a = 4+4
a = 8 units.
a is the radius of the quarter circle.
cosb = ⅛(0.5*4)
b = acos(¼)°
cosb = c/8
c = 8cos(acos(¼))
c = ¼(8)
c = 2 units.
c is the width of the inscribed rectangle.
sinb = d/8...
Let AD = BC = 1 unit.
a = 180-100-30
a = 50°
a is angle BAC.
(1/sin50) = (b/sin30)
b = 0.65270364467 units.
b is AC.
Therefore, the required angle theta is, let it be c.
(0.65270364...
Let BD = CD = 1 unit.
a = 180-45-30
a = 105°
a is angle CAD.
(1/sin105) = (b/sin45)
b = 0.73205080757 units.
b is AC.
c² = 0.73205080757²+2²-2*2*0.73205080757cos30
c = 1.41421356237 units.
c is A...
a = 180-60
a = 120°
b = 180-120-45
b = 15°
(1/sin15) = (c/sin45)
c = 2.73205080757 units.
sin60 = d/c
d = 2.73205080757sin60
d = 2.36602540378 units.
cos60 = e/c
e = 2.73205080757...
Area blue is;
2(area quarter circle with radius 8 cm - area isosceles right-angled triangle with equal lengths 8 cm) + 2(area quarter circle with radius 4 cm - area isosceles right-angled triang...
Notice.
10 m is the radius of the circle.
a = 10-3
a = 7 m.
sinb = (7/10)
b = asin(7/10)°
Calculating length AB.
tanb = 10/(AB)
AB = 10/(tanb)
AB = 10/tan(asin(7/10))
AB = 10.2020406122 m.
Or...
Calculating angle x.
Let the longest ascribed quadrilateral side length be 1 unit.
a = = 180-25-2(35)
a = 180-95
a= 85°
(1/sin85) = (b/sin25)
b = 0.42423259484 units.
c = 180-35-2(25)
c = 180-8...
Calculating Area Triangle A.
Let the two equal inscribed angles be a each.
(0.5*14*12sina)÷(0.5*12*35sina)
= 14/35
= 2/5
= 2:5
Where 2:5 is the ratio of the bases of the both triangles wi...
b = √(a)
b = √(48)
b = √(16*3)
b = 4√(3) units.
b is the radius of the ascribed quarter circle.
c = ½(b)
c = 2√(3) units.
c is the radius of the inscribed half circle.
tan30 = d/c
⅓√(3) = d/(2√(3)...
Calculating angle x.
a = 3-1
a = 2 units.
a is CD.
tanb = 3/1
b = atan(3)°
b is angle BCF equal angle ACD.
It implies;
((⅕(3√(10)))/sin(atan(3))) = (2/sinc)
c = asin(1)
c = 90°
c...
