Let a be the side length of the square and the diameter of the biggest inscribed semi circle.
Let b = diameter of the bigger inscribed semi circle.
Let c = diameter of the big inscribed semi circl...
a = (√(3)-1) units.
b = (1-c) units.
Calculating c.
Observing similar plane shape (right-angled triangle) side length ratios.
(1-c) - (√(3)-1)
(√(3)-1) - 1
Cross Multiply.
1-c = (√(3)-1)²
c = 1-...
Let the square side length be 2 units.
It implies;
R = 1 unit.
a = (2+2x) units.
a is diameter of the bigger circle.
b = ½(a)
b = ½(2+2x)
b = (1+x) units.
b is the radius of the bigger circle.
c...
a = (x+17) cm.
a is the length of the the ascribed rectangle.
b = a-9
b = (x+17)-9
b = (x+8) cm.
b is the width of the ascribed rectangle and also, the diameter of the inscribed semi circle...
a² = 2²+2²-2*2*2cos120
a = √(12)
a = 2√(3) units.
a is the side length of each of the congruent 4 inscribed regular hexagon.
Calculating the side length of the ascribed regular hexagon.
sin30 = c/...
a = 5-4
a = 1 cm.
b² = 12²+1²
b² = 145
b = √(145) cm.
c = 4+5
c = 9 cm.
Therefore, length x is;
x²+9² = √(145)²
x² = 145-81
x² = 64
x = √(64)
x = 8 cm.
Let the square side be 1 unit.
Let r be the radius of the semi circle.
Calculating r.
c² = 2(1)²
c = √(2) units.
c is the diagonal of the square.
tand = 1/0.5
d = atan(2)°
e = 180-...
cosa = ½
a = acos(½)°
a = 60°
Calculating Red Perimeter.
It is;
2(length of arc of a sector with radius 2 units and angle acos(½)°).
= 2(acos(½)π*2*2/360)
= 4.1887902048 units.
Calculating Gree...
a = (1+x) units.
a is the diameter of the semi circle.
b = ½(a)
b = ½(1+x) units.
b is the radius of the semi circle.
c = x units.
c is the radius of the quarter circle.
Notice!
A-B =...
Let a be 1 unit.
(1/sin45) = (c/sin75)
c = 1.3660254038 units.
d = 75+45
d = 120°
e = 60-15
e = 45°
Calculating b.
(b/sin15) = (1.3660254038/sin45)
b = 0.5 units.
Therefore;
a/b is;
1÷0.5
= 1÷...
