Radius of the two congruent inscribed white circles a, is;
a = ½*4√(3)
a = 2√(3) cm.
b = 4√(3) cm.
b is the radius of the ascribed circle.
Area yellow is;
2(2(area sector with radius 4√(3) cm and angle 120° - area triangle with height 4√(3) cm and base 4√(3)sin120 cm) - Area circle with radius 2√(3) cm.)
= 2(2((120π*(4√(3))²/360)-(0.5*(4√(3))²sin120))-π(2√(3))²)
= 2(2(16π-12√(3))-12π)
= 2(32π-24√(3)-12π)
= 2(20π-24√(3))
= 8(5π-6√(3)) cm²
= 42.5252673802 cm²
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