Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
21st May, 2024

Let CE be 1 unit.


Observing Sum of Interior Angles of a Triangle.

a = 180-64-10

a = 106°

a is angle CED.


Observing Sine Rule.

(1/sin10) = (b/sin106)

b = 5.5356854811 units.

b is DE.


Observing Sum of Interior Angles of a Triangle.

c = 180-50+38

c = 92°

c is angle BEC.


Observing Sine Rule.

(1/sin38) = (d/sin50)

d = 1.2442624296 units.

d is BE.


Observing Sum of Interior Angles of a Triangle.

e = 180-86-24

e = 70°

e is angle AEB.


Observing Sine Rule.

(1.2442624296/sin24) = (f/sin86)

f = 3.0516834172 units.

f is AE.


Observing Sum of Angles at a Point.

g = 360-c-a-e

g = 360-92-106-70

g = 360-268

g = 92°

g is angle AED.


Observing Cosine Rule.

h² = 3.0516834172²+5.5356854811²-2*3.0516834172*5.5356854811cos92

h = 6.4137127281 units.

h is AD.


It implies, the required angle, x is;

Observing Sine Rule.

(6.4137127281/sin92) = (5.5356854811/sinx)

x = 59.6070338069°

x ≈ 60° to the nearest whole number.

x is angle EAD

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