Mathematics Question and Solution
Let the inscribed semi circle's radius be a.
b = 2+1
b = 3 units.
b is the diameter of the ascribed semi circle.
c = ½(b)
c = ½(3)
c = (3/2) units.
c = 1.5 units.
c is the radius of the ascribed semi circle.
Therefore;
d² = a²+(1.5-1)²
d² = a²+(½)²
d = √(a²+¼) units.
It implies;
(3/2)² = d²+a²
(9/4) = √(a²+¼)²+a²
(9/4) = a²+¼+a²
2 = 2a²
a² = 1
a = 1 unit.
Again, a is the radius of the inscribed semi circle.
Diameter CD of the inscribed semi circle, let it be e, is;
e = 2a
e = 2*1
e = 2 units.
