Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
14th April, 2024

Let the square side length be 1 unit.


Therefore, the regular hexagon side length a, is;

a = 5*1

a = 5 units.


b² = 2(5)²-2(5)²cos120

b = 5√(3) units.


Area regular hexagon is;


2(½*5*5sin120)+(5√(3)*5)

= ½(25√(3))+25√(3)

= ½(75√(3)) square units.


Calculating the inscribed blue area.


tan30 = c/1

c = ⅓√(3) units.


Blue Area is;


6(area rectangle with length 1 unit and width ⅓√(3) units).

= 6(1*⅓√(3))

= 2√(3) square units.


Therefore, shaded fraction is;


(2√(3)) ÷ (½(75√(3)))

= 4/75

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