.
It implies;
Area Shaded is;
2(½*(⅓(6-2√(3)))²sin60) + 2*⅓(6-2√(3))...
The Management and Educators of Online Edumath gladly wish you, Ogheneruona a happy belated birthday.
Thank you for allowing us to celebrate with you.
Ogheneruona is a year 10 student, a Mathematici...
The Management and Educators of Online Edumath are happy to welcome our online learners;
Sharon, Ogheneruona, Ogheneruno, Oghenemano, Oghenevwarhe, Manasseh, Oghosa, Efemena, Adesuwa, The Prince,...
