Let AD = BC = 1 unit.
a = 180-100-30
a = 50°
a is angle BAC.
(1/sin50) = (b/sin30)
b = 0.65270364467 units.
b is AC.
Therefore, the required angle theta is, let it be c.
(0.65270364467/sinc) = (1/sin100)
sinc = 0.65270364467sin100
sinc = 0.64278760969
c = asin(0.64278760969)
c = 40°
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