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cos60 = a/4
½ = a/4
a = 2 units.
b = a+4
b = 2+4
b = 6 units.
tan60 = c/6
c = 6√(3) units.
d = b+4
d = 6+4
d = 10 units.
It implies, area red is;
½(cd)
= ½*6√(3)*10
= 30√(3) square units.
Let r be the radius of the circle.
It implies, calculating r.
r² = (r-1)²+(r-0.5)²
r² = r²-2r+1+r²-r+(¼)
0 = r²-3r+(5/4)
4r²-12r+5 = 0
Resolving the above quadratic equation via completi...
Sir Mike Ambrose is the author of the question.
Area Orange exactly in square cm decimal is;
Area triangle with height 1.64419338427 cm and base (4.95325421888sin129.5411167921) cm
= ½*1.644193384...
a = ⅕(180(5-2))
a = 108°
b = 180-108
b = 72°
sin72 = c/6
c = 5.7063390978 cm.
cos72 = d/6
d = 1.8541019662 cm.
e = 1.8541019662+6
e = 7.8541019662 cm
f² = 7.8541019662²+6²-2*7.8541019662*6cos10...
Sir Mike Ambrose is the author of the question.
Let the side of the regular Pentagon be 2 units.
Therefore;
Area orange is;
Area triangle with height 1.7013016167 unit and base 1.8345763534sin(18)...
Calculating angle x.
Notice!
The ascribed triangle is equilateral.
Let the base of the ascribed triangle be 1 unit.
Observing Sine Rule.
(1/sin(180-20-10)) = (a/sin10)
a = 0.3472963553 units.
Ob...
Let the diameter of the inscribed circle be 1 unit.
Therefore, the radius of the ascribed semi circle is 1 unit.
Calculating angle a°.
b = 0.5 unit.
c = 1.5 units.
Therefore, angle a° is;
atan(...
Let the length and width of the ascribed rectangle be 3 units and 2 units respectively.
Calculating red area.
It is;
Area quarter circle with radius 2 units - Area sector with radius 1.5 units and...
a² = 9
a = √(9)
a = 3 cm.
a is the side of square ABCD.
b² = 3²+3²
b = √(18)
b = 3√(2) cm.
b is AC = BD.
c = ½(b)
c = ½(3√(2))
c = 1.5√(2) cm.
c = AQ = BQ.
Let DE = d.
e = (3+...
