By OnlineEdumath   |  13th March, 2026
Area green is;½*6*8= 24 square units.
By OnlineEdumath   |  12th March, 2026
Calculating Angle x.a+30+20+20 = 180a = 180-70a = 110°Let 1 unit be the radius of the circle.cos20 = b/1b = cos20b = 0.93969262079 units.c = 2bc = 1.87938524157 units.1.87938524157/sin110 = d/sin40d...
By OnlineEdumath   |  12th March, 2026
Sir Mike Ambrose is the author of the question.Area blue exactly in cm² is;Area triangle with height (2√(13)-2) cm and base (4sin120) cm.= ½*(2√(13)-2)*(4sin120)= √(3)(2√(13)-2)= 2(√(39)-√(3)) cm²
By OnlineEdumath   |  11th March, 2026
Calculating Area Yellow Inscribed Trapezoid.(2√(2)/sin135) = (√(2)/sina)a = 20.70481105464°b = 180-20.70481105464-135b = 24.29518894536°(c/sin24.29518894536) = (2√(2)/sin135)c = 1.64575131106 units.W...
By OnlineEdumath   |  10th March, 2026
Calculating Area Yellow.Notice.The ascribed quadrilateral is a square with side 6 units.a² = x²+3²a = √(x²+9) units.b = 2ab = 2√(x²+9) units.c = (6+x) units.Notice.b = cTherefore, calculating x.2√(x²...
By OnlineEdumath   |  10th March, 2026
Calculating Area Purple.a = 0.5(90-60)a = 15°cos15 =4/bb = 4.14110472164 cm.Where b is the side length of the inscribed regular triangle purple area.Purple area is;Area triangle with height 4.1411047...
By OnlineEdumath   |  9th March, 2026
Red Area is;7(area square with side 1 unit) - Area triangle with base 1 unit and height 4 units - Area square with side 1 unit - Area triangle with height and base 1 unit respectively.= 7(1*1) - 0.5(...
By OnlineEdumath   |  8th March, 2026
Sir Mike Ambrose is the author of the question.8 = 4a = (8-a) Cross multiply.64-8a = 4a64 = 12aa = ⅓(16) cm.b = 8-ab = ⅓(8) cm.c = atan(⅔)°d = atan(3/2)°⅔ = 8/ee = 12 cm⅔ = f/8f = ⅓(16) cm.g = 8-fg =...
By OnlineEdumath   |  7th March, 2026
Sir Mike Ambrose is the author of the question.Calculating Area Shaded.y = 2^(x)P coordinate is;P(1, 2)dy/dx = 2^(x)In2For x = 1dy/dx = 2In2It implies;Q coordinate is;Q(0, (2-2In2))Therefore;Shaded a...
By OnlineEdumath   |  6th March, 2026
Sir Mike Ambrose is the author of the question.a² = 11*11+10*10-2*11*10cos50a = 8.92113926968 cm.(8.92113926968/sin50) = (10/sinb)b = 59.16920318624°c = 180-50-59.16920318624c = 70.83079681376° d = 0...
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