Mathematics Question and Solution
Let the length and width of the rectangle be y and z respectively.
Therefore;
7+7+x+y+z+7+7+x+y+z=66
Where 7 is the single side length of the square.
It implies;
14+14+2x+2y+2z=66
Therefore;
2(x+y+z)=38
x+y+z=19 ------ (1)
And;
x+z=7
Therefore;
x = 7-z ------- (2)
z+z+2y=30
2z+2y=30
z+y = 15
y = 15 - z ------- (3)
Substituting (2) and (3) in (1)
(7-z)+(15-z)+z= 19
22-2z+z=19
z = 22-19
z = 3
Notice;
At (3).
y = 15 -z, and z = 3
Therefore;
y = 15 - 3
y = 12
Recall please;
Let the length and width of the rectangle be y and z respectively.
Therefore the area of each rectangle is;
y * z
= 12 * 3
= 36 square units.
