Mathematics Question and Solution

By Ogheneovo Daniel Ephivbotor
12th March, 2024

a = ⅕(180(5-2))

a = 108°


b = 180-108

b = 72°


sin72 = c/6

c = 5.7063390978 cm.


cos72 = d/6

d = 1.8541019662 cm.


e = 1.8541019662+6

e = 7.8541019662 cm


f² = 7.8541019662²+6²-2*7.8541019662*6cos108

f = 11.2610625384 cm.


(11.2610625384/sin108) = (6/sing)

g = 30.4463843172°


h = 90-30.4463843172

h = 59.5536156828°


i = 180-18-59.5536156828

i = 102.4463843172°


(5.7063390978/sin102.4463843172) = (j/sin59.5536156828)

j = 5.0378552605 cm.


k² = 6²+6²-2*6*6cos108

k = 9.7082039325 cm.


l = 90-18

l = 72°



Therefore, area shaded (orange area) is;


Area triangle with height 6 cm and base 6sin108 cm + Area triangle with height 9.7082039325 cm and base 5.0378552605sin72 cm.


= 0.5*6*6sin108+0.5*9.7082039325*5.0378552605sin72

= 17.1190172933+23.2573862969

= 40.3764035902 cm²

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