Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
14th April, 2024

Let the side length of the regular hexagon be 1 unit.


a² = 2-2cos120

a = √(3) units.


Area regular hexagon is;


2(½*sin120)+(1*√(3))

= ½√(3)+√(3)

= ½(3√(3)) square units.

= 2.5980762114 square units.


Calculating yellow area.


b² = 2(0.5)²-2(0.5)²cos120

b = ½√(3) units.


c = ½(a-b)

c = ½(√(3)-½√(3))

c = ¼√(3) units.


cos60 = d/0.5

d = ¼ units.


e = c-d

e = ¼√(3)-¼

e = ¼(√(3)-1) units.


Area yellow is;


Area regular hexagon with side length 1 unit - Area triangle with height 1 unit and base sin120 units - 2(area rectangle with length ¼√(3) units and width ¼(√(3)-1) units) - Area triangle with length ½√(3) units and width ¼(√(3)-1) units + Area square with side ¼√(3) units + Area rectangle with length ½√(3) units and width ¼√(3) units.


= ½(3√(3))-¼√(3)-2(¼√(3)*¼(√(3)-1))-(½√(3)*¼(√(3)-1)+(¼√(3)*¼√(3))+(½√(3)*¼√(3))

= ½(3√(3))-¼√(3)-2((3/16)-(√(3)/16))-((3/8)-(√(3)/8))+(3/16)+(3/8)

= ½(3√(3))-¼√(3)-(3/8)+(√(3)/8)-(3/8)+(√(3)/8)+(9/16)

= ½(3√(3))-¼√(3)+¼√(3)-(¾)+(9/16)

= ½(3√(3))-(¾)+(9/16)

= ½(3√(3))-(3/16)

= (24√(3)-3)/16 square units.

= 2.4105762114 square units.


Or 


Yellow Area is;


½(3√(3))-(0.5³sin120)-2(0.5²*(¼√(3)-¼)sin120)

= 2.5980762114-0.1082531755-0.0792468245

= 2.4105762113 square units.


Therefore, the fraction of the shaded regular hexagon is;


2.4105762113÷2.5980762114

= 0.9278312163

= (24-√(3))/24

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