By OnlineEdumath   |  15th June, 2024
Calculating Area Red. It is; Area sector with radius 5 m and angle 60° - Area triangle with height 5 units and base 5sin60 m + 2(area triangle with height 2.5 m and base 2.5 m) = (60π*5*5/...
By OnlineEdumath   |  15th June, 2024
Calculating the total shaded area with respect to d. a = (180(12-2))/12 a = 150° a is the single interior angle of the regular dodecagon. b = 105-75 b = 30° sin30 = c/d c = ½(d) units....
By OnlineEdumath   |  15th June, 2024
Let the two equal lengths be 1 unit each. a = 180-45 a = 135° b = 180-135-15 b = 30° (1/sin15) = (c/sin30) c = 1.9318516526 units. d² = 1.9318516526²+1²-2*1.9318516526cos45 d = 1.41...
By OnlineEdumath   |  14th June, 2024
Calculating Area Triangle ABC. a = 7-5 a = 2 units. b = 180-60-45 b = 75° sin75 = 7/c c = 7.2469332629 units. c is the side length of the triangle ABC, equilateral triangle. Area tr...
By OnlineEdumath   |  14th June, 2024
Let the radius of the ascribed semi circle be a. b = ½(a) units. c = b+a c = ½(3a) units. It implies; (½(3a))² = (½a)²+6² ¼(9a²) = ¼(a²)+36 ¼(8a²) = 36 8a² = 36*4 a² = 18 a = 3√(2...
By OnlineEdumath   |  14th June, 2024
a = 40+10 a = 50° a is angle ACB. b = 180-10-50 b = 120° b is angle ADC. (6/sin120) = (c/sin10) c = 1.2030698654 units. c is CD. (6/sin120) = (d/sin50) d = 5.3073115854 units. d is...
By OnlineEdumath   |  13th June, 2024
Let the side length of the inscribed two blue squares be 1 unit. a² = 2(1)² a = √(2) units. a is the radius of the green half circle. b = a-1 b = (√(2)-1) units. tanc = 1/(√(2)-1) c =...
By OnlineEdumath   |  13th June, 2024
Let the ascribed square side be be 4 units. Area ascribed square is; 4² = 16 square units. Calculating the inscribed red rectangle. It implies; a² = 2²+1² a = √(5) units. b² = 1²+0.5² b = √(5/4...
By OnlineEdumath   |  13th June, 2024
Let 1 be R. Calculating r. a = (1-r) units. tanb = 1/2 b = atan(½) c = 180-2b c = (180-2atan(½))° d = 180-c d = 2atan(½)° It implies, calculate r. sin(2atan(½)) = r/(1-r) ⅘ = r/(1-r) 5r = 4-4...
By OnlineEdumath   |  13th June, 2024
2a² = √(2)² 2a² = 2 a = 1 unit. a is the radius of the half circle. It implies; x = a+a x = 2a x = 2*1 x = 2 units. x is the diameter of the half circle.
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