sin36 = c/b
c = bsin36 units.
c = 0.5877852523b units.
Calculating b.
b² = (0.5877852523b)²+(0.5(b+1))²
0.6545084972b² = ¼(b²+2b+1)
1.6180339888b²-2b-1 = 0
It implies;
b = 1.61803 unit...
Let the side length of the regular hexagon be 1 unit.
a² = 2-2cos120
a = √(3) units.
Area regular hexagon is;
2(½*sin120)+(1*√(3))
= ½√(3)+√(3)
= ½(3√(3)) square units.
= 2.5980762114...
Let the inscribed semi circle's radius be a.
b = 2+1
b = 3 units.
b is the diameter of the ascribed semi circle.
c = ½(b)
c = ½(3)
c = (3/2) units.
c = 1.5 units.
c is the radius of the...
a²sin60 = 8
√(3)a² = 16
a = 4/(√√(3)) units.
a = 3.0393427426 units.
a is the side length of the big regular triangle.
b²sin60 = 18
√(3)b² = 36
b = 6/(√√(3)) units.
b = 4.5590141139 units...
Let the square side length be 1 unit.
Therefore, the regular hexagon side length a, is;
a = 5*1
a = 5 units.
b² = 2(5)²-2(5)²cos120
b = 5√(3) units.
Area regular hexagon is;
2(½*5*5s...
2² = a²+(3a)²-2*a*3acos60
4 = 10a²-3a²
4 = 7a²
a² = 4/7
a = ⅐(2√(7)) units.
a is the side length of the big equilateral triangle.
b = 3a
b = 3*⅐(2√(7))
b = ⅐(6√(7)) units.
b is the side...
Let the side length of the regular pentagon be 1 unit.
a² = 2-2cos108
a = 1.6180339887 units.
cos18 = b/1
b = 0.9510565163 units.
Area ascribed regular pentagon is;
½*sin108+½(1+1.618...
Calculating angle x.
a = ⅕*180(5-2)
a = 108°
a is the single interior angle of the regular pentagon.
b = 108-½(180-108)
b = 108-36
b = 72°
c = 90-72
c = 18°
d = 60+108
d = 168°...
x² = 8²+8²-2*8*8cos60
x² = 128-64
x² = 64
x = √(64)
x = 8 units.
Notice!
(4+2√(3)) units = 7.4641016151 units is the side length of the regular hexagon.
a = ⅙*180(6-2)
a = ⅙(180*4)
a = 120°
a is the single interior angle of the regular hexagon.
b = ½...
